EBK GET READY FOR ORGANIC CHEMISTRY
2nd Edition
ISBN: 8220100576379
Author: KARTY
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 16, Problem 16.23YT
Interpretation Introduction
Interpretation:
To determine the lowest chemical shift you should expect to observe for a carbon that is a part of a double bond or is attached to an electronegative atom according to table 16-4.
Concept introduction:
If protons are adjacent to or near a carbon having electron-withdrawing group, they get deshielded and cause a downfield shift. Benzene and additional oxygen atoms can also cause such deshielding.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Organic Chemistry: IR spectroscopy
A student obtains an IR spectrum with an intense, broad absorption at about 3350 cm-1. The student claims that the sample is an alcohol, but the professor says that the absorption is there because the sample is contaminated with water. What peak(s) could be looked for to show that the sample is indeed an alcohol? Which functional groups would make it difficult to use this strategy?
Q11. From each pair of species, determine the stronger base and justify your answer.
(a)
(b)
CI
مل مل
or
Br
or
مل
3. (1) The overall range for carbon chemical shifts are 0 - 220 ppm. Where in "chemical shift" ranges
do you expect to find carbon signals based on their orbital hybridization?
C (sp')
C(sp) as in alkynes, nitriles
C (sp')
Chapter 16 Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
Ch. 16 - Prob. 16.1PCh. 16 - Prob. 16.2PCh. 16 - Prob. 16.3PCh. 16 - Prob. 16.4PCh. 16 - Prob. 16.5PCh. 16 - Prob. 16.6PCh. 16 - Prob. 16.7PCh. 16 - Prob. 16.8PCh. 16 - Prob. 16.9PCh. 16 - Prob. 16.10P
Ch. 16 - Prob. 16.11PCh. 16 - Prob. 16.12PCh. 16 - Prob. 16.13PCh. 16 - Prob. 16.14PCh. 16 - Prob. 16.15PCh. 16 - Prob. 16.16PCh. 16 - Prob. 16.17PCh. 16 - Prob. 16.18PCh. 16 - Prob. 16.19PCh. 16 - Prob. 16.20PCh. 16 - Prob. 16.21PCh. 16 - Prob. 16.22PCh. 16 - Prob. 16.23PCh. 16 - Prob. 16.24PCh. 16 - Prob. 16.25PCh. 16 - Prob. 16.26PCh. 16 - Prob. 16.27PCh. 16 - Prob. 16.28PCh. 16 - Prob. 16.29PCh. 16 - Prob. 16.30PCh. 16 - Prob. 16.31PCh. 16 - Prob. 16.32PCh. 16 - Prob. 16.33PCh. 16 - Prob. 16.34PCh. 16 - Prob. 16.35PCh. 16 - Prob. 16.36PCh. 16 - Prob. 16.37PCh. 16 - Prob. 16.38PCh. 16 - Prob. 16.39PCh. 16 - Prob. 16.40PCh. 16 - Prob. 16.41PCh. 16 - Prob. 16.42PCh. 16 - Prob. 16.43PCh. 16 - Prob. 16.44PCh. 16 - Prob. 16.45PCh. 16 - Prob. 16.46PCh. 16 - Prob. 16.47PCh. 16 - Prob. 16.48PCh. 16 - Prob. 16.49PCh. 16 - Prob. 16.50PCh. 16 - Prob. 16.51PCh. 16 - Prob. 16.52PCh. 16 - Prob. 16.53PCh. 16 - Prob. 16.54PCh. 16 - Prob. 16.55PCh. 16 - Prob. 16.56PCh. 16 - Prob. 16.57PCh. 16 - Prob. 16.58PCh. 16 - Prob. 16.59PCh. 16 - Prob. 16.60PCh. 16 - Prob. 16.61PCh. 16 - Prob. 16.62PCh. 16 - Prob. 16.63PCh. 16 - Prob. 16.64PCh. 16 - Prob. 16.65PCh. 16 - Prob. 16.66PCh. 16 - Prob. 16.67PCh. 16 - Prob. 16.68PCh. 16 - Prob. 16.69PCh. 16 - Prob. 16.70PCh. 16 - Prob. 16.71PCh. 16 - Prob. 16.72PCh. 16 - Prob. 16.73PCh. 16 - Prob. 16.74PCh. 16 - Prob. 16.75PCh. 16 - Prob. 16.76PCh. 16 - Prob. 16.77PCh. 16 - Prob. 16.78PCh. 16 - Prob. 16.79PCh. 16 - Prob. 16.80PCh. 16 - Prob. 16.81PCh. 16 - Prob. 16.82PCh. 16 - Prob. 16.83PCh. 16 - Prob. 16.84PCh. 16 - Prob. 16.85PCh. 16 - Prob. 16.86PCh. 16 - Prob. 16.87PCh. 16 - Prob. 16.88PCh. 16 - Prob. 16.89PCh. 16 - Prob. 16.1YTCh. 16 - Prob. 16.2YTCh. 16 - Prob. 16.3YTCh. 16 - Prob. 16.4YTCh. 16 - Prob. 16.5YTCh. 16 - Prob. 16.6YTCh. 16 - Prob. 16.7YTCh. 16 - Prob. 16.8YTCh. 16 - Prob. 16.9YTCh. 16 - Prob. 16.10YTCh. 16 - Prob. 16.11YTCh. 16 - Prob. 16.12YTCh. 16 - Prob. 16.13YTCh. 16 - Prob. 16.14YTCh. 16 - Prob. 16.15YTCh. 16 - Prob. 16.16YTCh. 16 - Prob. 16.17YTCh. 16 - Prob. 16.18YTCh. 16 - Prob. 16.19YTCh. 16 - Prob. 16.20YTCh. 16 - Prob. 16.21YTCh. 16 - Prob. 16.22YTCh. 16 - Prob. 16.23YTCh. 16 - Prob. 16.24YTCh. 16 - Prob. 16.25YTCh. 16 - Prob. 16.26YTCh. 16 - Prob. 16.27YTCh. 16 - Prob. 16.28YTCh. 16 - Prob. 16.29YTCh. 16 - Prob. 16.30YTCh. 16 - Prob. 16.31YTCh. 16 - Prob. 16.32YTCh. 16 - Prob. 16.33YTCh. 16 - Prob. 16.34YT
