CHEMISTRY-TEXT
8th Edition
ISBN: 9780134856230
Author: Robinson
Publisher: PEARSON
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Chapter 17, Problem 17.4P
Interpretation Introduction
Interpretation:
“pH of reaction” should be explained.
Concept introduction:
As, equal volumes of solution added so Molarities will be
[CH3 NH3+ ] = M/ V = 0.6/2 = 0.3 M
[CH3 NH2] = 0.2 /2 = 0.1 M
Given:
[CH3 NH3+ ]= 0.6M
[CH3 NH2] = 0.2 M
Kb =3.7 * 10-4
To determine:
PH of reaction
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Chapter 17 Solutions
CHEMISTRY-TEXT
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Ch. 17 - PRACTICE 16.12 How would you prepare anbuffer...Ch. 17 - APPLY 16.13 Suppose you are performing an...Ch. 17 - A 40.0 mL volume of 0.100 M HCl is titrated with...Ch. 17 - APPLY 16.15 A 40.0 mL volume of 0.100 M NaOH is...Ch. 17 - What is the pH at the equivalence point in the...Ch. 17 - The following pictures represent solutions at...Ch. 17 - Assume that 40.0 mL of 0.0800...Ch. 17 - Assume that 40.0 mL of a 0.0250 M solution of the...Ch. 17 - Write the equilibrium-constant expression for...Ch. 17 - The following pictures represent solutions of...Ch. 17 - Prob. 17.21PCh. 17 - Ca2, which causes clotting, is removed from...Ch. 17 - What is the molar solubility of Ag2CrO4 in water...Ch. 17 - Prior to having an X-ray exam of the upper...Ch. 17 - Calculate the molar solubility of MgF2 , in...Ch. 17 - Calculate the molar solubility of Zn(OH)2 , in a...Ch. 17 - In an excess of NH3(aq),Cu2+ ion forms a deep blue...Ch. 17 - Cyanide ion is used in gold mining because it...Ch. 17 - Prob. 17.29PCh. 17 - 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