To demonstrate : The frequency and energy of a photon of visible light.

Question

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Answer 1

Question

Chapter 19.14, Problem 1QP

To determine

To demonstrate:

The frequency and energy of a photon of visible light.

Expert Solution & Answer

Answer to Problem 1QP

The frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Explanation of Solution

Given:

The wavelength of a visible light, $λ=5×10−7 m$ .

Explanation:

Write the equation of frequency of a photon of green light.

$ν=cλ$ (I)

Here, the velocity of light is c.

Determine the energy of a photon of visible light.

$E=hcλ$ (II)

Here, the universal constant is h.

Conclusion:

Substitute $3×108 m/s$ for c and $5×10−7 m$ for $λ$ in Equation (I).

$ν=3×108 m/s5×10−7 m=6×1014 s−1$

Substitute $3×108 m/s$ for c, $5×10−7 m$ for $λ$ , and $6.63×10−34 J⋅s$ for h in Equation (II).

$E=(6.63×10−34 J⋅s)(3×108 m/s)5×10−7 m=3.98×10−19 J$

Thus, the frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

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Answer 2

Question

Chapter 19.14, Problem 1QP

To determine

To demonstrate:

The frequency and energy of a photon of visible light.

Expert Solution & Answer

Answer to Problem 1QP

The frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Explanation of Solution

Given:

The wavelength of a visible light, $λ=5×10−7 m$ .

Explanation:

Write the equation of frequency of a photon of green light.

$ν=cλ$ (I)

Here, the velocity of light is c.

Determine the energy of a photon of visible light.

$E=hcλ$ (II)

Here, the universal constant is h.

Conclusion:

Substitute $3×108 m/s$ for c and $5×10−7 m$ for $λ$ in Equation (I).

$ν=3×108 m/s5×10−7 m=6×1014 s−1$

Substitute $3×108 m/s$ for c, $5×10−7 m$ for $λ$ , and $6.63×10−34 J⋅s$ for h in Equation (II).

$E=(6.63×10−34 J⋅s)(3×108 m/s)5×10−7 m=3.98×10−19 J$

Thus, the frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

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Answer 3

Question

Chapter 19.14, Problem 1QP

To determine

To demonstrate:

The frequency and energy of a photon of visible light.

Expert Solution & Answer

Answer to Problem 1QP

The frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Explanation of Solution

Given:

The wavelength of a visible light, $λ=5×10−7 m$ .

Explanation:

Write the equation of frequency of a photon of green light.

$ν=cλ$ (I)

Here, the velocity of light is c.

Determine the energy of a photon of visible light.

$E=hcλ$ (II)

Here, the universal constant is h.

Conclusion:

Substitute $3×108 m/s$ for c and $5×10−7 m$ for $λ$ in Equation (I).

$ν=3×108 m/s5×10−7 m=6×1014 s−1$

Substitute $3×108 m/s$ for c, $5×10−7 m$ for $λ$ , and $6.63×10−34 J⋅s$ for h in Equation (II).

$E=(6.63×10−34 J⋅s)(3×108 m/s)5×10−7 m=3.98×10−19 J$

Thus, the frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

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Answer 4

Question

Chapter 19.14, Problem 1QP

To determine

To demonstrate:

The frequency and energy of a photon of visible light.

Expert Solution & Answer

Answer to Problem 1QP

The frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Explanation of Solution

Given:

The wavelength of a visible light, $λ=5×10−7 m$ .

Explanation:

Write the equation of frequency of a photon of green light.

$ν=cλ$ (I)

Here, the velocity of light is c.

Determine the energy of a photon of visible light.

$E=hcλ$ (II)

Here, the universal constant is h.

Conclusion:

Substitute $3×108 m/s$ for c and $5×10−7 m$ for $λ$ in Equation (I).

$ν=3×108 m/s5×10−7 m=6×1014 s−1$

Substitute $3×108 m/s$ for c, $5×10−7 m$ for $λ$ , and $6.63×10−34 J⋅s$ for h in Equation (II).

