consider a parallel plate capacitor with a dielectric material between the plates. if the temperature of the dielectric increases, the capacitance a) increases b) decreases c) remains the same

You have a capacitor made of two sheets of foil of area 2.7 cm2 separated by a distance 0.5 mm. a) what is the capacitance (in pF(10-12F)) of this capacitor? b) what is the voltage across the capacitor if 7 x 10-12 C is stored? c) how much energy is stored in the capacitor?

You have a capacitor made of two sheets of foil of area 2.7 cm2 separated by a distance 0.5 mm. a) what is the capacitance (in pF(10-12F)) of this capacitor? b) what is the voltage across the capacitor if 7 x 10-12 C is stored? c) how much energy is stored in the capacitor?

A simple capacitor can be constructed from two conductive plates. Two conductive plates with an area of 10.0cm x 10.0 cm are held facing one another at a separation of 1.50 mm and 12.0 V is applied between them. a) Find the capacitance of this configuration b) Find the charge on the plates. c) How much energy is stored in the capacitor? d) How much energy can the capacitor store if a dielectric with K= 4.5 is inserted between the plates rather than air?

The volume enclosed by the plates of a parallel plate capacitor is given by the equation Volume = Ad. If one doubles the area, A, of the plates and reduces the plate separation, d, by a factor of two so that the volume remains the same, the capacitance will do which of the following? decrease by a factor of 4 O increase by a factor of 4 increase by a factor of 2 decrease by a factor of 2 O remain constant

A parallel-plate capacitor has a capacitance of 10 uf and is charged with a 16 V power supply. The power supply is then removed and a dielectric material of dielectric constant 4 is used to fill the space between the plates of the capacitor. What is the capacitance now of the capacitor in uf and, what is the voltage now across the capacitor in V O C=10.0uF, V=4.0V O C=10.0uF, V-16.0V O C=40.0uF, V=16.0V o C-40.0uF. V=4.0V O C=40.0µF. V=64.0V

Two parallel-plate capacitors have the same charge Q, but the area of the plates in capacitor 1 is 2.0cm2 and the area of the plates in capacitor 2 is 4.0cm2. If the spacing between the plates in capacitor 1 is 1.0mm , what should the spacing between the plates in capacitor 2 be to make the capacitance of the two capacitors equal?     0.5mm     1.0mm     2.0mm     4.0mm

9d K1=5 5d 8d 15d 15d 2d » K2=2 Two dielectric slabs with dielectric constants, K, and K2 are placed in parallel plate capacitor as shown in fig. Plates of the capacitor and both slabs have the same width of 15d. If the capacitance of the capacitor before slabs are inserted is Co, What is the capacitance of capacitor with slabs in terms of Co ?

The dielectric of a parallel plate capacitor is to be constructed from glass (Kd= 4.6). The area of each plate is 0.50 m2 . A) What thickness should the glass have if the capacitance is to be 0.10 microfarad? B) What is the charge on the capacitor if connected to a 12-volt battery?

A parallel-plate capacitor illustrated in the figure has a plate area of 10 cm² that are separated by a distance of 1 mm. This capacitor can be thought of two capacitors made from different dielectrics connected in parallel. The two regions have relative permittivities of 2 and 3 respectively. Determine the total capacitance of the parallel plate capacitor. ←A/2 A d A B O (The answer cannot be found on the other choices.) O 53.1251 pF 22.1354 pF O 21.2501 pF O 5.3125 pF