Chapter 19, Problem 73A

Interpretation Introduction

(a)

Interpretation:

The oxidation number of $O$ in $O{F}_2$ is to be determined.

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 73A

The oxidation number of $O$ in $O{F}_2$ is+2.

Explanation of Solution

The oxidation number of $O$ is calculated as:

$\begin{array}{c}x+\left(-1\times 2\right)=0\\ x-2=0\\ x=2\end{array}$

Interpretation Introduction

(b)

Interpretation:

The oxidation number of $Ru$ in $Ru{O}_4$ is to be determined.

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 73A

The oxidation number of $Ru$ in $Ru{O}_4$ is+8.

Explanation of Solution

The oxidation number of $Ru$ is calculated as:

$\begin{array}{c}x+\left(-2\times 4\right)=0\\ x-8=0\\ x=+8\end{array}$

Interpretation Introduction

(c)

Interpretation:

The oxidation number of $N$ in $N{O}_2{}^{-}$ is to be determined.

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 73A

The oxidation number of $N$ in $N{O}_2{}^{-}$ is+3.

Explanation of Solution

The oxidation number of N is calculated as:

$\begin{array}{c}x+\left(-2\times 2\right)=-1\\ x-4=-1\\ x-3=0\\ x=3\end{array}$

Interpretation Introduction

(d)

Interpretation:

The oxidation number of $Fe$ in $F{e}_2{O}_3$ is to be determined.

Concept introduction:

Oxidation number: It is defined as charge the atom would have if electrons are not shared but transfer completely.

Answer to Problem 73A

The oxidation number of $Fe$ in $F{e}_2{O}_3$ is+3.

Explanation of Solution

The oxidation number of $Fe$ is calculated as:

$\begin{array}{c}2\times x+\left(-2\times 3\right)=0\\ 2x-6=0\\ x-3=0\\ x=3\end{array}$