STARTING OUT WITH C++ MPL
9th Edition
ISBN: 9780136673989
Author: GADDIS
Publisher: PEARSON
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Chapter 19, Problem 8RQE
Program Plan Intro
Binary Tree:
Binary tree is a non-linear data structure which contains the node such as root node that is pointed to two child nodes. A root node will have left reference node and right reference node.
A complete binary tree is a tree with the property that every node must have exactly two children, and in the last level the nodes should be from left to right.
The analog for binary tree is given below:
struct NodeName
{
int value;
NodeName *left;
NodeName *right;
};
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Imagine a tree in which each node can have up to a hundred children. Write an analog of the TreeNode declaration that can be used to represent the nodes of such a tree. A declaration such as
TreeNode
{int value;TreeNode *child1;TreeNode *child2;TreeNode *child3;... };
A dequeue is a list from which elements can be inserted or deleted at either end
a. Develop an array based implementation for dequeue.
b. Develop a pointer based implementation dequeue.
5. Assume the following definition for a node of a binary tree.
public class Node {
public int data;
public Node left; public Node right;
public Node (int d) { data = d; left = null; right = null; }
}
(a) Write a recursive function height (Node root) which calculates and returns the height
of the binary tree rooted at the given root node.
public static int height (Node root) {
}
(b) Consider the following recursive function:
public static void fun (int a, int b, int c)
int d - 3 - (b + c);
if (a > 1) fun (a-1, ь, d);
System.out.println (a + "
" + b +"
" + c) ;
if(a > 1) fun (a-1, d, c);
What is the output generated by calling: fun (3, 0, 2)?
Answer:
Chapter 19 Solutions
STARTING OUT WITH C++ MPL
Ch. 19.1 - Prob. 19.1CPCh. 19.1 - Prob. 19.2CPCh. 19.1 - Prob. 19.3CPCh. 19.1 - Prob. 19.4CPCh. 19.1 - Prob. 19.5CPCh. 19.1 - Prob. 19.6CPCh. 19.2 - Prob. 19.7CPCh. 19.2 - Prob. 19.8CPCh. 19.2 - Prob. 19.9CPCh. 19.2 - Prob. 19.10CP
Ch. 19.2 - Prob. 19.11CPCh. 19.2 - Prob. 19.12CPCh. 19 - Prob. 1RQECh. 19 - Prob. 2RQECh. 19 - Prob. 3RQECh. 19 - Prob. 4RQECh. 19 - Prob. 5RQECh. 19 - Prob. 6RQECh. 19 - Prob. 7RQECh. 19 - Prob. 8RQECh. 19 - Prob. 9RQECh. 19 - Prob. 10RQECh. 19 - Prob. 11RQECh. 19 - Prob. 12RQECh. 19 - Prob. 13RQECh. 19 - Prob. 14RQECh. 19 - Prob. 15RQECh. 19 - Prob. 16RQECh. 19 - Prob. 17RQECh. 19 - Prob. 18RQECh. 19 - Prob. 19RQECh. 19 - Prob. 20RQECh. 19 - Prob. 1PCCh. 19 - Prob. 2PCCh. 19 - Prob. 3PCCh. 19 - Prob. 4PCCh. 19 - Prob. 5PCCh. 19 - Prob. 6PCCh. 19 - Prob. 7PCCh. 19 - Prob. 8PCCh. 19 - Prob. 9PCCh. 19 - Prob. 10PC
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