Materials Science and Engineering
Materials Science and Engineering
9th Edition
ISBN: 9781118324578
Author: Jr. William D. Callister
Publisher: WILEY
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Chapter 16.16, Problem 23QP
To determine

To State:

The distinction between carbon and graphite.

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HW_03.pdf EE 213-01 > Assignments HW_#3 uah.instructure.com b Success Confirmation of Question Submission | bartleby ✓ Download → Info × Close Page 1 > of 2 - ZOOM + 1) (5 pts) Use node voltage analysis at nodes A and B to determine values for VA, VB, I₁, 12 and 13. If a current has a negative value, then the reference direction chosen was incorrect and the current is positive in the opposite direction. Your answer can be the negative value – i.e. you find that 12 = -1mA. Note, the current through R5 is (VB - 28 Volts)/10K 10K VA 20K VB 10K R1 12 R2 R5 13 IS1 R3 10 mA 10K 28 V R4 VS1 5K -VREF B 2) (5pts) Use node voltage analysis to find values for the node voltages VA, VR and Vc. Use these node voltages to determine values for V1, V2, V3, V4, 11, 12, 13, and 14. Hints: V3 = VB and the value for Vc can be found with no analysis. Dependent current source has a value of gV3 amps VA gV3 Amps 14 12 20K + V2 - + 10K VB 13 V3 10K - 20K I₁ V₁ + Vc g=5x10-5 20 volts VREF 3) (5 pts) For the…
5. Problem 8-46 on Page 374. 8-46. The L-shaped frame is made from two fixed-connected segments. Determine the vertical displacement of the end C. Use the method of virtual work. El is constant. -9 ft- 2 k/ft 12 ft
HW_02.pdf EE 213-01 > Assignments HW_#4 uah.instructure.com b Success Confirmation of Question Submission | bartleby ✓ Download → Info × Close 1) (5 pts)For the circuit shown, find the value of Ia, Ib, I¸ and Va: Ib 10 Ohms + Ic 20 Ohms 70 Volts Va 40 Ohms Page 1 > of 2 - ZOOM + Hint: use KCL to find Ic in terms of la and lb, use KVL around the right loop to find a relationship between la and lb, use KVL around the outer loop to solve for a current value (use ohms law for the voltage drops across the resistors) - 2) (5 pts) For problem 1, show that the power supplied (delivered) by the source equals the power absorbed by the resistors. 3) (5 pts) Determine the equivalent resistance looking into terminals a-b for the two circuits shown. Use series and parallel resistor combinations. Hint: work from the opposite end of terminals a-b towards terminals a-b a) 24 Ohms 10 Ohms 8 Ohms a REQ b) b = 75K 5 Ohms 50K 60 Ohms 4 OHMs 20 Ohms 30 Ohms □ a 20K 8.2K 40K 16K 10K □ b 7.2K REQ
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