Physics for Scientists and Engineers: Foundations and Connections
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN: 9781133939146
Author: Katz, Debora M.
Publisher: Cengage Learning
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Chapter 17, Problem 74PQ

(a)

To determine

The intensity of the sound.

(a)

Expert Solution
Check Mark

Answer to Problem 74PQ

The intensity of the sound is 13.8W/m2_.

Explanation of Solution

Write the equation of intensity of sound.

  I=PA                                                                                                                 (I)

Here, I is the intensity, P is the power and A is the area.

Write the expression for the power.

  P=Et                                                                                                              (II)

Here, E is the energy and t is the time.

Rewrite the expression for the intensity by using equation (II).

  I=EAt                                                                                                             (III)

Conclusion:

Substitute 275J for E, 5.00m2 for A and 4.00s for t in equation (III) to find I.

  I=(275J)(5.00m2)(4.00s)=(275J)(20.0m2/s)=13.8W/m2

Thus, the intensity of the sound is 13.8W/m2_.

(b)

To determine

The amount of sound level.

(b)

Expert Solution
Check Mark

Answer to Problem 74PQ

The amount of sound level is 131dB_.

Explanation of Solution

Write the equation of sound level.

  β=10log(IIo)                                                                                               (IV)

Here, β is the sound level, I is the intensity and Io is the initial intensity.

Conclusion:

Substitute 13.8W/m2 for I and 1012W/m2 for Io in equation (IV) to find β.

  β=10log((13.8W/m2)(1012W/m2))=10log(13.8×1012)=131dB

Thus, the amount of sound level is 131dB_.

(c)

To determine

The intensity of the sound.

(c)

Expert Solution
Check Mark

Answer to Problem 74PQ

The intensity of the sound is 3.44W/m2_.

Explanation of Solution

Write the equation of intensity of sound.

  I=PA                                                                                                                 (I)

Here, I is the intensity, P is the power and A is the area.

Write the expression for the power.

  P=Et                                                                                                              (II)

Here, E is the energy and t is the time.

Rewrite the expression for the intensity by using equation (II).

  I=EAt                                                                                                            (III)

Conclusion:

Substitute 275J for E, 20.00m2 for A and 4.00s for t in equation (III) to find I.

  I=(275J)(20.00m2)(4.00s)=(275J)(80.00m2/s)=3.44W/m2

Thus, the intensity of the sound is 3.44W/m2_.

(d)

To determine

The amount of sound level.

(d)

Expert Solution
Check Mark

Answer to Problem 74PQ

The amount of sound level is 125dB_.

Explanation of Solution

Write the equation of sound level.

  β=10log(IIo)                                                                                               (IV)

Here, β is the sound level, I is the intensity and Io is the initial intensity.

Conclusion:

Substitute 3.44W/m2 for I and 1012W/m2 for Io in equation (IV) to find β.

  β=10log((3.44W/m2)(1012W/m2))=10log(3.44×1012)=125dB

Thus, the amount of sound level is 125dB_.

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Chapter 17 Solutions

Physics for Scientists and Engineers: Foundations and Connections

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