World of Chemistry
World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
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Chapter 18, Problem 49A

(a)

Interpretation Introduction

Interpretation: The oxidation state of all of the atoms in MnO2 is needs to be explained.

Concept Introduction: In a compound, the charge assigned to an atom is called its oxidation state. Oxidation is resulted by an increase in oxidation state and reduction is results by decreasing oxidation state.

(a)

Expert Solution
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Answer to Problem 49A

In MnO2 , oxidation state of Mn is +4 and O is 2 .

Explanation of Solution

The electronegativity value of O is higher than Mn. Charge of O as anion is 2 . Hence, oxidation state of O is 2 . The charge of two O in MnO2 is 4(2×2) . The overall charge of MnO2 is zero. Hence, oxidation state of Mn is +4 .

(b)

Interpretation Introduction

Interpretation: The oxidation state of all of the atoms in BaCrO4 is needs to be explained.

Concept Introduction: In a compound, the charge assigned to an atom is called oxidation state. Oxidation is resulted by an increase in oxidation state and reduction is results by decreasing oxidation state.

(b)

Expert Solution
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Answer to Problem 49A

In BaCrO4 , oxidation state of Cr is +6 , O is 2 and Ba is +2.

Explanation of Solution

The electronegativity of O is higher than chromium and barium. Charge of O as anion is 2 . Hence, oxidation state of O is 2 . The total charge of four O in BaCrO4 is 8(4×2) . Barium belongs to group 2 elements so, it forms +2 cations. The sum of the oxidation state of an electrically neutral compound is zero. Hence, the oxidation state of Cr is +6 .

(c)

Interpretation Introduction

Interpretation: The oxidation state of all of the atoms in H2SO3 is needs to be explained.

Concept Introduction: In a compound, the charge assigned to an atom is called oxidation state. Oxidation is resulted by an increase in oxidation state and reduction is results by decreasing oxidation state.

(c)

Expert Solution
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Answer to Problem 49A

In H2SO3 , oxidation state of H is +1 , O is 2 and S is +4.

Explanation of Solution

As electronegativity of O is higher than S and H. Charge of O as anion is 2 . Hence, oxidation state of O is 2 . The charge of three O in H2SO3 is 6(3×2) . The oxidation state of one H is +1. The sum of the oxidation state of electrically neutral compound is zero. Hence, oxidation state of S is +4 .

(d)

Interpretation Introduction

Interpretation: The oxidation state of all of the atoms in Ca3(PO4)2 is needs to be explained.

Concept Introduction: In a compound, the charge assigned to an atom is called oxidation state. Oxidation is resulted by an increase in oxidation state and reduction is results by decreasing oxidation state.

(d)

Expert Solution
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Answer to Problem 49A

In Ca3(PO4)2 , oxidation state of Ca is +2 , O is 2 and P is +5 .

Explanation of Solution

The electronegativity of O is higher than Ca and P. Charge of O as anion is 2 . Hence, oxidation state of O is 2 . Calcium is a group 2 elements so, it forms +2 cations. Its oxidation state is +2. The sum of the oxidation state of electrically neutral compound is zero. Hence, the oxidation state of P is +5 .

Chapter 18 Solutions

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