(a)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension a to dimension B is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension a is given by
The measure of dimension B is given by
The ratio of dimension a to dimension B is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension a to Dimension B is
(b)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of Dimension a to Dimension C is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension a is given by
The measure of dimension C is given by
The ratio of dimension a to dimension C is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension a to Dimension C is 
(c)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension C to dimension D is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension C is given by
The measure of dimension D is given by
The ratio of dimension C to dimension D is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension C to Dimension D is 
(d)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension C to dimension E is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension C is given by
The measure of dimension E is given by
The ratio of dimension C to dimension E is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension C to Dimension E is 
(e)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension D to dimension F is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension D is given by
The measure of dimension F is given by
The ratio of dimension D to dimension F is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension D to Dimension F is 
(f)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension F to dimension B is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension F is given by
The measure of dimension B is given by
The ratio of dimension F to dimension B is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension F to Dimension B is 
(g)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension F to dimension C is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension F is given by
The measure of dimension C is given by
The ratio of dimension F to dimension C is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension F to Dimension C is 
(h)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension E to dimension a is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of nearer hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension E is given by
The measure of dimension a is given by
The ratio of dimension E to dimension a is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension E to Dimension a is 
(i)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension D to dimension B is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance the near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension D is given by
The measure of dimension B is given by
The ratio of dimension D to dimension B is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension D to Dimension B is 
(j)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension C to dimension F is 
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of nearer hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension C is given by
The measure of dimension F is given by
The ratio of dimension C to dimension F is given by
Thus, the ratio is 
Conclusion:
The ratio of Dimension C to Dimension F is 
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Chapter 18 Solutions
Mathematics for Machine Technology
- Determine diameters A, B, C, D, and E of the shaft in Figure 124. All dimensions are in millimeters. A=_B=_C=_D=_E=_arrow_forwardFind the decimal value of the distance C in Figure 10-3. Note the total unit value of the line.arrow_forwardFind the decimal value of the distance B in Figure 10-2. Note the total unit value of the line.arrow_forward
- Find the decimal value of the distance A in Figure 10-1. Note the total unit value of the line.arrow_forwardThe length, L, of the point on any standard 118° included angle drill, as shown in Figure 12-5, can be calculated using the formula L=0.3 O where represents the diameter of the drill. Determine the lengths of the following drill points with the given diameters. Round to 3 decimal places for inches and 1 decimal place for millimeters. a. 12 b. 14 c. 38 d. 10 mm e. 25 mm f. 45 mmarrow_forwardRead the setting on the following 0.001-inch micrometer scale. The vernier, thimble, and barrel scales are shown in flattened view.arrow_forward
Mathematics For Machine TechnologyAdvanced MathISBN:9781337798310Author:Peterson, John.Publisher:Cengage Learning,
Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL