Explanation Given Information: The arithmetic series, ∑ j = 1 10 ( 6 − j ) Formula used: The sum ( S n ) of first n terms of an arithmetic progression is, S n = n 2 ( a 1 + a n ) Here, a 1 and a n are first and n th term of the arithmetic progression. Calculation: Consider the arithmetic series, ∑ j = 1 10 ( 6 − j ) To find the value of a 1 Take j = 1 , Then, a 1 = 6 − j = 6 − 1 =

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ISBN: 9781259616754

Author: Julie Miller, Molly O'Neill, Nancy Hyde

Publisher: McGraw-Hill Education

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Chapter 14.3, Problem 58PE

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To calculate: The sum of the arithmetic series, ∑j=110(6−j).

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Chapter 14.3, Problem 57PE

Chapter 14.3, Problem 59PE

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Chapter 14 Solutions

Beginning and Intermediate Algebra

Ch. 14.1 - Prob. 1SP Ch. 14.1 - Prob. 2SP Ch. 14.1 - Evaluate the expressions. 3. 1! Ch. 14.1 - Prob. 4SP Ch. 14.1 - Prob. 5SP Ch. 14.1 - Prob. 6SP Ch. 14.1 - Write out the first three terms of ( x + y ) 5 .Ch. 14.1 - 8. Use the binomial theorem to expand . Ch. 14.1 - Use the binomial theorem to expand ( 2 a − 3 b 2 )...Ch. 14.1 - Find the fourth term of ( x + y ) 8 .

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The sum of the arithmetic series, ∑ j = 1 10 ( 6 − j ) .

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To calculate: The sum of the arithmetic series, ∑j=110(6−j).

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Chapter 14 Solutions