Algebra and Trigonometry: Structure and Method, Book 2
Algebra and Trigonometry: Structure and Method, Book 2
2000th Edition
ISBN: 9780395977255
Author: MCDOUGAL LITTEL
Publisher: McDougal Littell
bartleby

Concept explainers

Addition Rule of Probability
It simply refers to the likelihood of an event taking place whenever the occurrence of an event is uncertain. The probability of a single event can be calculated by dividing the number of successful trials of that event by the total number of trials.
Expected Value
When a large number of trials are performed for any random variable ‘X’, the predicted result is most likely the mean of all the outcomes for the random variable and it is known as expected value also known as expectation. The expected value, also known …
Probability Distributions
Understanding probability is necessary to know the probability distributions. In statistics, probability is how the uncertainty of an event is measured. This event can be anything. The most common examples include tossing a coin, rolling a die, or choosi…
Basic Probability
The simple definition of probability it is a chance of the occurrence of an event. It is defined in numerical form and the probability value is between 0 to 1. The probability value 0 indicates that there is no chance of that event occurring and the prob…
bartleby

Videos

Question
Book Icon
Chapter 15.10, Problem 8WE

(a)

To determine

To find:The probability of both card are jacks.

(a)

Expert Solution
Check Mark

Answer to Problem 8WE

The probability of both card are jacks 1221 .

Explanation of Solution

Given information:

The given information is two cards are drawn at the same time from a 52 card-deck.

Calculation:

Two cards are drawn at random from a 52 -card deck at the same time.

We find the probability that both cards are jacks.

There are 4 jacks in a standard deck of 52 cards. The probability that a card drawn is jack is thus

  P(First card is Jack)=4C152C1P(First card is Jack)=452P(First card is Jack)=113

Two cards are drawn at the same time the first card is not replaced. So there are now 3 Jacks and 51 cards in total Hence the probability that the second card is a jack is given by:

  P(second card is Jack)=3C151C1P(second card is Jack)=351P(second card is Jack)=117

Hence the probability that both cards are jacks is given by

  P(both card is Jack)=113×117P(both card is Jack)=1221

Therefore, the probability of both card are jacks 1221 .

(b)

To determine

To find:The probability of both card are sixes.

(b)

Expert Solution
Check Mark

Answer to Problem 8WE

The probability of both card are sixes 1221 .

Explanation of Solution

Given information:

The given information is two cards are drawn at the same time from a 52 card-deck.

Calculation:

We find the probability that both cards are sixes. There are 4 shoes in a standard deck of 52 cards. The probability that the first card drawn is six is thus given by

  P(First card is six)=4C152C1P(First card is six)=452P(First card is six)=113

Two cards are drawn at the same time the first card is not replaced. So there are now 3 six and 51 cards in total Hence the probability that the second card is a jack is given by:

  P(second card is six)=3C151C1P(second card is six)=351P(second card is six)=117

Hence the probability that both cards are sixes is given by

  P(both card is sixes)=113×117P(both card is sixes)=1221

Therefore, the probability of both card are sixes 1221 .

(c)

To determine

To find:The probability of either both card are jacks or both card are sixes.

(c)

Expert Solution
Check Mark

Answer to Problem 8WE

The probability of both card are jacks or both card are sixes 2221 .

Explanation of Solution

Given information:

The given information istwo cards are drawn at the same time from a 52 card-deck.

Calculation:

We find the probability that either both cards are jacks or both are sixes. The event that both cards are jacks and the event that both cards are sixes are mutually exclusive. Hence the probability that either both cards are jacks or both are sixes is given by:

  P(both cards are jacks or both are sixes)=P(First card is jacks)+P(First card is sixes)P(both cards are jacks or both are sixes)=1221+1221P(both cards are jacks or both are sixes)=2221

Therefore, the probability of both card are jacks or both card are sixes 2221 .

