(a)
To find: the probability that the researcher is detained for further testing.
(a)
Answer to Problem 41E
20%
Explanation of Solution
Given:
The police are taking the right decision 80% of the time, it implies that 20% of the time they are taking the wrong decision. Therefore, the probability that detained even though you have not been drinking is 20%
(b)
To find: the probability that any mention driver would be detained.
(b)
Answer to Problem 41E
27.2%
Explanation of Solution
Given:
Calculation:
There are two
P {driver is sober and police take wrong choice}
P (driver is drunk and police make right choice)
Therefore, the probability that a driver is detained is 17.6% + 9.6% = 27.2%
(c)
To find: the probability that a driver who is detained has actually been drinking.
(c)
Answer to Problem 41E
35.29%
Explanation of Solution
Given:
Calculation:
Knowing that P (driver is drunk | driver is detained), that is, the probability that the driver is drunk mention that he is detained.
(d)
To find: the probability that a driver who was released had actually been drinking.
(d)
Answer to Problem 41E
3.30%
Explanation of Solution
Given:
Calculation:
P (driver is drunk and driver was released)
So P(driver is drunk | driver was released) =2.4% / 72.8% = 3.30%
Chapter 15 Solutions
Stats: Modeling the World Nasta Edition Grades 9-12
Additional Math Textbook Solutions
STATS:DATA+MODELS-W/DVD
Introductory Statistics (2nd Edition)
Essentials of Statistics, Books a la Carte Edition (5th Edition)
Statistics for Psychology
Elementary Statistics: Picturing the World (7th Edition)
Elementary Statistics Using Excel (6th Edition)
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