Explanation The value of the acid dissociation constant of acetic acid is 1 .8 × 10 − 5 . The value of the ionic product of water is 1 .0 × 10 − 14 . Sodium acetate ( CH 3 COONa ) dissociates into acetate ion CH 3 COO − ion and Na + ion. The chemical equation corresponding to the ionization of acetate ion ( CH 3 COO − ) is, CH 3 COO − ( a q ) + H 2 O ( l ) ⇌ CH 3 COOH ( a q ) + OH − ( a q ) The value of K b can be calculated by the following formula, K b × K a = K w Where, K b is the base ionization constant. K a is the acid dissociation constant. K w is the ionic product of water. Rearrange the above formula to calculate the value of K b , K b = K w K a Substitute the value of K a and K w in the above expression, K b = 1 .0 × 10 − 14 1 .8 × 10 − 5 = 5 .6 × 10 − 10 The value of K b of acetate ion is 5 .6 × 10 − 10 . Substitute the value of pH in the above equation, pOH = 14 - pH = 14 - 9 .70 = 4 .30 The value of [ OH ] is calculated by the formula, [OH] = 10 − pOH Substitute the value of [ pOH ] in the above expression, [OH] = 10 − 4 .30 = 5 .01 × 10 − 5 M The initial concentration of CH 3 COO − is assumed to be x . The ICE table is formed for the given reaction. CH 3 OO − ( a q ) + H 2 O ( l ) ⇌ CH 3 COOH ( a q ) + OH − ( a q ) Initial : x 0 0 Change : − 5

Chemistry: The Central Science (14th Edition)

14th Edition

ISBN: 9780134414232

Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus

Publisher: PEARSON

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Chapter 16, Problem 81E

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To determine: The molarity of the given sodium acetate solution having pH=9.70 .

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Chapter 16, Problem 80E

Chapter 16, Problem 82E

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Chemistry: The Central Science (14th Edition)

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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