Previous
Chapter 15.10, Problem 7WE
Next
Chapter 15.10, Problem 9WE

Chapter 15 Solutions

Algebra and Trigonometry: Structure and Method, Book 2

Ch. 15.1 - Prob. 1OECh. 15.1 - Prob. 2OECh. 15.1 - Prob. 3OECh. 15.1 - Prob. 4OECh. 15.1 - Prob. 5OECh. 15.1 - Prob. 6OECh. 15.1 - Prob. 7OECh. 15.1 - Prob. 8OECh. 15.1 - Prob. 1WECh. 15.1 - Prob. 2WE
Ch. 15.1 - Prob. 3WECh. 15.1 - Prob. 4WECh. 15.1 - Prob. 5WECh. 15.1 - Prob. 6WECh. 15.1 - Prob. 7WECh. 15.1 - Prob. 8WECh. 15.1 - Prob. 9WECh. 15.1 - Prob. 10WECh. 15.1 - Prob. 11WECh. 15.1 - Prob. 12WECh. 15.1 - Prob. 13WECh. 15.1 - Prob. 14WECh. 15.1 - Prob. 15WECh. 15.1 - Prob. 16WECh. 15.1 - Prob. 17WECh. 15.1 - Prob. 18WECh. 15.1 - Prob. 1MRECh. 15.1 - Prob. 2MRECh. 15.1 - Prob. 3MRECh. 15.1 - Prob. 4MRECh. 15.1 - Prob. 5MRECh. 15.1 - Prob. 6MRECh. 15.2 - Prob. 1OECh. 15.2 - Prob. 2OECh. 15.2 - Prob. 3OECh. 15.2 - Prob. 4OECh. 15.2 - Prob. 5OECh. 15.2 - Prob. 6OECh. 15.2 - Prob. 7OECh. 15.2 - Prob. 8OECh. 15.2 - Prob. 9OECh. 15.2 - Prob. 10OECh. 15.2 - Prob. 11OECh. 15.2 - Prob. 12OECh. 15.2 - Prob. 13OECh. 15.2 - Prob. 14OECh. 15.2 - Prob. 1WECh. 15.2 - Prob. 2WECh. 15.2 - Prob. 3WECh. 15.2 - Prob. 4WECh. 15.2 - Prob. 5WECh. 15.2 - Prob. 6WECh. 15.2 - Prob. 7WECh. 15.2 - Prob. 8WECh. 15.2 - Prob. 9WECh. 15.2 - Prob. 10WECh. 15.2 - Prob. 11WECh. 15.2 - Prob. 12WECh. 15.2 - Prob. 13WECh. 15.2 - Prob. 14WECh. 15.2 - Prob. 15WECh. 15.2 - Prob. 16WECh. 15.2 - Prob. 17WECh. 15.2 - Prob. 18WECh. 15.2 - Prob. 19WECh. 15.2 - Prob. 20WECh. 15.3 - Prob. 1OECh. 15.3 - Prob. 2OECh. 15.3 - Prob. 3OECh. 15.3 - Prob. 4OECh. 15.3 - Prob. 5OECh. 15.3 - Prob. 6OECh. 15.3 - Prob. 1WECh. 15.3 - Prob. 2WECh. 15.3 - Prob. 3WECh. 15.3 - Prob. 4WECh. 15.3 - Prob. 5WECh. 15.3 - Prob. 6WECh. 15.3 - Prob. 7WECh. 15.3 - Prob. 8WECh. 15.3 - Prob. 9WECh. 15.3 - Prob. 10WECh. 15.3 - Prob. 11WECh. 15.3 - Prob. 12WECh. 15.3 - Prob. 1MRECh. 15.3 - Prob. 2MRECh. 15.3 - Prob. 3MRECh. 15.3 - Prob. 4MRECh. 15.3 - Prob. 5MRECh. 15.3 - Prob. 6MRECh. 15.4 - Prob. 1OECh. 15.4 - Prob. 2OECh. 15.4 - Prob. 3OECh. 15.4 - Prob. 1WECh. 15.4 - Prob. 2WECh. 15.4 - Prob. 3WECh. 15.4 - Prob. 4WECh. 15.4 - Prob. 5WECh. 15.4 - Prob. 6WECh. 15.4 - Prob. 7WECh. 15.4 - Prob. 8WECh. 15.4 - Prob. 9WECh. 15.4 - Prob. 10WECh. 15.4 - Prob. 11WECh. 15.4 - Prob. 12WECh. 15.4 - Prob. 13WECh. 15.4 - Prob. 1STCh. 15.4 - Prob. 2STCh. 15.4 - Prob. 3STCh. 15.4 - Prob. 4STCh. 15.4 - Prob. 5STCh. 15.4 - Prob. 6STCh. 15.5 - Prob. 1OECh. 15.5 - Prob. 2OECh. 15.5 - Prob. 3OECh. 15.5 - Prob. 4OECh. 15.5 - Prob. 1WECh. 15.5 - Prob. 2WECh. 