For Problems 34-39, use a differential equation solver to determine the solution to each of the initial-value problems and sketch the corresponding solution curve. The initial-value problem in Problem 21. 21. y ′ − 2 y = f ( x ) , y ( 0 ) = 1 , where f ( x ) = { 1 − x , if x < 1, 0, if x ≥ 1.
For Problems 34-39, use a differential equation solver to determine the solution to each of the initial-value problems and sketch the corresponding solution curve. The initial-value problem in Problem 21. 21. y ′ − 2 y = f ( x ) , y ( 0 ) = 1 , where f ( x ) = { 1 − x , if x < 1, 0, if x ≥ 1.
Solution Summary: The author explains the formula used to find the solution of the initial-value problem.
For Problems 34-39, use a differential equation solver to determine the solution to each of the initial-value problems and sketch the corresponding solution curve.
The initial-value problem in Problem 21.
21.
y
′
−
2
y
=
f
(
x
)
,
y
(
0
)
=
1
, where
f
(
x
)
=
{
1
−
x
,
if
x
<
1,
0,
if
x
≥
1.
With integration, one of the major concepts of calculus. Differentiation is the derivative or rate of change of a function with respect to the independent variable.
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