Heat flux The heat flow vector field for conducting objects is F = – k ▿ T , where T ( x , y , z ) is the temperature in the object and k > 0 is a constant that depends on the material. Compute the outward flux of F across the following surfaces S for the given temperature distributions. Assume k = 1. 62. T ( x , y , z ) = 100 e − x 2 − y 2 − z 2 ; S is the sphere x 2 + y 2 + z 2 = a 2
Heat flux The heat flow vector field for conducting objects is F = – k ▿ T , where T ( x , y , z ) is the temperature in the object and k > 0 is a constant that depends on the material. Compute the outward flux of F across the following surfaces S for the given temperature distributions. Assume k = 1. 62. T ( x , y , z ) = 100 e − x 2 − y 2 − z 2 ; S is the sphere x 2 + y 2 + z 2 = a 2
Solution Summary: The author explains how to compute the outward flux of F across the surface S.
Heat fluxThe heat flow vector field for conducting objects isF = –k▿T, where T(x, y, z) is the temperature in the object and k > 0 is a constant that depends on the material. Compute the outward flux ofFacross the following surfaces S for the given temperature distributions. Assume k = 1.
62.
T
(
x
,
y
,
z
)
=
100
e
−
x
2
−
y
2
−
z
2
; S is the sphere x2 + y2 + z2 = a2
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Fourier's Law of heat transfer (or heat conduction) states that the heat flow vector F at a point is proportional to the negative gradient of the temperature;
that is, F = -KVT, which means that heat energy flows from hot regions to cold regions. The constant k is called the conductivity, which has metric units
SS
S
of J/m-s-K or W/m-K. A temperature function T for a region D is given below. Find the net outward heat flux
boundary S of D. It may be easier to use the Divergence Theorem and evaluate a triple integral. Assume that k = 1.
T(x,y,z) = 100 - 5x+ 5y +z; D = {(x,y,z): 0≤x≤5, 0≤y≤4, 0≤z≤ 1}
The net outward heat flux across the boundary is
(Type an exact answer, using as needed.)
-KSS
S
F.ndS = -k
VT n dS across the
Find the equation of the tangent plane to the surface z=e-4x/17ln(1y) at the point (-3, 4, 2.808).
z=_____________________.
Chapter 17 Solutions
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