15.5 - Prob. 3WECh. 15.5 - Prob. 4WECh. 15.5 - Prob. 5WECh. 15.5 - Prob. 6WECh. 15.5 - Prob. 7WECh. 15.5 - Prob. 8WECh. 15.5 - Prob. 9WECh. 15.5 - Prob. 10WECh. 15.5 - Prob. 11WECh. 15.5 - Prob. 12WECh. 15.5 - Prob. 13WECh. 15.5 - Prob. 14WECh. 15.5 - Prob. 15WECh. 15.5 - Prob. 16WECh. 15.5 - Prob. 17WECh. 15.5 - Prob. 18WECh. 15.5 - Prob. 19WECh. 15.5 - Prob. 20WECh. 15.5 - Prob. 1MRECh. 15.5 - Prob. 2MRECh. 15.5 - Prob. 3MRECh. 15.5 - Prob. 4MRECh. 15.5 - Prob. 5MRECh. 15.5 - Prob. 6MRECh. 15.5 - Prob. 7MRECh. 15.5 - Prob. 8MRECh. 15.6 - Prob. 1OECh. 15.6 - Prob. 2OECh. 15.6 - Prob. 3OECh. 15.6 - Prob. 4OECh. 15.6 - Prob. 5OECh. 15.6 - Prob. 6OECh. 15.6 - Prob. 7OECh. 15.6 - Prob. 8OECh. 15.6 - Prob. 9OECh. 15.6 - Prob. 10OECh. 15.6 - Prob. 11OECh. 15.6 - Prob. 12OECh. 15.6 - Prob. 1WECh. 15.6 - Prob. 2WECh. 15.6 - Prob. 3WECh. 15.6 - Prob. 4WECh. 15.6 - Prob. 5WECh. 15.6 - Prob. 6WECh. 15.6 - Prob. 7WECh. 15.6 - Prob. 8WECh. 15.6 - Prob. 9WECh. 15.6 - Prob. 10WECh. 15.6 - Prob. 11WECh. 15.6 - Prob. 12WECh. 15.6 - Prob. 13WECh. 15.6 - Prob. 14WECh. 15.6 - Prob. 15WECh. 15.6 - Prob. 16WECh. 15.6 - Prob. 17WECh. 15.6 - Prob. 18WECh. 15.6 - Prob. 19WECh. 15.6 - Prob. 20WECh. 15.6 - Prob. 21WECh. 15.6 - Prob. 22WECh. 15.6 - Prob. 23WECh. 15.6 - Prob. 24WECh. 15.6 - Prob. 25WECh. 15.6 - Prob. 26WECh. 15.6 - Prob. 27WECh. 15.6 - Prob. 28WECh. 15.6 - Prob. 29WECh. 15.6 - Prob. 30WECh. 15.6 - Prob. 31WECh. 15.7 - Prob. 1OECh. 15.7 - Prob. 2OECh. 15.7 - Prob. 3OECh. 15.7 - Prob. 4OECh. 15.7 - Prob. 5OECh. 15.7 - Prob. 6OECh. 15.7 - Prob. 7OECh. 15.7 - Prob. 1WECh. 15.7 - Prob. 2WECh. 15.7 - Prob. 3WECh. 15.7 - Prob. 4WECh. 15.7 - Prob. 5WECh. 15.7 - Prob. 6WECh. 15.7 - Prob. 7WECh. 15.7 - Prob. 8WECh. 15.7 - Prob. 9WECh. 15.7 - Prob. 10WECh. 15.7 - Prob. 11WECh. 15.7 - Prob. 12WECh. 15.7 - Prob. 13WECh. 15.7 - Prob. 14WECh. 15.7 - Prob. 15WECh. 15.7 - Prob. 16WECh. 15.7 - Prob. 17WECh. 15.7 - Prob. 18WECh. 15.7 - Prob. 19WECh. 15.7 - Prob. 20WECh. 15.7 - Prob. 21WECh. 15.7 - Prob. 22WECh. 15.7 - Prob. 23WECh. 15.7 - Prob. 24WECh. 15.7 - Prob. 25WECh. 15.7 - Prob. 26WECh. 15.7 - Prob. 27WECh. 15.7 - Prob. 28WECh. 15.7 - Prob. 29WECh. 15.7 - Prob. 30WECh. 15.7 - Prob. 1MRECh. 15.7 - Prob. 2MRECh. 15.7 - Prob. 3MRECh. 15.7 - Prob. 4MRECh. 15.7 - Prob. 5MRECh. 15.7 - Prob. 6MRECh. 15.7 - Prob. 7MRECh. 15.7 - Prob. 8MRECh. 15.7 - Prob. 9MRECh. 15.7 - Prob. 10MRECh. 15.7 - Prob. 11MRECh. 15.7 - Prob. 12MRECh. 