EBK FOUNDATIONS OF ASTRONOMY
14th Edition
ISBN: 8220106820612
Author: Backman
Publisher: YUZU
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Chapter 18, Problem 1P
If you observed the Solar System from the vantage point of the nearest star, at a distance of 1.3 pc, what would the maximum angular separation be between Earth and the Sun? (Hint: Use the small-angle formula, Eq. 3-1.) (Note: 1 pc = 2.1 × 105 AU.)
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If you observed the solar system from the nearest star (distance 1.3 parsecs), what would the...
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If you observed the solar system from the nearest star (distance 1.3 parsecs), what would the maximum
angular separation be between Earth and the sun? Note that 1 pc is 2.1 105 AU. (Hint: Use the small-angle
formula, Chapter 3.)
The International Space Station is about 90 meters across and about 380 kilometers away. One night it appears to be the same angular size as Jupiter. Jupiter is 143,000 km in size. Use S = r x a to figure out how far away Jupiter is in AU. Note 1 AU = 1.5 x 108 km
Chapter 18 Solutions
EBK FOUNDATIONS OF ASTRONOMY
Ch. 18 - Why was the nebular hypothesis never fully...Ch. 18 - What produced the helium now present in the Suns...Ch. 18 - What produced the iron and heavier elements such...Ch. 18 - Prob. 4RQCh. 18 - What evidence can you give that disks of gas and...Ch. 18 - Why is the solar nebula theory considered a theory...Ch. 18 - According to the solar nebula theory, why is...Ch. 18 - According to the solar nebula theory, why is there...Ch. 18 - Why does the solar nebula theory predict that...Ch. 18 - What evidence can you give that the Solar System...
Ch. 18 - What planet in the Solar System is larger than the...Ch. 18 - Why is almost every solid surface in the Solar...Ch. 18 - What is the difference between condensation and...Ch. 18 - Why dont Terrestrial planets have ring systems...Ch. 18 - How does the solar nebula theory help you...Ch. 18 - Prob. 16RQCh. 18 - If rocks obtained from the Moon indicate an age of...Ch. 18 - Which is older, the Moon or the Sun? How do you...Ch. 18 - How does the solar nebula theory explain the...Ch. 18 - Did hydrogen gas condense from the nebula as the...Ch. 18 - What happens if a planet has differentiated? Would...Ch. 18 - Order the following steps in the formation of a...Ch. 18 - Which step(s) listed in the previous question can...Ch. 18 - Describe two processes that could melt the...Ch. 18 - What is the evidence that Jupiter and Saturn are...Ch. 18 - Describe two processes that cleared the solar...Ch. 18 - What is the difference between a planetesimal and...Ch. 18 - Does Uranus have enough mass to have formed by...Ch. 18 - What properties of the gas and dust disks observed...Ch. 18 - Why would the astronomically short lifetime of gas...Ch. 18 - Prob. 31RQCh. 18 - Describe three methods to find extrasolar planets.Ch. 18 - Why is the existence of hot Jupiters puzzling?...Ch. 18 - The evidence is overwhelming that the Grand Canyon...Ch. 18 - Prob. 35RQCh. 18 - If you observed the Solar System from the vantage...Ch. 18 - Venus can be as bright as apparent magnitude 4.7...Ch. 18 - What is the smallest-diameter crater you can...Ch. 18 - Prob. 4PCh. 18 - Prob. 5PCh. 18 - You analyze a sample of a meteorite that landed on...Ch. 18 - You analyze a sample of a meteorite that landed on...Ch. 18 - Prob. 8PCh. 18 - Examine Table 18-2. What might a planets...Ch. 18 - Examine Table 18-2. What might a planets...Ch. 18 - Suppose that Earth grew to its present size in 10...Ch. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - Prob. 1SOPCh. 18 - Prob. 2SOPCh. 18 - What do you see in this image that indicates this...Ch. 18 - Why do astronomers conclude that the surface of...Ch. 18 - Prob. 3LTLCh. 18 - Prob. 4LTL
