Chapter 16, Problem 10A

(a)

Interpretation Introduction

Interpretation:

The conjugate base of ${\text{HCO}}_{\text{3}}{}^{\text{-}}$ is to be written.

Concept Introduction:

The conjugate base is the compound that is formed by the loosing of a proton.

Take an example of the conjugate base is ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ .

Answer to Problem 10A

The conjugate base of ${\text{HCO}}_{\text{3}}{}^{\text{-}}$ is ${\text{CO}}_{\text{4}}{}^{\text{-2}}$ .

Explanation of Solution

The given ion ${\text{HCO}}_{\text{3}}{}^{\text{-}}$ has one negative charge. So, the conjugate base of ${\text{HCO}}_{\text{3}}{}^{\text{-}}$ ion is formed by losing one hydrogen ion.

  ${\text{HCO}}_{\text{3}}{}^{\text{-}}\to {\text{CO}}_{\text{3}}{}^{\text{-2}}\text{+}{\text{H}}^{{}^{\text{+}}}$

(b)

Interpretation Introduction

Interpretation:

The conjugate base of ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ is to be written.

Concept Introduction:

The conjugate base is the compound that is formed by the loosing of a proton.

Answer to Problem 10A

The conjugate base of ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ is ${\text{HPO}}_{\text{4}}{}^{\text{-2}}$ .

Explanation of Solution

The given ion ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ has one negative charge. The conjugate base is formed by the removal of hydrogen ion. So, the conjugate base of ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}$ is ${\text{HPO}}_{\text{4}}{}^{\text{-2}}$ .

  ${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}{}^{\text{-}}\to {\text{HPO}}_{\text{4}}{}^{\text{-2}}{\text{+H}}^{\text{+}}$

(c)

Interpretation Introduction

Interpretation:

The conjugate base of $\text{HCl}$ is to be written.

Concept Introduction:

The conjugate base is the compound that is formed by the loosing of a proton.

Answer to Problem 10A

The conjugate base of $\text{HCl}$ is ${\text{Cl}}^{\text{-}}$ .

Explanation of Solution

  $\text{HCl}$ is a compound that forms a conjugate base by the removal of hydrogen ion.

  $\text{HCl}\to {\text{Cl}}^{\text{-1}}{\text{+H}}^{\text{+}}$

(d)

Interpretation Introduction

Interpretation:

The conjugate base of ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ is to be written.

Concept Introduction:

The conjugate base is the compound that is formed by the loosing of the proton.

Answer to Problem 10A

The conjugate base of ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ is ${\text{SO}}_{\text{4}}{}^{\text{-2}}$ .

Explanation of Solution

The given ion ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ has one negative charge. So, the conjugate base of this ion is formed by removing the hydrogen ion. The conjugate base of ${\text{HSO}}_{\text{4}}{}^{\text{-}}$ is ${\text{SO}}_{\text{4}}{}^{\text{-2}}$ .

  ${\text{HSO}}_{\text{4}}{}^{\text{-1}}\to {\text{SO}}_{\text{4}}{}^{\text{-2}}\text{+}{\text{H}}^{\text{+}}$