Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Chapter 17, Problem 14P
To determine
Soil classification using USCS method
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The table shows the laboratory result of the sieve analysis of the sample. Determine the percent finer at size 0.74and 0.004. Determine also the soil classification using AASHTO.
The table below shows the laboratory results of the sieve analysis of a sample. The soil has
a liquid limit of 35% and plasticity limit of 9%.
Determine the following:
a) Plot the grain size curve.
b) Classify the soil according to
SIZE (mm)
WEIGHT RETAINED (gms.)
0.25
18.96
USCS
0.149
33.18
c) Classify the soil according to
0.074
45.03
AASHTO
0.052
54.51
d) Classify the soil according to
0.02
42.66
USDA
0.01
11.85
0.004
4.74
0.001
4.74
PAN
21.33
Page
1 | 1
Q +
-
A Sample of soil was tested in the laboratory with the following results
Liquid limit =30%
Plastic limit =12%
U.S. Sieve Size Percentage Passing
3/8 in. 100.0
No. 4 76.5
No. 10 60.0
No. 40 39.7
No. 200 15.2
Classify the soil sample by the USCS classification system.
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- Given the sieve analysis and plasticity data for five soils, classify the soil 4 and 5 according to Unified Soil Classification System and explain your steps for each soil sample classifications.arrow_forwardThe following table shows the sieve analysis data on the left and hydrometer test data on the right for the minus No. 200 sieve material for a given soil. (a) Compute Cu and Cc. (b) Report the percentage gravel, sand, silt, and clay according to AASHTO. (c) Classify the soil according to AASHTO.arrow_forwardClassify this Soil Sample accoring to Unified Soil Classification System Soil Sample 1 Percentage Sieve No.4 60% Sieve No.200 42% Liquid Limit 28% Plasticity Index 4.5% Topic Soil Classification (Soil Mechanics). Show full solutionarrow_forward
- Can I get a step by step for this question? Using the data presented for the given soil sample, determine the soil classification using the ASTM and the AASHTO Soil classification system. Give the group index if needed. The soil is inorganic soil. Sieve No. 19mm (¾ in.) 12.5mm (1/2in.) No. 4 (4.75 mm) No. 10 (2.00 mm). No. 20 (0.850 mm) No. 40 (0.425 mm) No. 100 (0.150 mm) No. 200 (0.075 mm) Percent Passing 100 83 67 56 54 45 39 36 Cu: 5.5 and Cc: 1.8 Atterberg limits: Liquid limit: 20%, Plasticity Index: 6%.arrow_forwardThe result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. Sieve Analysis Sieve Diameter, Percent Passing Number mm. A В C 4 4.76 2.38 90 100 100 8 84 90 100 10 2 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 63 LL 42 46 47 PL 23 29 24 What is the classification of Soil A? What is the classification of Soil B? What is the classification of Soil C? EDIarrow_forwardPercent Passing (by weight) You are provided the mechanical sieve/hydrometer and Atterberg Limit test results for three soils, labeled as Soil #1, Soil #2, and Soil #3. The mechanical sieve results are shown in Figure 1, while Table 2 presents the Atterberg Limit test results. Classify the soils in accordance with the Unified Soil Classification System (USCS) and AASHTO. 100 90 80 60 50 40 30 20 10 0 0.0001 CLAY SIZE Soil #3 Soil #2 Soil #1 0.001 } Soil #1 #2 SILT SIZE #3 0.01 0.1 Grain Size (mm) Figure 1. Mechanical Sieve and Hydrometer Results for Problem #2. 0.075 mm Table 2. Atterberg Limits (ASTM D4318) for Problem #2. LL 68 39 SAND SIZE ΝΑ 1 PL 19 31 ΝΑ GRAVEL 10arrow_forward
- Soil classification requires all of the results of the following tests: Liquid limit and Plastic limit tests Atterberg limit and Hydrometer tests Atterberg limit and grain size analysis test Sieve and Hydrometer analysis testsarrow_forward00 docs.google.com/forms/ A It is easier than the sieve analysis CH soil is formed by chemical 1/1 weathering * True False Neither true nor false The grain size distribution has 0/2 been conducted on a soil sample and the following have been obtained: Percentage of passing from sieve number 200 is 47%, LL = 30%, PL = 15% Using the above information, the soil classification according to the USCS is * :O A5arrow_forward7. Given below is the result of a sieve analysis done on a soil sample.arrow_forward
- Problem 1 The following grain size distribution test results were obtained from sieve analysis test. Percent Passing U.S. Sieve Number 4 100 10 90 20 64 40 38 08 200 18 13 Also, the Atterberg test results revealed the following results LL = 23 and PL = 19 Classify the soil by using a) AASHTO soil classification system b) USCS soil classification system Give group names and group symbols. Show the GSDC and sketch of finding necessary information from GSDC. Problem 2arrow_forwardA sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by both the AASHTO and the USCS. - LL = 29%, PL = 19% Sieve Size 1 in 3/4 in 3/8 in #4 #10 #40 #200 Percent Passing 100 90 82 70 65 54 25arrow_forwardClassify the soil sample using USDA Textural Classification System if the sample has the following particle size distribution. Gravel = 18 % Silt = 11 % Sand = 66 % Clay = 5 % O Loamy Sand O sity Loam O Sandy Loam O sity Clayarrow_forward
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