(a)
Interpretation:
Whether iodine is oxidized or reduced in reaction below has to be determined.
Concept Introduction:
Oxidation number is integer value allotted to every element. It is formal charge occupied by atom if all of its bonds are dissociated heterolytically. Below mentioned are rules to assign oxidation numbers to various elements.
1. Elements present in their free state have zero oxidation number.
2. Oxidation number of hydrogen is generally
3. Oxidation number of oxygen is
4. Metals have positive oxidation numbers.
5. Negative oxidation numbers are assigned to most electronegative element in covalent compounds.
6. Sum of oxidation numbers of different elements in neutral atom is zero.
7. Sum of oxidation numbers of various elements in polyatomic ion is equal to charge present on ion.
(a)
Answer to Problem 1RQ
Iodine undergoes oxidation in this reaction.
Explanation of Solution
Given chemical equation is as follows:
Oxidation of element in their elemental state is 0. Thus oxidation state of
Expression for oxidation number in
Rearrange equation (1) for oxidation number of
Substitute
Hence, oxidation number of
Oxidation state of iodine in
(b)
Interpretation:
Whether chlorine is oxidized or reduced in reaction below has to be determined.
Concept Introduction:
Refer to part (a).
(b)
Answer to Problem 1RQ
Chlorine undergoes reduction in this reaction.
Explanation of Solution
Given chemical equation is as follows:
Oxidation of element in their elemental state is 0. Thus oxidation state of
Expression for oxidation number in
Rearrange equation (3) for oxidation number of
Substitute
Hence, oxidation number of
Oxidation state of chlorine in
Want to see more full solutions like this?
Chapter 17 Solutions
EBK FOUNDATIONS OF COLLEGE CHEMISTRY