In a first experiment, a sinusoidal sound wave is sent through a long tube of air. transporting energy at the average rate of P avg, 1 · In a second experiment, two other sound waves, identical to the first one, are to be sent simultaneously through the tube with a phase difference ϕ of either 0, 0.2 wavelength, or 0.5 wavelength between the waves, (a) With only mental calculation, rank those choices of ϕ according to the average rate at which the waves will transport energy, greatest first, (b) For the first choice of ϕ , what is the average rate in terms of P avg, 1 ?

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Answer 1

Textbook Question

Chapter 17, Problem 1Q

In a first experiment, a sinusoidal sound wave is sent through a long tube of air. transporting energy at the average rate of P_{avg, 1}· In a second experiment, two other sound waves, identical to the first one, are to be sent simultaneously through the tube with a phase difference ϕ of either 0, 0.2 wavelength, or 0.5 wavelength between the waves, (a) With only mental calculation, rank those choices of ϕ according to the average rate at which the waves will transport energy, greatest first, (b) For the first choice of ϕ, what is the average rate in terms of P_{avg, 1}?

Expert Solution & Answer

To determine

To find:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first.

b) The average rate of energy transport for the first choice in (a).

Answer to Problem 1Q

Solution:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first, is $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

b) The average rate of energy transport for (a) $Pavg=4Pavg1$

Explanation of Solution

1) Concept:

The rate of energy transported by a travelling wave depends on the intensity of the wave as well as the area to which the energy is transported. The intensity of a resultant wave depends on the phase difference between the two superposing waves.

2) Formula:

$P= I.A$

3) Given:

i) The average rate of energy transported by a single wave = $Pavg1$

ii) The phase difference between the two waves sent through the pipe are $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

4) Calculations:

a) The rate of energy transported is given by

$P= I.A$

$I$ is intensity of the wave and $A$ is area to which the energy is transported.

When two waves are sent with phase difference $ϕ1=0$ ; the two waves will coincide exactly with each other. There will be constructive interference between the two and the resultant amplitude will be twice the original amplitude. Hence, the intensity of the resultant wave will be 4 times the original. (Since $I=A2$ )

Thus, the rate of energy transport for $ϕ1=0$ will be more than that for a single wave.

When two waves are sent with phase difference $ϕ2=0.2 λ$ ; the two waves will coincide partially. There will be partial constructive interference between the two waves.

Hence, the resultant intensity will be more than the single wave but less than that for $ϕ1=0$

When two waves are sent with phase difference $ϕ3=0.5 λ$ ; the two waves will show destructive interference. i.e the resultant wave will be a standing wave and not a travelling wave. Hence, it will not transport the energy.

Hence, the ranking of the situations will be

$Pφ=0>Pφ=0.2λ>Pφ=0.5 λ$

b) Since the amplitude of the resultant wave is twice the single wave, intensity is four fold. Hence, the rate of energy transported will be

$Pavg=I .A$

$∴Pavg= 4I1.A$

$∴ Pavg=4 . Pavg 1$

Conclusion:

The energy transported by a wave can be calculated by using the intensity of the wave. Here, the intensity changes according to the phase difference between the two superposing waves. Hence the rate of energy transported changes as the phase difference changes.

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Answer 2

Textbook Question

Chapter 17, Problem 1Q

In a first experiment, a sinusoidal sound wave is sent through a long tube of air. transporting energy at the average rate of P_{avg, 1}· In a second experiment, two other sound waves, identical to the first one, are to be sent simultaneously through the tube with a phase difference ϕ of either 0, 0.2 wavelength, or 0.5 wavelength between the waves, (a) With only mental calculation, rank those choices of ϕ according to the average rate at which the waves will transport energy, greatest first, (b) For the first choice of ϕ, what is the average rate in terms of P_{avg, 1}?

Expert Solution & Answer

To determine

To find:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first.

b) The average rate of energy transport for the first choice in (a).

Answer to Problem 1Q

Solution:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first, is $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

b) The average rate of energy transport for (a) $Pavg=4Pavg1$

Explanation of Solution

1) Concept:

The rate of energy transported by a travelling wave depends on the intensity of the wave as well as the area to which the energy is transported. The intensity of a resultant wave depends on the phase difference between the two superposing waves.

2) Formula:

$P= I.A$

3) Given:

i) The average rate of energy transported by a single wave = $Pavg1$

ii) The phase difference between the two waves sent through the pipe are $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

4) Calculations:

a) The rate of energy transported is given by

$P= I.A$

$I$ is intensity of the wave and $A$ is area to which the energy is transported.

When two waves are sent with phase difference $ϕ1=0$ ; the two waves will coincide exactly with each other. There will be constructive interference between the two and the resultant amplitude will be twice the original amplitude. Hence, the intensity of the resultant wave will be 4 times the original. (Since $I=A2$ )

Thus, the rate of energy transport for $ϕ1=0$ will be more than that for a single wave.

When two waves are sent with phase difference $ϕ2=0.2 λ$ ; the two waves will coincide partially. There will be partial constructive interference between the two waves.

Hence, the resultant intensity will be more than the single wave but less than that for $ϕ1=0$

When two waves are sent with phase difference $ϕ3=0.5 λ$ ; the two waves will show destructive interference. i.e the resultant wave will be a standing wave and not a travelling wave. Hence, it will not transport the energy.

Hence, the ranking of the situations will be

$Pφ=0>Pφ=0.2λ>Pφ=0.5 λ$

b) Since the amplitude of the resultant wave is twice the single wave, intensity is four fold. Hence, the rate of energy transported will be

$Pavg=I .A$

$∴Pavg= 4I1.A$

$∴ Pavg=4 . Pavg 1$

Conclusion:

The energy transported by a wave can be calculated by using the intensity of the wave. Here, the intensity changes according to the phase difference between the two superposing waves. Hence the rate of energy transported changes as the phase difference changes.

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Answer 3

Textbook Question

Chapter 17, Problem 1Q

In a first experiment, a sinusoidal sound wave is sent through a long tube of air. transporting energy at the average rate of P_{avg, 1}· In a second experiment, two other sound waves, identical to the first one, are to be sent simultaneously through the tube with a phase difference ϕ of either 0, 0.2 wavelength, or 0.5 wavelength between the waves, (a) With only mental calculation, rank those choices of ϕ according to the average rate at which the waves will transport energy, greatest first, (b) For the first choice of ϕ, what is the average rate in terms of P_{avg, 1}?

Expert Solution & Answer

To determine

To find:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first.

b) The average rate of energy transport for the first choice in (a).

Answer to Problem 1Q

Solution:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first, is $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

b) The average rate of energy transport for (a) $Pavg=4Pavg1$

Explanation of Solution

1) Concept:

The rate of energy transported by a travelling wave depends on the intensity of the wave as well as the area to which the energy is transported. The intensity of a resultant wave depends on the phase difference between the two superposing waves.

2) Formula:

$P= I.A$

3) Given:

i) The average rate of energy transported by a single wave = $Pavg1$

ii) The phase difference between the two waves sent through the pipe are $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

4) Calculations:

a) The rate of energy transported is given by

$P= I.A$

$I$ is intensity of the wave and $A$ is area to which the energy is transported.

When two waves are sent with phase difference $ϕ1=0$ ; the two waves will coincide exactly with each other. There will be constructive interference between the two and the resultant amplitude will be twice the original amplitude. Hence, the intensity of the resultant wave will be 4 times the original. (Since $I=A2$ )

Thus, the rate of energy transport for $ϕ1=0$ will be more than that for a single wave.

When two waves are sent with phase difference $ϕ2=0.2 λ$ ; the two waves will coincide partially. There will be partial constructive interference between the two waves.

Hence, the resultant intensity will be more than the single wave but less than that for $ϕ1=0$

When two waves are sent with phase difference $ϕ3=0.5 λ$ ; the two waves will show destructive interference. i.e the resultant wave will be a standing wave and not a travelling wave. Hence, it will not transport the energy.

Hence, the ranking of the situations will be

$Pφ=0>Pφ=0.2λ>Pφ=0.5 λ$

b) Since the amplitude of the resultant wave is twice the single wave, intensity is four fold. Hence, the rate of energy transported will be

$Pavg=I .A$

$∴Pavg= 4I1.A$

$∴ Pavg=4 . Pavg 1$

Conclusion:

The energy transported by a wave can be calculated by using the intensity of the wave. Here, the intensity changes according to the phase difference between the two superposing waves. Hence the rate of energy transported changes as the phase difference changes.

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Answer 4

Textbook Question

Chapter 17, Problem 1Q

In a first experiment, a sinusoidal sound wave is sent through a long tube of air. transporting energy at the average rate of P_{avg, 1}· In a second experiment, two other sound waves, identical to the first one, are to be sent simultaneously through the tube with a phase difference ϕ of either 0, 0.2 wavelength, or 0.5 wavelength between the waves, (a) With only mental calculation, rank those choices of ϕ according to the average rate at which the waves will transport energy, greatest first, (b) For the first choice of ϕ, what is the average rate in terms of P_{avg, 1}?

Expert Solution & Answer

To determine

To find:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first.

b) The average rate of energy transport for the first choice in (a).

Answer to Problem 1Q

Solution:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first, is $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

b) The average rate of energy transport for (a) $Pavg=4Pavg1$

Explanation of Solution

1) Concept:

The rate of energy transported by a travelling wave depends on the intensity of the wave as well as the area to which the energy is transported. The intensity of a resultant wave depends on the phase difference between the two superposing waves.

2) Formula:

$P= I.A$

3) Given:

i) The average rate of energy transported by a single wave = $Pavg1$

ii) The phase difference between the two waves sent through the pipe are $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

4) Calculations:

a) The rate of energy transported is given by

$P= I.A$

$I$ is intensity of the wave and $A$ is area to which the energy is transported.

When two waves are sent with phase difference $ϕ1=0$ ; the two waves will coincide exactly with each other. There will be constructive interference between the two and the resultant amplitude will be twice the original amplitude. Hence, the intensity of the resultant wave will be 4 times the original. (Since $I=A2$ )

Thus, the rate of energy transport for $ϕ1=0$ will be more than that for a single wave.

When two waves are sent with phase difference $ϕ2=0.2 λ$ ; the two waves will coincide partially. There will be partial constructive interference between the two waves.

Hence, the resultant intensity will be more than the single wave but less than that for $ϕ1=0$

When two waves are sent with phase difference $ϕ3=0.5 λ$ ; the two waves will show destructive interference. i.e the resultant wave will be a standing wave and not a travelling wave. Hence, it will not transport the energy.

Hence, the ranking of the situations will be

$Pφ=0>Pφ=0.2λ>Pφ=0.5 λ$

b) Since the amplitude of the resultant wave is twice the single wave, intensity is four fold. Hence, the rate of energy transported will be

$Pavg=I .A$

$∴Pavg= 4I1.A$

$∴ Pavg=4 . Pavg 1$

Conclusion:

The energy transported by a wave can be calculated by using the intensity of the wave. Here, the intensity changes according to the phase difference between the two superposing waves. Hence the rate of energy transported changes as the phase difference changes.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

To find:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first.

b) The average rate of energy transport for the first choice in (a).

Answer to Problem 1Q

Solution:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first, is $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

b) The average rate of energy transport for (a) $Pavg=4Pavg1$

Explanation of Solution

1) Concept:

The rate of energy transported by a travelling wave depends on the intensity of the wave as well as the area to which the energy is transported. The intensity of a resultant wave depends on the phase difference between the two superposing waves.

2) Formula:

$P= I.A$

3) Given:

i) The average rate of energy transported by a single wave = $Pavg1$

ii) The phase difference between the two waves sent through the pipe are $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

4) Calculations:

a) The rate of energy transported is given by

$P= I.A$

$I$ is intensity of the wave and $A$ is area to which the energy is transported.

When two waves are sent with phase difference $ϕ1=0$ ; the two waves will coincide exactly with each other. There will be constructive interference between the two and the resultant amplitude will be twice the original amplitude. Hence, the intensity of the resultant wave will be 4 times the original. (Since $I=A2$ )

Thus, the rate of energy transport for $ϕ1=0$ will be more than that for a single wave.

When two waves are sent with phase difference $ϕ2=0.2 λ$ ; the two waves will coincide partially. There will be partial constructive interference between the two waves.

Hence, the resultant intensity will be more than the single wave but less than that for $ϕ1=0$

When two waves are sent with phase difference $ϕ3=0.5 λ$ ; the two waves will show destructive interference. i.e the resultant wave will be a standing wave and not a travelling wave. Hence, it will not transport the energy.

Hence, the ranking of the situations will be

$Pφ=0>Pφ=0.2λ>Pφ=0.5 λ$

b) Since the amplitude of the resultant wave is twice the single wave, intensity is four fold. Hence, the rate of energy transported will be

$Pavg=I .A$

$∴Pavg= 4I1.A$

$∴ Pavg=4 . Pavg 1$

Conclusion:

The energy transported by a wave can be calculated by using the intensity of the wave. Here, the intensity changes according to the phase difference between the two superposing waves. Hence the rate of energy transported changes as the phase difference changes.

Answer 8

Expert Solution & Answer

To determine

To find:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first.

b) The average rate of energy transport for the first choice in (a).

Answer to Problem 1Q

Solution:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first, is $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

b) The average rate of energy transport for (a) $Pavg=4Pavg1$

Explanation of Solution

1) Concept:

The rate of energy transported by a travelling wave depends on the intensity of the wave as well as the area to which the energy is transported. The intensity of a resultant wave depends on the phase difference between the two superposing waves.

