General Physics, 2nd Edition
General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 17, Problem 77E

(a)

To determine

The charge on the capacitor plates.

(a)

Expert Solution
Check Mark

Answer to Problem 77E

The charge on the capacitor plates is 0.1C_.

Explanation of Solution

Given that the capacitance is 100μF, and the potential difference is 1000V.

Write the expression for charge on the capacitor plates.

  Q=CV        (I)

Here, Q is the charge, C is the capacitance, and V is the potential difference.

Conclusion:

Substitute 100μF for C, and 1000V for V in equation (I) to find Q.

  Q=(100μF)(1000V)=(100μF×1F1×106μF)(1000V)=0.1C

Therefore, the charge on the capacitor plates is 0.1C_.

(b)

To determine

The resistance of the circuit.

(b)

Expert Solution
Check Mark

Answer to Problem 77E

The resistance of the circuit is 10ohm_.

Explanation of Solution

Given that the time is 0.001s, the remaining charge is 0.37 times the initial charge, and the capacitance is 100μF.

Write the expression for the charge in the capacitor in an RC circuit under charging.

  q(t)=qfet/RC        (II)

Here, q(t) is the charge at time t, R is the resistance, and C is the capacitance, qf is the charge when capacitor is fully charged (here the initial charge).

Since the charge remaining is 0.37 of the initial charge, in equation (II), q(t) can be replaced by 0.37qf.

  0.37qf=qfet/RC0.37=et/RC        (III)

Solve equation (III) for R

  ln0.37=tRCR=tCln0.37        (IV)

Conclusion:

Substitute 0.001s for t, and 100μF for C in equation (IV) to find R.

  R=(0.001s)(100μF)ln0.63=(0.001s)(100μF×1F1×106μF)ln0.37=10ohm

Therefore, the resistance of the circuit is 10ohm_.

(c)

To determine

The current after 0.001s.

(c)

Expert Solution
Check Mark

Answer to Problem 77E

The current after 0.001s is 37A_.

Explanation of Solution

Write the expression for the current in the series RC circuit.

  i(t)=εRet/RC        (V)

Here, i(t) is the current at time t, ε is the potential difference.

Conclusion:

Substitute 10ohm for R, 100μF for C, 1000V for ε, and 0.001s for t in equation (V) to find i.

  i(t)=1000V10ohme0.001s/(10ohm)(100μF)=1000V10ohme0.001s/(10ohm)(100μF×1F1×106μF)=37A

Therefore, the current after 0.001s is 37A_.

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Chapter 17 Solutions

General Physics, 2nd Edition

Ch. 17 - Prob. 11RQCh. 17 - Prob. 12RQCh. 17 - Prob. 1ECh. 17 - Prob. 2ECh. 17 - Prob. 3ECh. 17 - Prob. 4ECh. 17 - Prob. 5ECh. 17 - Prob. 6ECh. 17 - Prob. 7ECh. 17 - Prob. 8ECh. 17 - Prob. 9ECh. 17 - Prob. 10ECh. 17 - Prob. 11ECh. 17 - Prob. 12ECh. 17 - Prob. 13ECh. 17 - Prob. 14ECh. 17 - Prob. 15ECh. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 18ECh. 17 - Prob. 19ECh. 17 - Prob. 20ECh. 17 - Prob. 21ECh. 17 - Prob. 22ECh. 17 - Prob. 23ECh. 17 - Prob. 24ECh. 17 - Prob. 25ECh. 17 - Prob. 26ECh. 17 - Prob. 27ECh. 17 - Prob. 28ECh. 17 - Prob. 29ECh. 17 - Prob. 30ECh. 17 - Prob. 31ECh. 17 - Prob. 32ECh. 17 - Prob. 33ECh. 17 - Prob. 34ECh. 17 - Prob. 35ECh. 17 - Prob. 36ECh. 17 - Prob. 37ECh. 17 - Prob. 38ECh. 17 - Prob. 39ECh. 17 - Prob. 40ECh. 17 - Prob. 41ECh. 17 - Prob. 42ECh. 17 - Prob. 43ECh. 17 - Prob. 44ECh. 17 - Prob. 45ECh. 17 - Prob. 46ECh. 17 - Prob. 47ECh. 17 - Prob. 48ECh. 17 - Prob. 49ECh. 17 - Prob. 50ECh. 17 - Prob. 51ECh. 17 - Prob. 52ECh. 17 - Prob. 53ECh. 17 - Prob. 54ECh. 17 - Prob. 55ECh. 17 - Prob. 56ECh. 17 - Prob. 57ECh. 17 - Prob. 58ECh. 17 - Prob. 59ECh. 17 - Prob. 60ECh. 17 - Prob. 61ECh. 17 - Prob. 62ECh. 17 - Prob. 63ECh. 17 - Prob. 64ECh. 17 - Prob. 65ECh. 17 - Prob. 66ECh. 17 - Prob. 67ECh. 17 - Prob. 68ECh. 17 - Prob. 69ECh. 17 - Prob. 70ECh. 17 - Prob. 71ECh. 17 - Prob. 72ECh. 17 - Prob. 73ECh. 17 - Prob. 74ECh. 17 - Prob. 75ECh. 17 - Prob. 76ECh. 17 - Prob. 77ECh. 17 - Prob. 78ECh. 17 - Prob. 79ECh. 17 - Prob. 80ECh. 17 - Prob. 81ECh. 17 - Prob. 82ECh. 17 - Prob. 83ECh. 17 - Prob. 84ECh. 17 - Prob. 85ECh. 17 - Prob. 86ECh. 17 - Prob. 87ECh. 17 - Prob. 88ECh. 17 - Prob. 89ECh. 17 - Prob. 90ECh. 17 - Prob. 91ECh. 17 - Prob. 92E
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