Construct Your Own Problem Consider a telescope of the type used by Galileo, having a convex objective and a concave eyepiece as illustrated in part (a) of Figure 2.40. Construct a problem in which you calculate the location and size of the image produced. Among the things to be considered are the focal lengths of the lenses and their relative placements as well as the size and location of the object. Verify that the angular magnification is greater than one. That is, the angle subtended at the eye by the image is greater than the angle subtended by the object.
Construct Your Own Problem Consider a telescope of the type used by Galileo, having a convex objective and a concave eyepiece as illustrated in part (a) of Figure 2.40. Construct a problem in which you calculate the location and size of the image produced. Among the things to be considered are the focal lengths of the lenses and their relative placements as well as the size and location of the object. Verify that the angular magnification is greater than one. That is, the angle subtended at the eye by the image is greater than the angle subtended by the object.
Construct Your Own Problem Consider a telescope of the type used by Galileo, having a convex objective and a concave eyepiece as illustrated in part (a) of Figure 2.40. Construct a problem in which you calculate the location and size of the image produced. Among the things to be considered are the focal lengths of the lenses and their relative placements as well as the size and location of the object. Verify that the angular magnification is greater than one. That is, the angle subtended at the eye by the image is greater than the angle subtended by the object.
if its mmage on the fim is to be in focus.
What is the magnification?
(b) An extension tube is added between the lens and the
camera body so that the lens can be positioned 100 mm
from film. How close can the object be now? What is the
magnification?
5. The focal length of a diverging lens is negative. If ƒ= −20 cm
for a particular diverging lens, where will the image be
formed of an object located 50 cm to the left of the lens on
the optical axis? What is the magnification of the image?
6. The equation connecting s, p, and ffor a simple lens can
be employed for spherical mirrors, too. A concave mirror
with a focal length of 8 cm forms an image of a small object
placed 10 cm in front of the mirror. Where will this image be
located?
17. If the mirror described in the previous problem is used to
form an image of the same object now located 16 cm in
front of the mirror, what would the new image position be?
Assuming that the magnification equations developed for
EXERCISE 1.2 SOLVE:
Repeat the problem in exercise 1.1 using the same lenses except for the following changes:(a) The first lens is a diverging lens having a focal length of magnitude 40.0 cm.(b) Both lenses are diverging lenses having focal lengths of the magnitudes as in the problem in exercise 1.1.
NOTE: The final answer should be:
(a) I1=200cm; (b) s'2=-37.5cm; y'2=−1.80cm; (c) The final image is s'=37.5cm to the left of the second lens, y'=1.80cm, inverted.
EXERCISE 1.1 (for reference)
A 1.20cm tall object is 50.0cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one has a focal length of 60.0cm, is located 300.0cm to the right of the first lens along the same optic axis.(a) Find the location and height of the image (call it I1) formed by the lens with a focal length of 40.0cm.(b) I1 is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by…
An object is placed at an object distance equal to the magnitude of the focal length of a diverging lens. Which of the following is NOT true? Consider the magnitudes only.
O The image magnification is 1.
O The image height is half the object height.
O The image distance is half the object distance.
O The image distance is half the focal length.
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