Explanation Given information: ln ( x 2 + 1 ) − 3 ln x = ln ( 2 ) Formula used: n ln x = ln x n ln x y = ln x − ln y Calculation: Given that ln ( x 2 + 1 ) − 3 ln x = ln ( 2 ) ln ( x 2 + 1 ) − ln x 3 = ln ( 2 ) ( Since n ln x = ln x n ) ln ( x 2 + 1 x 3 ) = ln ( 2 ) ( Since ln x y = ln x − ln y ) Now taking antilog on both sides, we get x 2 + 1 x 3 = 2 x 2 + 1 = 2 x 3 2 x 3 − x 2

4th Edition

ISBN: 9781319050740

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Chapter 1.6, Problem 26E

To determine

Solve for x:ln(x2+1)−3lnx=ln(2).

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Chapter 1.6, Problem 25E

Chapter 1.6, Problem 27E

Chapter 1 Solutions

Calculus: Early Transcendentals

Ch. 1.1 - Prob. 1PQ Ch. 1.1 - Prob. 2PQ Ch. 1.1 - Prob. 3PQ Ch. 1.1 - Prob. 4PQ Ch. 1.1 - Prob. 5PQ Ch. 1.1 - Prob. 6PQ Ch. 1.1 - Prob. 7PQ Ch. 1.1 - Prob. 8PQ Ch. 1.1 - Prob. 9PQ Ch. 1.1 - Prob. 10PQ

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Solve for x : ln ( x 2 + 1 ) − 3 ln x = ln ( 2 ) .

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Solve for x:ln(x2+1)−3lnx=ln(2).

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Chapter 1 Solutions