Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
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Chapter 18, Problem 40P
(a)
To determine
The magnitude of frequency.
(b)
To determine
The distance between the adjacent antinodes for the mode of vibration.
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The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends. (a) Find the frequency of the lowest note a piccolo can play. (b) Opening holes in the side effectively shortens the length of the resonant column. If the highest note a piccolo can sound is 4.00 x 103 Hz, find the distance between adjacent antinodes for this mode of vibration.
The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends.
(a) Find the frequency of the lowest note a piccolo can play.
Hz
(b) Opening holes in the side effectively shortens the length of the resonant column. If the highest note a piccolo can sound is 4,000 Hz, find the distance
between adjacent antinodes for this mode of vibration.
cm
A stretched string fixed at each end has a mass of 32.0 g and a length of 8.40 m. The tension in the string is 50.0 N.
(a) Determine the positions of the nodes and antinodes for the third harmonic. (Enter your answers from smallest to largest
distance from one end of the string.)
nodes:
antinodes:
EEEE
EEE
(b) What is the vibration frequency for this harmonic?
Hz
Chapter 18 Solutions
Physics for Scientists and Engineers with Modern Physics, Technology Update
Ch. 18.1 - Prob. 18.1QQCh. 18.2 - Consider the waves in Figure 17.8 to be waves on a...Ch. 18.3 - When a standing wave is set up on a string fixed...Ch. 18.5 - Prob. 18.4QQCh. 18.5 - Prob. 18.5QQCh. 18 - Prob. 1OQCh. 18 - Prob. 2OQCh. 18 - Prob. 3OQCh. 18 - Prob. 4OQCh. 18 - Prob. 5OQ
Ch. 18 - Prob. 6OQCh. 18 - Prob. 7OQCh. 18 - Prob. 8OQCh. 18 - Prob. 9OQCh. 18 - Prob. 10OQCh. 18 - Prob. 11OQCh. 18 - Prob. 12OQCh. 18 - Prob. 1CQCh. 18 - Prob. 2CQCh. 18 - Prob. 3CQCh. 18 - Prob. 4CQCh. 18 - Prob. 5CQCh. 18 - Prob. 6CQCh. 18 - Prob. 7CQCh. 18 - Prob. 8CQCh. 18 - Prob. 9CQCh. 18 - Prob. 1PCh. 18 - Prob. 2PCh. 18 - Two waves on one string are described by the wave...Ch. 18 - Prob. 5PCh. 18 - Prob. 6PCh. 18 - Two pulses traveling on the same string are...Ch. 18 - Two identical loudspeakers are placed on a wall...Ch. 18 - Prob. 9PCh. 18 - Why is the following situation impossible? Two...Ch. 18 - Two sinusoidal waves on a string are defined by...Ch. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - Prob. 14PCh. 18 - Prob. 15PCh. 18 - Prob. 16PCh. 18 - Prob. 17PCh. 18 - Prob. 18PCh. 18 - Prob. 19PCh. 18 - Prob. 20PCh. 18 - Prob. 21PCh. 18 - Prob. 22PCh. 18 - Prob. 23PCh. 18 - Prob. 24PCh. 18 - Prob. 25PCh. 18 - A string that is 30.0 cm long and has a mass per...Ch. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - Prob. 29PCh. 18 - Prob. 30PCh. 18 - Prob. 31PCh. 18 - Prob. 32PCh. 18 - Prob. 33PCh. 18 - Prob. 34PCh. 18 - Prob. 35PCh. 18 - Prob. 36PCh. 18 - Prob. 37PCh. 18 - Prob. 38PCh. 18 - Prob. 39PCh. 18 - Prob. 40PCh. 18 - The fundamental frequency of an open organ pipe...Ch. 18 - Prob. 42PCh. 18 - An air column in a glass tube is open at one end...Ch. 18 - Prob. 44PCh. 18 - Prob. 45PCh. 18 - Prob. 46PCh. 18 - Prob. 47PCh. 18 - Prob. 48PCh. 18 - Prob. 49PCh. 18 - Prob. 50PCh. 18 - Prob. 51PCh. 18 - Prob. 52PCh. 18 - Prob. 53PCh. 18 - Prob. 54PCh. 18 - Prob. 55PCh. 18 - Prob. 56PCh. 18 - Prob. 57PCh. 18 - Prob. 58PCh. 18 - Prob. 59PCh. 18 - Prob. 60PCh. 18 - Prob. 61PCh. 18 - Prob. 62APCh. 18 - Prob. 63APCh. 18 - Prob. 64APCh. 18 - Prob. 65APCh. 18 - A 2.00-m-long wire having a mass of 0.100 kg is...Ch. 18 - Prob. 67APCh. 18 - Prob. 68APCh. 18 - Prob. 69APCh. 18 - Review. For the arrangement shown in Figure...Ch. 18 - Prob. 71APCh. 18 - Prob. 72APCh. 18 - Prob. 73APCh. 18 - Prob. 74APCh. 18 - Prob. 75APCh. 18 - Prob. 76APCh. 18 - Prob. 77APCh. 18 - Prob. 78APCh. 18 - Prob. 79APCh. 18 - Prob. 80APCh. 18 - Prob. 81APCh. 18 - Prob. 82APCh. 18 - Prob. 83APCh. 18 - Prob. 84APCh. 18 - Prob. 85APCh. 18 - Prob. 86APCh. 18 - Prob. 87CP
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- A sound wave in air has a pressure amplitude equal to 4.00 103 Pa. Calculate the displacement amplitude of the wave at a frequency of 10.0 kHz.arrow_forwardThe overall length of a piccolo is 32.0 cm. The resonating air column is open at both ends, (a) Find the frequency of the lowest note a piccolo can sound. (b) Opening holes in the side of a piccolo effectively shortens the length of the resonant column. Assume the highest note a piccolo can sound is 4 000 Hz. Find the distance between adjacent antinodes for this mode of vibration.arrow_forwardThe bulk modulus of water is 2.2 109 Pa (Table 15.2). The density of water is 103 kg/m3 (Table 15.1). Find the speed of sound in water and compare your answer with the value given in Table 17.1.arrow_forward
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