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Predict the characteristic infrared absorptions of the functional groups in the following molecules. (f) pentanoic acid (g) pentanenitrilearrow_forwardIdentify functional groups in the following Fourier Transform Infra-Red (FTIR) spectra for the given chemical structures. Write your answer in the box.arrow_forwardExplain why TMS has a lower chemical shift than its carbon analog, dimethylpropane, (CH3)4C.arrow_forward
- You are given two compounds, dimethylamine (CH3)2NH and ethanamide, CH3CONH2. a) b) c) Which compound is more basic? Explain your answer. How do you distinguish them by infrared spectroscopy? Outline an extraction method to separate a mixture of these two compounds.arrow_forwardIn Section 6.2d, we saw that the pK, of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base. UV-vis spectroscopy can be used to measure the relative concentrations involved if the acid or conjugate base absorbs UV-vis light. With this in mind, suppose that a particular acid has a Amax of 312 nm. The figure here shows the absorbance at that wavelength as a function of pH. What is the pk, of the acid? 3 4 6 7 8 10 11 12 pH Absorbance at 312 nmarrow_forward(b) Estimate the 1H chemical shift for HB of 2-indanol and HA of 1-indanol. Is one more downfield than the other or are they expected to be similar? Explain your answer.arrow_forward
- A common lab experiment is the dehydration of cyclohexanol to cyclohexene.(a) Explain how you could tell from the IR spectrum whether your product was pure cyclohexene, pure cyclohexanol,or a mixture of cyclohexene and cyclohexanol. Give approximate frequencies for distinctive peaks.arrow_forwardPredict the approximate chemical shifts of the protons in the following compounds. (a) benzene (b) cyclohexanearrow_forwardBy examining the carbon NMR spectra of 1,1-dichlorocyclohexane and cis-1,2- dichlorocyclohexane, what TWO things would you look for to distinguish between the spectra. Use structures to explain your answer.arrow_forward
- Can ypu explain to me why the answer is letter C.arrow_forwardThe longest wavelength electronic transition in simple unsaturated hydrocarbons corresponds to a transition from the highest occupied molecular orbita l (HOMO) to the lowest unoccupied molecular orbita l (LUMO) . Predict the energy of the HOMO to LUMO separation in (a) ethane. (b) butadiene. and (c) benzene.arrow_forwardLook at the three infrared spectra in Figures C to D and answer the following questions (a) Are any of the spectra that of an alcohol? If so, which? What absorption pattern(s) at what wavelength(s) identifies an alcohol? (b) Are any of the spectra that of a compound containing a benzene ring? If so, which? What three absorption patterns at what wavelengths show that a compound has a benzene ring? (c) Are any of the spectra that of a compound containing only carbons and hydrogens? If so, which? Benzene rings contain only carbons and hydrogens. Might the spectrum or spectra you chose for your answer above indicate a benzene ring? (Tell what absorption patterns are present or not present that would support your answer.)arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physical ChemistryChemistryISBN:9781133958437Author:Ball, David W. (david Warren), BAER, TomasPublisher:Wadsworth Cengage Learning,
Physical Chemistry
Chemistry
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Wadsworth Cengage Learning,