(a)
Interpretation:
The mass of the indicated solute in the given solution is to be calculated.
Concept Introduction:
The
The number of moles is calculated by the formula,
The molarity is calculated by the formula,
Answer to Problem 46QAP
The mass of the indicated solute in
Explanation of Solution
It is given that
The conversion of units of volume into
The molar mass of
The number of moles of a solute is calculated by the formula,
Substitute the values of volume of solution and molarity of
The mass of
Substitute the values of molar mass and number of moles of
Therefore, the mass of the indicated solute in
(b)
Interpretation:
The mass of the indicated solute in the given solution is to be calculated.
Concept Introduction:
The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.
The number of moles is calculated by the formula,
The molarity is calculated by the formula,
Answer to Problem 46QAP
The mass of the indicated solute in
Explanation of Solution
It is given that
The conversion of units of volume into
The molar mass of
The number of moles of a solute is calculated by the formula,
Substitute the values of volume of solution and molarity of
The mass of
Substitute the values of molar mass and number of moles of
Therefore, the mass of the indicated solute in
(c)
Interpretation:
The mass of the indicated solute in the given solution is to be calculated.
Concept Introduction:
The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.
The number of moles is calculated by the formula,
The molarity is calculated by the formula,
Answer to Problem 46QAP
The mass of the indicated solute in
Explanation of Solution
It is given that
The conversion of units of volume into
The molar mass of
The number of moles of a solute is calculated by the formula,
Substitute the values of volume of solution and molarity of
The mass of
Substitute the values of molar mass and number of moles of
Therefore, the mass of the indicated solute in
(d)
Interpretation:
The mass of the indicated solute in the given solution is to be calculated.
Concept Introduction:
The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.
The number of moles is calculated by the formula,
The molarity is calculated by the formula,
Answer to Problem 46QAP
The mass of the indicated solute in
Explanation of Solution
It is given that
The conversion of units of volume into
The molar mass of
The number of moles of a solute is calculated by the formula,
Substitute the values of volume of solution and molarity of
The mass of
Substitute the values of molar mass and number of moles of
Therefore, the mass of the indicated solute in
Want to see more full solutions like this?
Chapter 15 Solutions
EBK INTRODUCTORY CHEMISTRY
- 34. For each of the following solutions, the number of moles of solute is given, followed by the total volume of the solution prepared. Calculate the molarity of each solution. a. 0.754 mol KNO; 225 mL b. 0.0105 in of CaCl; 10.2 mL c. 3.15 mol NaCl; 5.00 L d. 0.499 mol NaBr; 100. mLarrow_forward3.64 How many grams of solute are present in each of these solutions? (a) 37.2 mL ofO.471 M HBr (b) 113.0 L of 1.43 M Na2CO3 (c) 212 mL of 6.8 M CH3COOH (d) 1.3 × 10-4 L of 1.03 M H2S03arrow_forwardWhat mass of solid NaOH (97.0% NaOH by mass) is required to prepare 1.00 L of a 10.0% solution of NaOH by mass? The density of the 10.0% solution is 1.109 g/mL.arrow_forward
- What mass of a 4.00% NaOH solution by mass contains 15.0 g of NaOH?arrow_forwardWhat is the difference between a solute and a solvent?arrow_forward3.65 Determine the final molarity for the following dilutions. (a) 24.5 mL of 3.0 M solution diluted to 100.0 mL (b) 15.3 mL of 4.22 M solution diluted to 1.00 L (c) 1.45 mL of 0.034 M solution diluted to 10.0 mL (d) 2.35 L of 12.5 M solution diluted to 100.0 Larrow_forward
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning