CHEMISTRY >CUSTOM<
CHEMISTRY >CUSTOM<
8th Edition
ISBN: 9781309097182
Author: SILBERBERG
Publisher: MCG/CREATE
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Chapter 17, Problem 17.99P

(a)

Interpretation Introduction

Interpretation:

Overall reaction for the formation of carbon dioxide and hydrogen from methane, steam and oxygen has to be given.

(a)

Expert Solution
Check Mark

Answer to Problem 17.99P

Overall reaction is 2CH4(g) + O2(g) + 2H2O(g)  2CO(g) + 6H2(g).

Explanation of Solution

Given reaction is shown below:

  2CH4(g) + O2(g)  2CO(g) + 4H2(g) (1)CO(g) + H2O(g)  CO2(g) + H2(g) (2)

To get the overall reaction for the formation of carbon dioxide and hydrogen from methane, steam and oxygen, reaction (1) and (2) has to be added. Reaction (2) is multiplied with 2 for cancelling CO(g) from both reactions.

Therefore,

Overall reaction for the formation of carbon dioxide and hydrogen from methane, steam and oxygen follows as,

  2CH4(g) + O2(g)  2CO(g) + 4H2(g) 2CO(g) + 2H2O(g)  2CO2(g) + 2H2(g) _2CH4(g) + O2(g) + 2H2O(g)  2CO(g) + 6H2(g)

Overall reaction is 2CH4(g) + O2(g) + 2H2O(g)  2CO(g) + 6H2(g).

(b)

Interpretation Introduction

Interpretation:

Kp for the overall reaction has to be determined.

Concept Introduction:

Equilibrium constant: It is the ratio of products to reactants has a constant value when the reaction is in equilibrium at a certain temperature. And it is represented by the letter K.

For a reaction,

aA+bBcC+dD

The equilibrium constant in terms of  partial pressure is, K=(PC)c(PD)d(PA)a(PB)b

where,

a, b, c and d are the stoichiometric coefficients of reactant and product in the reactions

(b)

Expert Solution
Check Mark

Answer to Problem 17.99P

Kp for the overall reaction is 1.76×1029.

Explanation of Solution

Given reaction is shown below:

  2CH4(g) + O2(g)  2CO(g) + 4H2(g) (1)CO(g) + H2O(g)  CO2(g) + H2(g) (2)Kp1 = 9.34×1028Kp2 = 1.374

To get the overall reaction for the formation of carbon dioxide and hydrogen from methane, steam and oxygen, reaction (1) and (2) has to be added. Reaction (2) is multiplied with 2 for cancelling CO(g) from both reactions.

Hence, Kp2 becomes Kp2 = (1.374)2 = 1.888

Therefore,

Kp for the overall reaction is given below,

  Kp = Kp1Kp2= (9.34×1028)(1.888)= 1.76×1029

Kp for the overall reaction is 1.76×1029.

(c)

Interpretation Introduction

Interpretation:

KC for the overall reaction has to be calculated.

Concept Introduction:

The relation between and Kp and Kc is given by the following equation.

Kp = Kc(RT)Δngas Kp = Equilibrium constant in terms of partial pressureKc = Equilibrium constant in terms of concentrationΔngas = moles of gaseous product  moles of gaseous reactant

Only moles of gaseous products and reactants are used for calculating Δngas.

(c)

Expert Solution
Check Mark

Answer to Problem 17.99P

KC for the overall reaction is 3.19×1023.

Explanation of Solution

Given data is shown below:

  Overall reaction:2CH4(g) + O2(g) + 2H2O(g)  2CO(g) + 6H2(g)KP =  1.76×1029T = 1000 K

  • Determine number of moles of reactants and products:

No. of moles of reactants = 2.0 mol CH4 + 1.0 mol O2 + 2.0 mol H2O= 5.0 molNo. of moles of products = 2.0 mol CO2 + 6.0 mol H2= 8.0 mol

  • Determine Δngas:

Δngas is determined as follows,

  Δngas  = moles of gaseous product - moles of gaseous reactant =85 =3

  • Determine KC:

KC of the reaction can be determined from given Kp as below,

  Kp = Kc(RT)Δngas1.76×1029= Kc[(0.0821 atm.L/mol.K)(1000 K)]3 Kc= 3.19×1023

Therefore,

KC for the overall reaction is 3.19×1023.

(d)

Interpretation Introduction

Interpretation:

Final pressure for the given reaction has to be calculated using the given data.

Concept Introduction:

The relation between pressure and number of moles of gas is given by the following equation.

  ninitialPinitial = nfinalPfinalwhere,n = No. of molesP= Pressure

(d)

Expert Solution
Check Mark

Answer to Problem 17.99P

Final pressure for the given reaction is 48 atm.

Explanation of Solution

Given data is shown below:

  Overall reaction:2CH4(g) + O2(g) + 2H2O(g)  2CO(g) + 6H2(g)Pinitial = 30.0 atm reactant

  • Determine initial number of moles of gas:

Total mol of gas initially = No. of moles of reactants = 2.0 mol CH4 + 1.0 mol O2 + 2.0 mol H2O= 5.0 mol

  • Determine initial number of moles of gas:

Total mol of gas finally = No. of moles of products = 2.0 mol CO2 + 6.0 mol H2= 8.0 mol

  • Determine final pressure::

Final pressure for the given reaction is determined as follows,

  ninitialPinitial = nfinalPfinal5.0 mol30.0 atm = 8.0 molPfinalPfinal = (30.0 atm)(8.0 mol5.0 mol)= 48 atm

Final pressure for the given reaction is 48 atm.

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Chapter 17 Solutions

CHEMISTRY >CUSTOM<

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