Concept explainers
Explanation of Solution
double conversion = 2.5; //Line 1
The above declaration is a correct one as the variable is correctly declared and initialized with a floating-point number.
char grade = 'B+'; //Line 2
The above declaration is incorrect as a char type variable is just a single character, whereas here we have two characters, B and +. Hence, it should be declared as a string type. The correct declaration would be:
string grade = "B+";
double 28.5 = num //Line 3
The above declaration is incorrect as the declaration does not end with a semi-colon. The correct one would be:
double 28.5 = num;
string message = ''First C++ course'; //Line 4
The above declaration is incorrect as the value must be within double quotes...
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Chapter 2 Solutions
C++ PROGRAMMING: PROGRAM DESIGN INCLUDIN
- #include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…arrow_forward#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…arrow_forward#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05); cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…arrow_forward
- Question1 Write a procedure to find the maximum of three numbers. Procedure specification: • Prototype: int max3(int a, int b, int c). - Parameter(s): a, b, c = Z. - Return value: the largest number among a, b and c. • e.g, max3(10, 20, 30) = 30, max3(1, 1, 1) = 1, max2(10, -20, -30) = 10 Main procedure specification: • • • Read three integers, a, b and c, using input macro. Call max3 procedure to find the largest. Display the result returned from your procedure using output macro.arrow_forwardFunction #2: largest Parameters: num1 - a floating point number being compared against num2 and num3 num2 - a floating point number being compared against num1 and num3 num3 - a floating point number being compared against num1 and num2 Description: Write a function that takes in three numbers as parameters and prints out the largest of the three. If two or all of the numbers are equal, or even all three, then just print the value once. Test Cases: >>>largest(433.1, 2340.32, 12323.7) 12323.7 >>>largest(12.0, 32.1, 32.1) 32.1 >>>largest(23.44, 23.44, 23.44) 23.44arrow_forwardAdmission Write a C++ program that: Define a void function named Admission() with two parameters. The function accepts two arguments: a student’s high school grade point average (for example, GPA is 3.2) and an admission test score (for example, 83). The function then displays a message “Accepted” if the student has any of the following: A GPA of 3.6 or above and an admission test score of at least 60. A GPA of 3.0 or above and an admission test score of at least 70. A GPA of 2.6 or above and an admission test score of at least 80. A GPA of 2.0 or above and an admission test score of at least 90. If the student does not meet any of the qualifications, the function should display a message “Rejected”. //for example, here is the function header: void admission (double gpa, int score) Write a function prototype statement for function Admission before the main function, and add function definition after the main function in the program. In the main function, prompts user to enter a…arrow_forward
- n. The memory for a static variable remains allocated betv Determine the value of each of the following expressions static_cast (toupper ('$')) a. b. static_cast (toupper ('3')) static_cast (toupper('#')) C. d. static cast (toupper ('d')) static cast (tolower('+')) e. f. static cast (tolower ('? ')) g. static cast (tolower ('H')) static_cast (tolower ('%') ) Determine the value of each of the following expressions: h. a. abs (12) b. fabs (23.45) c. fabs (-7.8) d. e. pow (4. g.arrow_forwardEvaluate the following expressions, assume the following declarations: int a=28; int b=4; int c=2; int z=0; z*=a/b-c; What is the value of z after expression is evaluated?arrow_forwardTrue/False 7. Python functions can never modify a parameterarrow_forward
- 38. To pass a scalar variable by reference in C++, you need to include the ____ operator before the formal parameter’s name in the receiving function’s header. a. & c. $ b. * d. @ 42. A simple, or ____ variable, is one that is unrelated to any other variable in memory. a. scalar b. vector c. independent d. dependent 43. You may use an assignment statement or the ____ operator to enter data into an array element. a. comparison b. arithmetic c. extraction d. insertion 44. Each of the ____ (variables) in an array has the same data type. a.elements b.objects c.structures d.subscriptsarrow_forwardAssume the following variable definitions: int a = 5, b = 12; double x = 3.4, z = 9.1; What are the values of the following expressions? A) b / a B) x * a C) static_cast <int> (x * z) D) static_cast<double> ( static_cast<int> ( x) * static_cast <int> (z) )arrow_forwardAssume x is 10, y is 7, and z; x and y are int, z is bool. What is assigned to z? z = x < yarrow_forward
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