Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 17, Problem 3PEB
To determine
The volume of helium balloon at an altitude where pressure is 560 hPa
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A helium balloon had a volume of 1.50 m when it was filled at an altitude where the atmospheric pressure was 775 hPa. What was the atmospheric pressure of the balloon, in hPa, at an altitude where its volume was 1.2 m3?
The basic barometer can be used to measure the height of a building. If the barometric readings at the top and at the bottom of a building are 675 and 695 mmHg, respectively, determine the height of the building. Take the densities of air and mercury to be 1.18 kg/m3 and 13,600 kg/m3, respectively.
Air pressure decreases at a rate of 1.25 Pa (pascals) per kilometer in the eastward direction. In addition, the air pressure is decreasing at a constant rate with respect to time everywhere. A ship sailing eastward at 10 km/hour past an island takes barometer readings and records a pressure drop of 40 Pa in 2 hours. Estimate the time rate of change of air pressure on the island. (pascal is a unit of air pressure 1Pa=1N/m2=1kg/m∗s2)
Chapter 17 Solutions
Integrated Science
Ch. 17.3 - Prob. 1SCCh. 17.3 - Prob. 2SCCh. 17.3 - Prob. 3SCCh. 17.3 - Prob. 4SCCh. 17.3 - Brief periods of showers are usually associated...Ch. 17.4 - Prob. 6SCCh. 17.4 - Prob. 7SCCh. 17.4 - Prob. 8SCCh. 17.4 - Prob. 9SCCh. 17.5 - Prob. 10SC
Ch. 17.5 - Prob. 11SCCh. 17.5 - Prob. 12SCCh. 17 - Explain the greenhouse effect. Is a greenhouse a...Ch. 17 - Describe how the ozone layer protects living...Ch. 17 - What is wind? What is the energy source for wind?Ch. 17 - Prob. 4CQCh. 17 - Prob. 5CQCh. 17 - Prob. 6CQCh. 17 - Prob. 7CQCh. 17 - Prob. 8CQCh. 17 - Prob. 9CQCh. 17 - Prob. 10CQCh. 17 - Prob. 11CQCh. 17 - Prob. 12CQCh. 17 - Prob. 13CQCh. 17 - Prob. 14CQCh. 17 - Prob. 15CQCh. 17 - Prob. 16CQCh. 17 - Prob. 17CQCh. 17 - Prob. 18CQCh. 17 - Prob. 19CQCh. 17 - Prob. 20CQCh. 17 - Prob. 21CQCh. 17 - Prob. 22CQCh. 17 - Prob. 23CQCh. 17 - Prob. 24CQCh. 17 - Given the current air temperature and relative...Ch. 17 - Explain why dew is not considered to be a form of...Ch. 17 - What are the significant similarities and...Ch. 17 - Prob. 28CQCh. 17 - Prob. 29CQCh. 17 - Prob. 1PEACh. 17 - Prob. 2PEACh. 17 - Prob. 3PEACh. 17 - Prob. 4PEACh. 17 - Prob. 5PEACh. 17 - On the scale of a basketball, how thick, in cm, is...Ch. 17 - Prob. 2PEBCh. 17 - Prob. 3PEBCh. 17 - A helium balloon had a volume of 1.50 m3 when it...Ch. 17 - Prob. 5PEB
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- A submarine dives down to a depth 80 metres beneath the surface of the ocean. Calculate the pressure in atmospheres at that depth, assuming the density of water is 1029 kg/m3, and the air pressure at the surface is 105.2 kPa. Give your answer with two digits of precision. Note: 1 standard atmosphere is 101325 Pa. Your Answer: Answerarrow_forwardIf atmospheric pressure at sea level is 1 × 10 Pa, what is the total mass of the air above a 5-m- area? Hint: find the weight of the air and then use w-mg and assume gravity is constant. O 9x 10? kg O 4 x 10-2 kg O2 x 10 4 kg 3 x 10 kg 5 x 104 kgarrow_forwardAir pressure decreases at a rate of 2.25 Pa(pascals) per kilometer in the eastward direction. In addition, the air pressure is decreasing at a constant rate with respect to time everywhere. A ship sailing eastward at 6 km/hour past an island takes barometer readings and records a pressure drop of 70 Pain 2 hours. Estimate the time rate of change of air pressure on the island. (Pascal is a unit of air pressure 1Pa=1N/m2=1kg/m∗s2^2) Time rate of change of air pressure =---- Pa/hrarrow_forward
- An airplane passenger has 99.7 cm³ of air in his stomach just before the plane takes off from a sea-level airport. What volume will the air have in cm at cruising altitude if cabin pressure drops to 7.89 x 10 N/m²? Type your answer...arrow_forwardA large truck tire is inflated to a gauge pressure of 70 psi. The total area of one sidewall of the tire is 1,180 in2. What is the net outward force (in lb) on the sidewall because of the air pressure? (Enter the magnitude.)arrow_forwardThe density of the atmosphere varies drastically with height, but you can use an average density from sea floor to the space in order to calculate its height. If we approximate this average density to be = 1 Kg/m³, what would be height of the atmosphere? HINT: Since the atmosphere is a fluid (in gas form), you can use the hydrostatic pressure formula (P pgh), just solve for h and use P = 1 atm. BTW, this is how the edge of space is defined, if you make it pass the height of the atmosphere you have reached space :)arrow_forward
- The rate of change of atmospheric pressure P with respect to altitude h is proportional to P, provided that temperature is constant. At 15°C the pressure is 101.3 kPa at sea level and 87.14 kPa at h = 1000 m. Answer the following questions. a) What is the atmospheric pressure at an altitude of 4000 m? Round to three decimal places. b) What is the atmospheric pressure at the top of Mount Greylock in Massachusetts, at an altitude of 1063 m? Round to three decimal places. CHECK ANSWER kPa NEXT kPaarrow_forwardDetermine the atmospheric pressure at a location where the barometric reading is 750 mmHg. Take the density of mercury to be 13,600 kg/m3.arrow_forwardFind the pressure on the roof of the Empire State Building (381 m). Assune: Pressure decreases about 12% for every 1000 m, the pressure at sea level is about 1013 hPa (Hectopascal is a 100x multiple of the pascal). Tip: Let t- meters O 963 hPa O 967 hPa O 961 hPa O 965 hPaarrow_forward
- The room you are sitting in has a height of 3.6 m. Taking the air pressure at the top (ceiling) as 100,000 Pa what is the air pressure at the bottom of the room? Note for air take the density= 1.2 kg/m³.arrow_forwardSuppose the human body as a column of blood. the density of the blood is 1.04 gm/cm³ if the average pressure at the heart = 100 mmHg. what is the height of blood column?arrow_forwardThe air pressure at an altitude of 5.6 k is 7.4 lb/sq in. What is the atmospheric pressure at this altitude in millibars?arrow_forward
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