Chapter 1.7, Problem 4IP

To determine

The domain and range of the relation.

Answer to Problem 4IP

The final table is

Number of Tickets	Total Cost($)
X	Y
4	32
7	56
9	72
12	96

Explanation of Solution

Given:

Each ticket to the school musical costs $8.

So the equation is $y=x\cdot 8$

  

Concept Used:

• To get rid of a number in addition from one side, subtract the same number from both sides of equal sign.
• To get rid of a number in subtraction from one side, add the same number both sides of equal sign.
• To get rid of a number in multiplication from one side, divide the same number from both sides of equal sign.
• To get rid of a number in division from one side, multiply the same number both sides of equal sign.

Rules of Addition/ Subtraction:

• Two numbers with similar sign always get added and the resulting number will carry the similar sign.
• Two numbers with opposite signs always get subtracted and the resulting number will carry the sign of larger number.

Rules of Multiplication/ Division:

• The product/quotient of two similar sign numbers is always positive.
• The product/quotient of two numbers with opposite signs is always negative.

Calculation:

In order to solve the given table. Here to solve the table and simplify as shown below,

  $\begin{array}{c}y=8\cdot x\\ x=4\\ \text{Then}y=8\cdot 4\\ =32\\ x=7\\ \text{Then}y=8\cdot 7\\ =56\\ x=9\\ \text{Then}y=8\cdot 9\\ =72\\ x=12\\ \text{Then}y=8\cdot 12\\ =96\end{array}$

Thus, the final table is below.

Number of Tuckets	Total Cost($)
X	Y
4	32
7	56
9	72
12	96