Chemistry Atoms First2e
2nd Edition
ISBN: 9781947172647
Author: OpenStax
Publisher: OpenStax College
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Textbook Question
Chapter 16, Problem 23E
Write the balanced cell reaction for the cell schematic below, calculate the standard cell potential, and note whether the reaction is Spontaneous under Standard State conditions.
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Chemistry Atoms First2e
Ch. 16 - Identify each half-reaction below as either...Ch. 16 - Identify each half-reaction below as either...Ch. 16 - Assuming each pair of half-reactions below takes...Ch. 16 - Balance the equations below assuming they occur in...Ch. 16 - Identify the oxidant and reductant of each...Ch. 16 - Balance the equations below assuming they occur in...Ch. 16 - Identify the oxidant and reductant of each...Ch. 16 - Why dont hydroxide ions appear in equations for...Ch. 16 - Why dont hydrogen ions appear in equations for...Ch. 16 - Why must the charge balance in oxidation-reduction...
Ch. 16 - Write cell schematics for the following cell...Ch. 16 - Assuming the schematics below represent galvanic...Ch. 16 - Write a balanced equation for the cell reaction of...Ch. 16 - Balance each reaction below, and write a cell...Ch. 16 - Identify the oxidant and reductant in each...Ch. 16 - From the information provided, use cell notation...Ch. 16 - Why is a salt bridge necessary in galvanic cell...Ch. 16 - An active (metal) electrode was found to gain mass...Ch. 16 - An active (metal) electrode was found to lose mass...Ch. 16 - The masses of three electrodes (A, B, and C), each...Ch. 16 - Calculate the standard cell potential for each...Ch. 16 - Calculate the standard cell potential for each...Ch. 16 - Write the balanced cell reaction for the cell...Ch. 16 - Determine the cell reaction and standard cell...Ch. 16 - Determine the cell reaction and standard cell...Ch. 16 - Write the balanced cell reaction for the cell...Ch. 16 - For each pair of standard cell potential and...Ch. 16 - For each pair of standard free energy change and...Ch. 16 - Determine the standard cell potential and the cell...Ch. 16 - Determine ∆G and ∆G for each of the reactions...Ch. 16 - Use the data in Appendix L to calculate...Ch. 16 - Consider a battery made from one half-cell that...Ch. 16 - Consider a battery with the overall reaction:...Ch. 16 - Why do batteries go dead, but fuel cells do not?Ch. 16 - Use the Nernst equation to explain the drop in...Ch. 16 - Using the information thus far in this chapter,...Ch. 16 - Which member of each pair of metals is more likely...Ch. 16 - Consider the following metals: Ag, Au, Mg, Ni, and...Ch. 16 - Aluminum (EoA13+/A1=-2.07V) is easily oxidized...Ch. 16 - If a sample of iron and a sample of zinc come into...Ch. 16 - Suppose you have three different metals. A, B, and...Ch. 16 - Why would a sacrificial anode made of lithium...Ch. 16 - If a 2.5 A current flows through a circuit for 35...Ch. 16 - For the scenario in the previous question, how...Ch. 16 - Write the half-reactions and cell reaction...Ch. 16 - What mass of each product is produced in each of...Ch. 16 - How long would it take to reduce 1 mole of each of...Ch. 16 - A Current of 2.345 A passes through the Shown in...Ch. 16 - An irregularly shaped metal part made from a...
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- What is the standard cell potential you would obtain from a cell at 25C using an electrode in which Hg22+(aq) is in contact with mercury metal and an electrode in which an aluminum strip dips into a solution of Al3+(aq)?arrow_forwardCalculate the standard cell potential of the cell corresponding to the oxidation of oxalic acid, H2C2O4, by permanganate ion. MnO4. 5H2C2O4(aq)+2MnO4(aq)+6H+(aq)10CO2(g)+2Mn2+(aq)+8H2O(l) See Appendix C for free energies of formation: Gf for H2C2O4(aq) is 698 kJ.arrow_forwardCalculate the standard cell potential of the following cell at 25C. Sn(s)Sn2+(aq)I2(aq)I(aq)arrow_forward
- A voltaic cell is constructed in which one half-cell consists of a silver wire in an aqueous solution of AgNO3.The other half cell consists of an inert platinum wire in an aqueous solution containing Fe2+(aq) and Fe3+(aq). (a) Calculate the cell potential, assuming standard conditions. (b) Write the net ionic equation for the reaction occurring in the cell. (c) Which electrode is the anode and which is the cathode? (d) If [Ag+] is 0.10 M, and [Fe2+] and [Fe3+] are both 1.0 M, what is the cell potential? Is the net cell reaction still that used in part (a)? If not, what is the net reaction under the new conditions?arrow_forwardCalculate the cell potential of a cell operating with the following reaction at 25C, in which [MnO4] = 0.010 M, [Br] = 0.010 M. [Mn2] = 0.15 M, and [H] = 1.0 M. 2MNO4(aq)+10Br(aq)+16H+(aq)2MN2(aq)+5Br2(l)+8H2O(l)arrow_forwardAn electrolysis experiment is performed to determine the value of the Faraday constant (number of coulombs per mole of electrons). In this experiment, 28.8 g of gold is plated out from a AuCN solution by running an electrolytic cell for two hours with a current of 2.00 A. What is the experimental value obtained for the Faraday Constant?arrow_forward
- An electrode is prepared from liquid mercury in contact with a saturated solution of mercury(I) chloride, Hg2Cl, containing 1.00 M Cl . The cell potential of the voltaic cell constructed by connecting this electrode as the cathode to the standard hydrogen half-cell as the anode is 0.268 V. What is the solubility product of mercury(I) chloride?arrow_forwarda Calculate G for the following cell reaction: Tl(s)Tl+(aq)Pb2+(aq)Pb(s) The Gf for Tl+(aq) is 32.4 kJ/mol. b From G, calculate the standard cell potential for the cell reaction and from this, determine the standard potential for Tl2+(aq)+eTl(s).arrow_forwardAt 298 K, the solubility product constant for PbC2O4 is 8.5 1010, and the standard reduction potential of the Pb2+(aq) to Pb(s) is 0.126 V. (a) Find the standard potential of the half-reaction PbC2O4(s)+2ePb(s)+C2O42(aq) (Hint: The desired half-reaction is the sum of the equations for the solubility product and the reduction of Pb2+. Find G for these two reactions and add them to find G for their sum. Convert the G to the potential of the desired half-reaction.) (b) Calculate the potential of the Pb/PbC2O4 electrode in a 0.025 M solution of Na2C2O4.arrow_forward
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