2) Formula:

$P= I.A$

3) Given:

i) The average rate of energy transported by a single wave = $Pavg1$

ii) The phase difference between the two waves sent through the pipe are $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

4) Calculations:

a) The rate of energy transported is given by

$P= I.A$

$I$ is intensity of the wave and $A$ is area to which the energy is transported.

When two waves are sent with phase difference $ϕ1=0$ ; the two waves will coincide exactly with each other. There will be constructive interference between the two and the resultant amplitude will be twice the original amplitude. Hence, the intensity of the resultant wave will be 4 times the original. (Since $I=A2$ )

Thus, the rate of energy transport for $ϕ1=0$ will be more than that for a single wave.

When two waves are sent with phase difference $ϕ2=0.2 λ$ ; the two waves will coincide partially. There will be partial constructive interference between the two waves.

Hence, the resultant intensity will be more than the single wave but less than that for $ϕ1=0$

When two waves are sent with phase difference $ϕ3=0.5 λ$ ; the two waves will show destructive interference. i.e the resultant wave will be a standing wave and not a travelling wave. Hence, it will not transport the energy.

Hence, the ranking of the situations will be

$Pφ=0>Pφ=0.2λ>Pφ=0.5 λ$

b) Since the amplitude of the resultant wave is twice the single wave, intensity is four fold. Hence, the rate of energy transported will be

$Pavg=I .A$

$∴Pavg= 4I1.A$

$∴ Pavg=4 . Pavg 1$

Conclusion:

The energy transported by a wave can be calculated by using the intensity of the wave. Here, the intensity changes according to the phase difference between the two superposing waves. Hence the rate of energy transported changes as the phase difference changes.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

To find:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first.

b) The average rate of energy transport for the first choice in (a).

Answer 12

Answer to Problem 1Q

Solution:

a) The rank of phase difference according to the average rate of transport of energy by the waves, greatest first, is $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

b) The average rate of energy transport for (a) $Pavg=4Pavg1$

Answer 13

Explanation of Solution

1) Concept:

The rate of energy transported by a travelling wave depends on the intensity of the wave as well as the area to which the energy is transported. The intensity of a resultant wave depends on the phase difference between the two superposing waves.

2) Formula:

$P= I.A$

3) Given:

i) The average rate of energy transported by a single wave = $Pavg1$

ii) The phase difference between the two waves sent through the pipe are $ϕ=0 , ϕ=0.2 λ and ϕ=0.5 λ$

4) Calculations:

a) The rate of energy transported is given by

$P= I.A$

$I$ is intensity of the wave and $A$ is area to which the energy is transported.

When two waves are sent with phase difference $ϕ1=0$ ; the two waves will coincide exactly with each other. There will be constructive interference between the two and the resultant amplitude will be twice the original amplitude. Hence, the intensity of the resultant wave will be 4 times the original. (Since $I=A2$ )

Thus, the rate of energy transport for $ϕ1=0$ will be more than that for a single wave.

When two waves are sent with phase difference $ϕ2=0.2 λ$ ; the two waves will coincide partially. There will be partial constructive interference between the two waves.

Hence, the resultant intensity will be more than the single wave but less than that for $ϕ1=0$

When two waves are sent with phase difference $ϕ3=0.5 λ$ ; the two waves will show destructive interference. i.e the resultant wave will be a standing wave and not a travelling wave. Hence, it will not transport the energy.

Hence, the ranking of the situations will be

$Pφ=0>Pφ=0.2λ>Pφ=0.5 λ$

b) Since the amplitude of the resultant wave is twice the single wave, intensity is four fold. Hence, the rate of energy transported will be

$Pavg=I .A$

$∴Pavg= 4I1.A$

$∴ Pavg=4 . Pavg 1$

Conclusion:

The energy transported by a wave can be calculated by using the intensity of the wave. Here, the intensity changes according to the phase difference between the two superposing waves. Hence the rate of energy transported changes as the phase difference changes.

Answer 14

Ch. 17 - In a first experiment, a sinusoidal sound wave is...Ch. 17 - In Fig. 17-25, two point sources S1, and S2, which...Ch. 17 - In Fig. 17-26, three long tubes A,B, and C are...Ch. 17 - Prob. 4Q Ch. 17 - In Fig. 17-27, pipe A is made to oscillate in its...Ch. 17 - Prob. 6Q Ch. 17 - Figure 17-28 shows a moving sound source S that...Ch. 17 - Prob. 8Q Ch. 17 - For a particular tube, here are four of the six...Ch. 17 - Prob. 10Q

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