A parallel-plate capacitor has a capacitance of 10 uF and is charged with a 16 V power supply. The power supply is then removed and a dielectric material of dielectric constant 4 is used to fil the space between the plates of the capacitor. What is the capacitance now of the capacitor in uF and, what is the voltage now across the capacitor in V O C-10.0uF, V=4.0V OC=10.0uF. V=16.0V o C=40.0uF, V=16.0V O C-40.0uF. V=4.0V O C-40.0uF, V=64.0V

A capacitor of capacity 10 uF is subjected to charge by a battery of 10 V. Calculate the energy stored in the capacitor.

An air-filled parallel-plate has capacitance Co. When it is connected to a battery with EMF Vo, it has charge Qo and stored energy Ub- The gap is then filled with a slab of material that has dielectric constant K. Which of the following physical quantities do increase by factor of k when the dielectric material is inserted between the plates? Vo Vo The potential difference, charge, and potential energy stored in the capacitor. The charge, capacitance, and potential energy stored in the capacitor. O The potential difference and potential energy stored in the capacitor. O The potential difference across the parallel-plate capacitor and the charge.

An engineer builds a parallel-plate capacitor with adjustable spacing between the plates. When the plates are at their initial separation, the capacitance is 2.00 uF. (a) At this capacitance, the capacitor is connected to a 20.00 V battery. After fully charging, how much energy (in ) is stored in the capacitor? μJ (b) The battery is then disconnected. Without discharging the capacitor, the engineer then doubles the separation between the plates. At this point, how much energy (in µ3) is stored in the capacitor? p] (c) Without changing this new separation between the plates, the capacitor is discharged, and then reconnected to the 20.00 V battery. Now, after fully charging, how much energy (in p) is stored in the capacitor? p3

A 10 cm2 parallel plate capacitor has its plates separated by 5 x 10-4 m thick paper. Find the capacitance of the capacitor. (κpapel = 3,7)

A capacitor is attached to a battery. It has initial capacitance Co, voltage Vo, charge Qo, and energy Uo. Let's put some dielectric material of dielectric constant K in there in two different ways. For each case, figure out the following for the resulting "new" capacitor: C, V, Q, and U, in terms of the old value and K. The capacitor is left attached to the battery. A slab of dielectric material with K=3 is inserted into the capacitor without otherwise disturbing it. In terms of the initial values, what are the new values? The capacitor is disconnected from the battery after it is charged up to Qo. Then, a slab of dielectric material with K=3 is inserted into the capacitor without anybody touching the plates or otherwise disturbing the capacitor. In terms of the initial values, what are the new values?

What is the equivalent capacitance of a 1 Farad capacitor and a 0.5 Farad capacitor in parallel?

A parallel-plate capacitor has a capacitance of 10 mF and is charged with a 20 V power supply. The power supply is then removed and a dielectric of dielectric constant 4 is used to fill the space between the plates. The voltage now across the capacitor is O 5 V. O 80 V. O zero. O 20 V. О 10 V.

The whole combination of capacitors shown in the diagram below is charged a potential difference of 2000V. Find (a) equivalent capacitance, (b) total charge, (c) individual charges and (d) the voltages across each capacitor. 4MF GuF 10ut 12ut

Problem 3:  Consider a parallel plate capacitor having plates of area 1.65 cm2 that are separated by 0.024 mm of neoprene rubber. You may assume the rubber has a dielectric constant κ = 6.7. Part (a)  What is the capacitance in nanofarads?  Part (b)  What charge, in coulombs, does the capacitor hold when 9.00 V is applied across it?