15.7 - Prob. 1CECh. 15.7 - Prob. 2CECh. 15.7 - Prob. 3CECh. 15.7 - Prob. 4CECh. 15.7 - Prob. 5CECh. 15.7 - Prob. 1STCh. 15.7 - Prob. 2STCh. 15.7 - Prob. 3STCh. 15.7 - Prob. 4STCh. 15.7 - Prob. 5STCh. 15.7 - Prob. 6STCh. 15.8 - Prob. 1OECh. 15.8 - Prob. 2OECh. 15.8 - Prob. 1WECh. 15.8 - Prob. 2WECh. 15.8 - Prob. 3WECh. 15.8 - Prob. 4WECh. 15.8 - Prob. 5WECh. 15.8 - Prob. 6WECh. 15.8 - Prob. 7WECh. 15.8 - Prob. 8WECh. 15.8 - Prob. 9WECh. 15.8 - Prob. 10WECh. 15.8 - Prob. 11WECh. 15.8 - Prob. 12WECh. 15.8 - Prob. 13WECh. 15.8 - Prob. 14WECh. 15.8 - Prob. 15WECh. 15.8 - Prob. 16WECh. 15.9 - Prob. 1OECh. 15.9 - Prob. 2OECh. 15.9 - Prob. 3OECh. 15.9 - Prob. 4OECh. 15.9 - Prob. 5OECh. 15.9 - Prob. 6OECh. 15.9 - Prob. 7OECh. 15.9 - Prob. 8OECh. 15.9 - Prob. 9OECh. 15.9 - Prob. 10OECh. 15.9 - Prob. 11OECh. 15.9 - Prob. 1WECh. 15.9 - Prob. 2WECh. 15.9 - Prob. 3WECh. 15.9 - Prob. 4WECh. 15.9 - Prob. 5WECh. 15.9 - Prob. 6WECh. 15.9 - Prob. 7WECh. 15.9 - Prob. 8WECh. 15.9 - Prob. 9WECh. 15.9 - Prob. 10WECh. 15.9 - Prob. 11WECh. 15.9 - Prob. 12WECh. 15.9 - Prob. 13WECh. 15.9 - Prob. 14WECh. 15.9 - Prob. 1MRECh. 15.9 - Prob. 2MRECh. 15.9 - Prob. 3MRECh. 15.9 - Prob. 4MRECh. 15.9 - Prob. 5MRECh. 15.9 - Prob. 6MRECh. 15.9 - Prob. 7MRECh. 15.9 - Prob. 8MRECh. 15.9 - Prob. 1CECh. 15.9 - Prob. 2CECh. 15.9 - Prob. 3CECh. 15.9 - Prob. 4CECh. 15.9 - Prob. 5CECh. 15.9 - Prob. 6CECh. 15.9 - Prob. 1.1ECh. 15.9 - Prob. 1.2ECh. 15.9 - Prob. 1.3ECh. 15.9 - Prob. 1.4ECh. 15.9 - Prob. 1.5ECh. 15.9 - Prob. 1.6ECh. 15.9 - Prob. 2.1ECh. 15.9 - Prob. 2.2ECh. 15.9 - Prob. 2.3ECh. 15.9 - Prob. 2.4ECh. 15.9 - Prob. 2.5ECh. 15.9 - Prob. 2.6ECh. 15.9 - Prob. 2.7ECh. 15.9 - Prob. 2.8ECh. 15.10 - Prob. 1OECh. 15.10 - Prob. 2OECh. 15.10 - Prob. 3OECh. 15.10 - Prob. 4OECh. 15.10 - Prob. 5OECh. 15.10 - Prob. 1WECh. 15.10 - Prob. 2WECh. 15.10 - Prob. 3WECh. 15.10 - Prob. 4WECh. 15.10 - Prob. 5WECh. 15.10 - Prob. 6WECh. 15.10 - Prob. 7WECh. 15.10 - Prob. 8WECh. 15.10 - Prob. 9WECh. 15.10 - Prob. 10WECh. 15.10 - Prob. 11WECh. 15.10 - Prob. 12WECh. 15.10 - Prob. 13WECh. 15.10 - Prob. 14WECh. 15.10 - Prob. 15WECh. 15.10 - Prob. 16WECh. 15.10 - Prob. 17WECh. 15.10 - Prob. 1STCh. 15.10 - Prob. 2STCh. 15.10 - Prob. 3STCh. 15.10 - Prob. 1ECh. 15.10 - Prob. 2ECh. 15 - Prob. 1CRCh. 15 - Prob. 2CRCh. 15 - Prob. 3CRCh. 15 - Prob. 4CRCh. 15 - Prob. 5CRCh. 15 - Prob. 6CRCh. 15 - Prob. 7CRCh. 15 - Prob. 8CRCh. 15 - Prob. 9CRCh. 15 - Prob. 10CRCh. 15 - Prob. 11CRCh. 15 - Prob. 12CRCh. 15 - Prob. 1CTCh. 15 - Prob. 2CTCh. 15 - Prob. 3CTCh. 15 - Prob. 4CTCh. 15 - Prob. 5CTCh. 15 - Prob. 6CTCh. 15 - Prob. 7CTCh. 15 - Prob. 8CTCh. 15 - Prob. 9CTCh. 15 - Prob. 10CTCh. 15 - Prob. 11CT

