Sometimes evaluating a surface integral results in an improper integral. When this happens, one can either attempt to determine the value of the integral using an appropriate limit or one can try another method. These exercises explore both approaches. Consider the integral of f x , y , z = z + 1 over the upper hemisphere σ : z = 1 − x 2 − y 2 0 ≤ x 2 + y 2 ≤ 1 . (a) Explain why evaluating this surface integral using (8) results in an improper integral. (b) Use (8) to evaluate the integral of f over the surface σ r : z = 1 − x 2 − y 2 0 ≤ x 2 + y 2 ≤ r 2 < 1 . Take the limit of this result as r → 1 − to determine the integral of f over σ . (c) Parametrize σ using spherical coordinates and evaluate the integral of f over σ using (6). Verify that your answer agrees with the result in part (b).
Sometimes evaluating a surface integral results in an improper integral. When this happens, one can either attempt to determine the value of the integral using an appropriate limit or one can try another method. These exercises explore both approaches. Consider the integral of f x , y , z = z + 1 over the upper hemisphere σ : z = 1 − x 2 − y 2 0 ≤ x 2 + y 2 ≤ 1 . (a) Explain why evaluating this surface integral using (8) results in an improper integral. (b) Use (8) to evaluate the integral of f over the surface σ r : z = 1 − x 2 − y 2 0 ≤ x 2 + y 2 ≤ r 2 < 1 . Take the limit of this result as r → 1 − to determine the integral of f over σ . (c) Parametrize σ using spherical coordinates and evaluate the integral of f over σ using (6). Verify that your answer agrees with the result in part (b).
Sometimes evaluating a surface integral results in an improper integral. When this happens, one can either attempt to determine the value of the integral using an appropriate limit or one can try another method. These exercises explore both approaches.
Consider the integral of
f
x
,
y
,
z
=
z
+
1
over the upper hemisphere
σ
:
z
=
1
−
x
2
−
y
2
0
≤
x
2
+
y
2
≤
1
.
(a) Explain why evaluating this surface integral using (8) results in an improper integral.
(b) Use (8) to evaluate the integral of f over the surface
σ
r
:
z
=
1
−
x
2
−
y
2
0
≤
x
2
+
y
2
≤
r
2
<
1
.
Take the limit of this result as
r
→
1
−
to determine the integral of f over
σ
.
(c) Parametrize
σ
using spherical coordinates and evaluate the integral of f over
σ
using (6). Verify that your answer agrees with the result in part (b).
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Please solve and explain into details for me to understand. Thank you!
(a) Let f(z) =
---2i)(24 – 23)
Using CRT, evaluate the integral Of(2)dz, where the contour
C is the circle z-i+ 1| = 2.
Evaluate the line integral using Green's Theorem and check the answer by evaluating it directly.
3 y dx + 5x²dy, where Cis the square with vertices (0, 0), (3, 0), (3, 3), and (0, 3) oriented counterclockwise.
3y'dx + 5x°dy:
i
Calculus, Single Variable: Early Transcendentals (3rd Edition)
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