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Biological Science, Books a la Carte Plus Mastering Biology with Pearson eText -- Access Card Package (6th Edition)
6th Edition
ISBN: 9780134296029
Author: Scott Freeman, Kim Quillin, Lizabeth Allison, Michael Black, Greg Podgorski, Emily Taylor, Jeff Carmichael
Publisher: PEARSON
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Chapter 15, Problem 13PIAT
Ciprofloxacin inhibits DNA gyrase, a bacterial topoisomerase that cuts DNA ahead of the replication fork, winds the DNA in a direction that relieves the twists added during DNA synthesis, and then reseals the DNA. In ciprofloxacin-treated bacteria, newly synthesized DNA is found in fragments. Based on this evidence, what activity of DNA gyrase is likely to be inhibited by ciprofloxacin?
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All known DNA polymerases catalyze synthesis only in the 5' → 3' direction. Nevertheless, during semiconservative DNA replication in the cell, they are able to catalyze the synthesis of both daughter chains, which would appear to require synthesis in the 3' → 5' direction on one strand. Explain the process that occurs in the cell that allows for synthesis of both daughter chains by DNA polymerase
Many of the gene products involved in DNA synthesis were initially defined by studying mutant E. coli strains that could not synthesize DNA. (a) The dnaE gene encodes the a subunit of DNA polymerase III. What effect is expected from a mutation in this gene? How could the mutant strain be maintained? (b) The dnaQ gene encodes the e subunit of DNA polymerase. What effect is expected from a mutation in this gene?
Human Fbh1 helicase is important in the process of DNA replication. When a mutation occurs during the production of Fbh1, the result is a mutant Fbh1 that binds at the replication fork and prevents any helicase protein from attaching to the strand.
Based on this information and the image shown, what would happen during DNA replication if this mutant helicase were present?
A - Topoisomerase would unwind the DNA and an RNA primer would attach to the DNA molecule and initiate replication. The process would then stop at the blue triangle because helicase is needed to separate the strands of DNA.
B - Topoisomerase would unwind the DNA, but then the process would stop at the blue triangle because helicase, the RNA primer, would not be able to attach to the DNA molecule and initiate replication.
C - The process would begin at the blue triangle when topoisomerase unwinds the DNA and an RNA primer attaches to the DNA molecule and initiates replication. DNA polymerase would begin the synthesis…
Chapter 15 Solutions
Biological Science, Books a la Carte Plus Mastering Biology with Pearson eText -- Access Card Package (6th Edition)
Ch. 15 - 1. Which of the following is not a property of DNA...Ch. 15 - 2. What is the function of primase?
a. synthesis...Ch. 15 - 3. How are Okazaki fragments synthesized?
a. using...Ch. 15 - Prob. 4TYKCh. 15 - PROCESS OF SCIENCE Researchers design experiments...Ch. 15 - Prob. 6TYUCh. 15 - 7. How does telomerase prevent linear chromosomes...Ch. 15 - Prob. 8TYUCh. 15 - 9. MODEL In the late 1950s, Herbert Taylor grew...Ch. 15 - Prob. 10TYPSS
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- There are two types of excision repair, base excision repair (BER) and nucleotide excision repair (NER). Which enzymes are used in Base excision repair in E. coli?And In nucleotide excision repair, what kind of damage is repaired by this mechanism and why are cutsmade on both sides of the damaged region of DNA?arrow_forwardDepurination of purine bases results in an apurinic site. Assume a single depurination event occurs in the GC base pair of the sequence below and is not repaired. Then, if two rounds of replication occur, which of the following DNA sequences will exist after two rounds of replication? Remember that when DNA polymerases encounter an apurinic site, most often an A is incorporated into the newly synthesized strand. Assume this is true for the sequence below. ...TACT... ...ATGA... Â Question 7 Select one or more: a) ...TAGT... ...ATCA... b) ...TACT... ...ATGA... c)...TAAT... ...ATTA... d) ...TAAT... ...AT_A... . e) ...TA_T... ...ATAA... f)...TATT... ...ATAA...arrow_forwardDepurination of purine bases results in an apurinic site. Assume a single depurination event occurs in the GC base pair of the sequence below and is not repaired. Then, if two rounds of replication occur, which of the following DNA sequences will exist after two rounds of replication? Remember that when DNA polymerases encounter an apurinic site, most often an A is incorporated into the newly synthesized strand. Assume this is true for the sequence below. ...TACT... ...ATGA... Â Question 7 Select one or more: ...TAGT... ...ATCA... 1. ...TACT... ...ATGA... 2. ...TAAT... ...ATTA... 3. ...TAAT... ...AT_A... 4. ...TA_T... ...ATAA... 5. ...TATT... ...ATAA...arrow_forward