Additional Math Textbook Solutions

Find more solutions based on key concepts
Solve each formula for the given letter . [2.3] What percent of 60 is 42? [2.4]

Elementary and Intermediate Algebra: Concepts and Applications (7th Edition)

Find the area of the parallelogram defined by [37] and [82] .

Linear Algebra with Applications (2-Download)

In each of Exercises 21–30, draw a linear graph to represent the given information. Be sure to label and number...

Elementary Algebra: Concepts and Applications (10th Edition)

Problems For Problems 9-12, determine two linearly independent power series solutions to the given differential...

Differential Equations and Linear Algebra (4th Edition)

Express the number -3 in terms of i.

College Algebra (5th Edition)

Practice Exercises In Exercises 1—20, find all numbers for which each rational expression is undefined. If th...

Introductory and Intermediate Algebra for College Students (5th Edition)

Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Text book image
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Text book image
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Text book image
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
Text book image
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
SEE MORE TEXTBOOKS
Probability & Statistics (28 of 62) Basic Definitions and Symbols Summarized; Author: Michel van Biezen;https://www.youtube.com/watch?v=21V9WBJLAL8;License: Standard YouTube License, CC-BY
Introduction to Probability, Basic Overview - Sample Space, & Tree Diagrams; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=SkidyDQuupA;License: Standard YouTube License, CC-BY