Concept explainers
Is each of the following mutations a transition, transversion, addition, or deletion? The original DNA strand is
5′–GGACTAGATAC–3′
(Note: Only the coding DNA strand is shown.)
A. 5′–GAACTAGATAC–3′
B. 5′–GGACTAGAGAC–3′
C. 5′–GGACTAGTAC–3′
D. 5′–GGAGTAGATAC–3′
To review:
The kind of mutations that are present in DNA (deoxyribonucleic acid) sequences, while comparing the given sequence
A.
B.
C.
D.
Introduction:
Point mutations are a common type of mutation in which, a lone nucleotide in a DNA sequence undergoes change. There could be addition of a nucleotide, deletion of a nucleotide or conversion of one nucleotide into another (transition and transversion mutations).
Explanation of Solution
Mutation is defined as the occurrence of change in the genetic material of an organism, which generally is of permanent nature. Further, more the different types of mutations, which might have occurred in the mentioned parts have been described below:
A. When the given sequence is compared with the new sequence,
B. On comparing the given sequence to the new sequence,
C. When compared with the new sequence,
D. On comparing with the new sequence,
Therefore, it can be concluded that mutations in the given sequences when compared to the reference sequence are: transition, transversion, deletion and transversion, respectively.
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Chapter 18 Solutions
Genetics: Analysis and Principles
- Look at the double-stranded segment of DNA shown below. Imagine that the two strands have already been denatured, and the temperature has been decreased to an appropriate annealing temperature. Show where the two primers would anneal to the strands, then indicate the direction of extension on each new strand with an arrow. 5’--T C A G G A C G T A A G C T T G C A T A T C T C G A T G C T A A A T C A T—3’ 3’--A G T C C T G C A T T C G A A C G T A T A G A G C T A C G A T T T A G T A—5’ Primer #1: 3’ A C G A T T T 5’ Primer #2: 5’ G G A C G T A 3’arrow_forwardGive the corresponding strand of the DNA having the sequence of:a. 5’ ATGGCTAGGATCGGTAACTGCGATCGATCAGCATGACTAG-3’b. 3’ TACCAGGATAATTCGAGGTACTACGACTAGGAT-5’c. 5’ AACATGATCTGGTCCATTAGCTTGTTCAATAATTAGC-3’arrow_forwardThe template strand of a segment of double-helical DNA contains the sequence – 5’-CTT-AAC-ACC-CCT-GAC-TTC-GCG-CCG-CAT-3’ a. What is the base sequence of the complementary strand of DNA? Indicate the 5’ and the 3’ ends. b. What is the base sequence of the mRNA that can be transcribed from this template DNA strand? Indicate the 5’ and the 3’ ends. c. What amino acid sequence can be coded by the mRNA in (b) starting from the 5’ end (or the N terminal amino acid)?arrow_forward
- Consider the following sequence of DNA: 3'-TTA CGG-5'What dipeptide is formed from this DNA after transcription and translation? b. If a mutation converts CGG to CGT in DNA, what dipeptide is formed? c. If a mutation converts CGG to CCG in DNA, what dipeptide is formed? d. If a mutation converts CGG to AGG in DNA, what dipeptide is formed?arrow_forwardA certain section of the coding (sense) strand of some DNA looks like this: 5'- ATGGGCCACTCATCTTAG-3' It's known that a very small gene is contained in this section. Classify each of the possible mutations of this DNA shown in the table below. I Don't Know mutant DNA 5'- ATG GGCCACAGTTCTTAG-3' 5'- ATG GG CTCATCTTAG - 3' 5'- ATG GGCCACGCATCTTAG-3' Submit type of mutation (check all that apply) ооооо O point O silent O noisy ооооо insertion deletion insertion O deletion Opoint Osilent noisy insertion O deletion ооооо Opoint silent O noisy X S Ⓒ2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forwardBelow is the 5’–3’ strand of a double-stranded DNA molecule with the following nucleotide sequences: 5’ C C T A T G C A G T G G C C A T A T T C C A A A G C A T A G C 3’ 1. If the above DNA strand is the coding (sense) strand and the DNA molecule is transcribed, what is the correct nucleotide sequence and direction of the RNA formed after transcription? 2. If the RNA synthesized above (item #1) is a functional mRNA and all the nucleotides belong to an exon, a. how many codons are present in this mRNA? b. how many codons actually code for proteins in this mRNA? c. what stop codon is present in this mRNA?arrow_forward
- The following is a section of DNA removed from a cell nucleus:5' ATGAAATAATCAGTTAACAGCAGVFCCGATTTTTATACT 3'strand 3' TACITTATTAGTCAAVFGTCGTCAAGGCTAAAAATATGA 5'strand a. What does the Central Dogma state? b. Label the strands above as the "sense" or "antisense" strand. c. Using the chart below, transcribe ONLY the gene into mRNA and then translate the gene into its amino acid sequence, d. What would happen to the gene if the adenosine mutates to a thymine where the arrow indicates? 3' TACTTTATTAGTCAATTGTCGTCAAGGCTAAAAATATGA 5' What type of mutation is this?arrow_forward2 a) The following nucleotide sequence is found on the template strand of DNA: 3-TAC TGG CCG TTA GTT GAT ATA ACT-5" Determine the amino acids of the encoded peptide, then provide the altered amino acid sequence of protein that would result from each of the following mutations and provide their classification (eg. Missense, nonsense, etc). 益券 A transition at nucleotide 11 A transition at nucleotide 13 A one-nucleotide deletion at nucleotide 7 AT to A transversion at nucleotide 15 An addition of TGG after nucleotide 6 A transition at nucleotide 9arrow_forwardb) For a DNA strand with the given genetic code of bases , undergoing transcription, what will be the complimentary RNA strand? Provide the direction as well as 5" and 3" indicators for the new genetic genome. 5" G-A-A-C-T-G-G-A^T-T-C-T-A-C-C3'.arrow_forward
- The following fragment of DNA is from the template strand. First determine the amino acids of the protein encoded by this sequence by using the table at the end of this document. Then give the altered amino acid sequence of the proteins that will be found in each of the following mutations: 3’ – TAC AAG GCT CTA TTT GCC ACA ATC – 5’ The nucleotides are numbered 1-24 from left to right. Mutant 1: A transition at nucleotide 9 Mutant 2: A transition at nucleotide 11 Mutant 3: A T to A transversion at nucleotide 15 Mutant 4: A one-nucleotide deletion at nucleotide 7 Mutant 5: A transition at nucleotide 13 Mutant 6: An addition of GGA after nucleotide 6arrow_forwardDesign primers that will amplify the following region of DNA (assume this is one strand from a double stranded region of DNA). The primers should be 15 bases in length. Indicate the 5' and 3' ends of the primers. 5' GGATCGATCAAGAACAATGACAGGATCGAGGAATTCAGCCTACGCAGCCCGTAGCTGGAGGGA 3'arrow_forwarda) Complete the table below. Assume that reading is from left to right and that the columns represent transcriptional and translational alignments. Label the 5’ and 3’ ends of DNA and RNA and carboxy and amino acid ends of protein. (You may fill in this chart by hand writing- no typing necessary here.) 2. b) Is the top or bottom DNA strand the template strand?arrow_forward
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