- In the following sequence, a cytosine was deaminated and is now a uracil (underlined). 5’-GGTAUTAAGC-3’ a. Which repair pathway(s) could restore this uracil to cytosine? b. If the uracil is not removed before a DNA replication fork passes through, what will be the sequences of the two resulting double helices? Provide the sequences of both strands of both helices. Label the old and new strands and underline the mutation(s). c. Could the mismatch repair pathway fix the mutations you’ve indicated in part b? d. If the cell undergoes mitosis, and the replicated DNAs are distributed into the two daughter cells. Will 0, 1, or 2 daughter cells have a mutation in this sequence?arrow_forwardDuring template-directed synthesis of a new DNA strand it can happen, if there are simple repeated sequences, that either the template strand or the strand being synthesized "slips" a short distance, and this can change the number of repeating sequence units in that stretch of repeated sequence. Which of the following processes involve such slippage? More than one answer is correct. Options:  The increase in genomic copy number of a DNA transposon by transposition from a location behind a replication fork to a location ahead of the fork.  Introduction of indels during DNA replication.  The initial unwinding of the DNA duplex during replication by helicase.  Increasing lengths of CAG trinucleotide repeats in the huntingtin gene giving rise to Huntington disease.  Synthesis of primer by primase during DNA replication.arrow_forwardYou examine DNA replication in an E. coli mutant, which has a partially defective DNA polymerase. In vitro experiments using the mutant DNA polymerase gives an error rate of 10-3, as compared to the expected error rate of 10-6. Which of the following activities is the mutant polymerase likely to be missing, as compared to the normal polymerase? Explain your answer.arrow_forward
- In the scenario where a single strand break occurs in the DNA replication fork: a) What would happen if RecC failed to bind to the chi site? Explain briefly and draw out the step at which recombinational DNA repair would stall. b) What would happen if RecA failed to bind DNA? Explain briefly and draw out the step at which recombinational DNA repair would stall. c) Draw the resolved product of this Holliday junction if it's cleaved in the direction of the white triangles. Is the result a heteroplex or recombinant? A Strand Invasion Ⓒ Holliday Junction A Resolvearrow_forwardDuring DNA replication in E. coli, which enzyme forms the phosphodiester bond between an RNA primer and the first incoming deoxyribonucleotide for an Okazaki fragment on the lagging strand? topoisomerase DNA polymerase III DNA helicase DNA polymerase II DNA ligase Heterogeneous nuclear RNA is typically characterized by which of the following features? it is more common in prokaryotes than in eukaryotes it contains introns, but no exons it contains more exons than introns it contains exons, but no introns it contains more introns than exonsarrow_forwardAdenylate cydase, which synthesizes cyclic AMP from ATP, requires two metal ions, and the enzyme has the same constellation of amino acid residues in the active site as does DNA polymerase I. In what sense is the adenylate cyclase reaction similar to that of DNA polymerase, and in what sense is it different?arrow_forward
- Which of the following statements regarding Nucleotide Excision Repair (NER) and Base Excision Repair (BER) is true?  Only NER involves the action of DNA ligase to seal nicks in the DNA backbone. Both NER and BER involve DNA strand cleavage by an endonuclease.  Both NER and BER can be activated by exposure to visible light. Only BER requires DNA polymerase.  Both NER and BER involve the creation of an apyrimidinic (AP) site.arrow_forwardA temperature-sensitive mutation is one in which the defect is not presented functionally until the temperature is raised. In the case described below, the enzymes function normally in bacteria at 37 °C, but are non-functional at 40 °C. Predict the detailed molecular consequences of a loss of function in a temperature-sensitive mutant for each of the following enzymes: a) DNA gyrase, b) DNA polymerase III, c) DNA ligase, d) DNA polymerase I.arrow_forwardYou are studying a colony of cells and determine that some of these cells have a mutated DNA polymerase I that results in loss of function of this enzyme. A)  What will the effect of the mutation in DNA polymerase I be on DNA replication? In your answer make sure to describe what would be observed in the leading and lagging strand and explain your reasoning. B)  Will this mutation in DNA polymerase I have an impact on another step in DNA replication? In your answer make sure to indicate whether DNA replication will be impacted or not. If it is not, explain why. If it is impacted, then describe the step that is impacted and name the molecule or enzyme involved.arrow_forward
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