A fixed mass of a gas is held in an adjustable sealed container at a pressure of 100.0 kPa. If the container size is decreased to 0.8 m3; what will be initial volume of the gas? Assume the final pressure of the gas inside the container is 400kPa and the temperature remains constant.

A bicycle tire has a pressure of 6.75 × 105 Pa at a temperature of 19°C and contains 2.00 L of gas. a) What will its pressure be, in pascals, if you let out an amount of air that has a volume of 110 cm3 at atmospheric pressure and at the temperature of the tire? Assume tire temperature and volume remain constant.

A bicycle tire has a pressure of 6.95 × 105 Pa at a temperature of 16°C and contains 2.00 L of gas. a)What will its pressure be, in pascals, if you let out an amount of air that has a volume of 105 cm3 at atmospheric pressure and at the temperature of the tire? Assume tire temperature and volume remain constant.

A fixed amount of gas occupies a volume of 1.75L and exerts a pressure of 95kpa on the walls of its container . What would be the pressure exerted by the gas if it's completely transferred into a new container having a volume of 0.5L(assuming the temperature and quantity of gas remains constant)

With the temperature held constant, the pressure of a gas in a cylinder with a movable piston is increased from 10 kPa to 80 kPa. The initial volume of the gas in the cylinder is 0.56 m^3. What is the final volume of the gas after the pressure is increased?

A basketball is pressurized to a gauge pressure of PG = 55 kPa when at the surface of a swimming pool. (Patm = 101 kPa). The ball is then submerged in the pool of water which has a density ρ = 1000 kg/m3. Assume the ball does not change in mass, temperature, or volume as it is submerged. Calculate the absolute pressure inside the basketball in kPa when it is at the surface.  Write an equation for the pressure difference ΔP between the inside and outside of the ball when it is submerged a distance y below the surface of the water.  Solve the pressure equation for the depth (in meters) at which the pressure difference between the inside and outside of the ball will become zero. At this depth the pressure inside the basketball is the same as the pressure outside the ball.

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV14 = C where C is a constant. Suppose that at a certain instant the volume is 560 cubic centimeters and the pressure is 81 kPa and is decreasing at a rate of 9 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant? cm min (Pa stands for Pascal -- it is equivalent to one Newton/(meter squared); kPa is a kiloPascal or 1000 Pascals. )

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV14 = Cwhere C is a constant. Suppose that at a certain instant the volume is 670 cubic centimeters and the pressure is 99 kPa and is decreasing at a rate of 7 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant? cm3 min (Pa stands for Pascal -- it is equivalent to one Newton/(meter squared); kPa is a kiloPascal or 1000 Pascals. )

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV14 = C where C is a constant. Suppose that at a certain instant the volume is 540 cubic centimeters and the pressure is 91 kPa and is decreasing at a rate of 12 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant? cm3 min (Pa stands for Pascal -- it is equivalent to one Newton/(meter squared); kPa is a kiloPascal or 1000 Pascals.