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- If you observed the Solar System from the nearest star (distance = 1.3 parsecs), what would the maximum angular separation be between Earth and the Sun? (Note: 1 pc is 2.1105 AU.) (Hint: Use the small-angle formula in Reasoning with Numbers 3-1.)arrow_forward1. These images were taken six months apart, first when Earth was as far to one side of Alpha Centauri as it can get and again when Earth was as far to the other side of Alpha Centauri as it can get. Consequently, the baseline between the two observing positions is how many AU across? Answer: 1.7 arcsec 2. First, convert this to kilometers using your measurement of how many kilometers are in an AU. 3. Now convert the baseline to kilometers using the true value for the number of kilometers in an AU. 4. Calculate the distance to Alpha Centauri using parallax and the true baseline in kilometers. 5. Google and record the true value. 6. Calculate your percent error 7. Discuss significant sources of errorarrow_forwardVenus can be as bright as apparent magnitude −4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 7 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 ✕ 105 AU). [fill in the blank] times fainter What would its apparent magnitude be?arrow_forward
- Thinking about the Scale of the Solar System As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.arrow_forwardVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. ote: 1 pc = 2.1 x 10° AU). times fainter What would its apparent magnitude be? Need Help? Read Itarrow_forwardUse this light curve of a star with a transiting exoplanet to answer the following. If the exoplanet is orbiting a star identical to our own Sun, what is its average orbital distance, in AU? What is the period in years of the transiting exoplanet? Use this light curve of a star with a transiting exoplanet to answer the following questions. Brightness 0 V V V B 5 10 15 20 Time (months) 25 30 35arrow_forward
- Consider the attached light curve for a transiting planet observed by the Kepler mission. If the host star is identical to the sun, what is the radius of this planet? Give your answer in terms of the radius of Jupiter. Brightness of Star Residual Flux 0.99 0.98 0.97 0.006 0.002 0.000 -8-881 -0.06 -0.04 -0.02 0.00 Time (days) → 0.02 0.04 0.06arrow_forward1. These images were taken six months apart, first when Earth was as far to one side of Alpha Centauri as it can get and again when Earth was as far to the other side of Alpha Centauri as it can get. Consequently, the baseline between the two observing positions is how many AU across? Answer: 1.7 arcsec USE 1.7 arcsec NOT 2.946 2. First, convert this to kilometers using your measurement of how many kilometers are in an AU. 3. Now convert the baseline to kilometers using the true value for the number of kilometers in an AU. 4. Calculate the distance to Alpha Centauri using parallax and the true baseline in kilometers. 5. Google and record the true value. 6. Calculate your percent error 7. Discuss significant sources of errorarrow_forward(a) The distance to a star is approximately 7.80 1018 m. If this star were to burn out today, in how many years would we see it disappear? years (b) How long does it take for sunlight to reach Saturn?arrow_forward
- The value we have just calculated is the combined masses of Jupiter and Callisto! Their mass is in units of the Sun's Mass (MS) - we can convert this to units which are more familiar to us like kilograms by multiplying this answer by the scale factor (1.99x1030 kg/1 MS): (MJupiter + MCallisto) = ( MS) (1.99x1030 kg/1 Solar Mass) = _______x_10___ kg (I have already written the x 10 so you are reminded to write the exponenet of 10 in the scientific notation expression of your answer). Since you know from looking at pictures of Jupiter with its Galilean Satellites (look in your book at a picture if you have not already), that Callisto is much smaller than Jupiter - in fact it is less than 0.001 of Jupiter's size or mass, so the number we have just calculated for (MJupiter + MCallisto) is almost the same as MJupiter . How much more massive is Jupiter than the Earth? (The mass of Earth is about 5.98 x 1024 kg)arrow_forwardVenus can be as bright as apparent magnitude −4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 7 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 ✕ 105 AU). What would its apparent magnitude be?arrow_forwardVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 x 105 AU). times fainter What would its apparent magnitude be?arrow_forward
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