Chapter 14.4, Problem 23PPS

To determine

To find:the dimensions of the billiard table.

Answer to Problem 23PPS

  $8ft,4ft$

Explanation of Solution

Given:

The perimeter ofbilliard table is $24ft$ .

And the length is twice as its width.

Calculation:

Let the width of therectangular billiard tablebe $x$ .

According to the question,length is twice as its width.

Therefore, length is $l=2x$ .

As the perimeter of billiard tableis $2\left(l+w\right)$ .

Therefore,

  $\begin{array}{l}2\left(l+w\right)=24\\ \Rightarrow 2\left(2x+x\right)=24\\ 3x=12\left\{\text{divide both side by 7}\right\}\\ \therefore x=4\end{array}$

Thus, the length is $l=2\times 4=8ft$

Hence, the dimensions are $8ft,4ft$ .