$E=(6.63×10−34 J⋅s)(3×108 m/s)5×10−7 m=3.98×10−19 J$

Thus, the frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

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Answer 5

Chapter 19.14, Problem 1QP

To determine

To demonstrate:

The frequency and energy of a photon of visible light.

Expert Solution & Answer

Answer to Problem 1QP

The frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Explanation of Solution

Given:

The wavelength of a visible light, $λ=5×10−7 m$ .

Explanation:

Write the equation of frequency of a photon of green light.

$ν=cλ$ (I)

Here, the velocity of light is c.

Determine the energy of a photon of visible light.

$E=hcλ$ (II)

Here, the universal constant is h.

Conclusion:

Substitute $3×108 m/s$ for c and $5×10−7 m$ for $λ$ in Equation (I).

$ν=3×108 m/s5×10−7 m=6×1014 s−1$

Substitute $3×108 m/s$ for c, $5×10−7 m$ for $λ$ , and $6.63×10−34 J⋅s$ for h in Equation (II).

$E=(6.63×10−34 J⋅s)(3×108 m/s)5×10−7 m=3.98×10−19 J$

Thus, the frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Answer 6

Chapter 19.14, Problem 1QP

To determine

To demonstrate:

The frequency and energy of a photon of visible light.

Expert Solution & Answer

Answer to Problem 1QP

The frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Explanation of Solution

Given:

The wavelength of a visible light, $λ=5×10−7 m$ .

Explanation:

Write the equation of frequency of a photon of green light.

$ν=cλ$ (I)

Here, the velocity of light is c.

Determine the energy of a photon of visible light.

$E=hcλ$ (II)

Here, the universal constant is h.

Conclusion:

Substitute $3×108 m/s$ for c and $5×10−7 m$ for $λ$ in Equation (I).

$ν=3×108 m/s5×10−7 m=6×1014 s−1$

Substitute $3×108 m/s$ for c, $5×10−7 m$ for $λ$ , and $6.63×10−34 J⋅s$ for h in Equation (II).

$E=(6.63×10−34 J⋅s)(3×108 m/s)5×10−7 m=3.98×10−19 J$

Thus, the frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Answer 7

Chapter 19.14, Problem 1QP

To determine

To demonstrate:

The frequency and energy of a photon of visible light.

Answer 8

Expert Solution & Answer

Answer to Problem 1QP

The frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given:

The wavelength of a visible light, $λ=5×10−7 m$ .

Explanation:

Write the equation of frequency of a photon of green light.

$ν=cλ$ (I)

Here, the velocity of light is c.

Determine the energy of a photon of visible light.

$E=hcλ$ (II)

Here, the universal constant is h.

Conclusion:

Substitute $3×108 m/s$ for c and $5×10−7 m$ for $λ$ in Equation (I).

$ν=3×108 m/s5×10−7 m=6×1014 s−1$

Substitute $3×108 m/s$ for c, $5×10−7 m$ for $λ$ , and $6.63×10−34 J⋅s$ for h in Equation (II).

$E=(6.63×10−34 J⋅s)(3×108 m/s)5×10−7 m=3.98×10−19 J$

Thus, the frequency and energy of a photon of visible light is $6×1014 s−1_$ and $3.98×10−19 J_$ respectively.

Answer 12

Ch. 19.14 - Prob. 1QP Ch. 19.14 - Prob. 2QP Ch. 19.14 - Prob. 3QP Ch. 19.14 - Prob. 4QP Ch. 19.14 - Prob. 5QP Ch. 19.14 - Prob. 6QP Ch. 19.14 - Prob. 7QP Ch. 19.14 - Prob. 8QP Ch. 19.14 - Prob. 9QP Ch. 19.14 - Prob. 10QP

To demonstrate : The frequency and energy of a photon of visible light.

To demonstrate: The frequency and energy of a photon of visible light.

Answer to Problem 1QP

Explanation of Solution

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Chapter 19 Solutions

To demonstrate:

The frequency and energy of a photon of visible light.