Three Armstrong’s axiom: The below are three Armstrong’s axiom and they are Reflexivity A is considered to be set of attributes B ⊆ C and B ⊆ A then A → B Augmentation A is considered to be set of attributes B → C, then AB → AC will also hold Transitivity A → B and B → A , then A → C can also be hold. Other axioms: Decomposition When A → BC holds, then A → B and A → C can also hold. Union When A → B and A → C holds, then A → BC can also hold. Computing the closure of the given functional dependency: The below is the computation of the functional dependencies (F + ): Considering the dependency A → BC Utilizing the decomposition axiom to yield A → B and A → C The transitive axiom is used on the provided functional dependency B → D and also with the functional dependency A → B to get A → D Utilize union axiom on A → C and A → D , to get A → CD The transitive axiom is used on the provided functional dependency CD → E and also with the functional dependency A →

Specifications: Part-1Part-1: DescriptionIn this part of the lab you will build a single operation ALU. This ALU will implement a bitwise left rotation. Forthis lab assignment you are not allowed to use Digital's Arithmetic components.IF YOU ARE FOUND USING THEM, YOU WILL RECEIVE A ZERO FOR LAB2!The ALU you will be implementing consists of two 4-bit inputs (named inA and inB) and one 4-bit output (named out). Your ALU must rotate the bits in inA by the amount given by inB (i.e. 0-15).Part-1: User InterfaceYou are provided an interface file lab2_part1.dig; start Part-1 from this file.NOTE: You are not permitted to edit the content inside the dotted lines rectangle.Part-1: ExampleIn the figure above, the input values that we have selected to test are inA = {inA_3, inA_2, inA_1, inA_0} = {0, 1, 0,0} and inB = {inB_3, inB_2, inB_1, inB_0} = {0, 0, 1, 0}. Therefore, we must rotate the bus 0100 bitwise left by00102, or 2 in base 10, to get {0, 0, 0, 1}. Please note that a rotation left is…

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