Explanation Given info: The intensity of sound pick by hearing aid is 3.00 × 10 − 11 W / m 2 , frequency of hearing aid is 250 Hz , sound level of audible frequencies is 30.0 dB . The formula to calculate the sound level of sound wave is, β 1 = 10 log ( I I o ) Here, I is the intensity of sound wave. I o is the reference intensity of sound wave. Substitute 3.00 × 10 − 11 W / m 2 for I and 1 × 10 − 12 W / m 2 for I o in the above formula to find β . β 1 = 10 log ( I I o ) = 10 log ( 3.00 × 10 − 11 W / m 2 1 × 10 − 12 W / m 2 ) = 14.77 dB Thus, the sound level of sound wave is 14.77 dB . The formula to calculate the sound level of an hearing aid is, β = β 1 + β 2 Here, β 1 is the sound level of audible frequencies. β 2 is the sound level that is increased by hearing aid. Substitute 14.77 dB for β 1 and 30.0 dB for β 2 in the above formula to find β . β = β 1 + β 2 = 14.77 dB + 30.0 dB = 44

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 17, Problem 17.23P

To determine

The intensity delivered to the hearing aid.

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Chapter 17 Solutions

Physics for Scientists and Engineers, Technology Update (No access codes included)

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The intensity delivered to the hearing aid.

Solution Summary: The author explains the formula to calculate the sound level of an hearing aid is, beta.

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The intensity delivered to the hearing aid.

Chapter 17 Solutions