Chapter 14.3, Problem 33WE

To determine

To find: The polar graph of given polar equation.

Answer to Problem 33WE

  

Explanation of Solution

Given information:

An equation in polar coordinate is given as $r=1+\sin \theta$ .

Concepts used: Conversion formula for coordinate systems are given as-

1. From polar to rectangular:

  $x=r\cos \theta$

  $y=r\sin \theta$

2. From rectangular to polar:

  $r^2=x^2+y^2\Rightarrow r=\pm \sqrt{x^2+y^2}$

  $\cos \theta =\frac{x}{r}$ ; $\sin \theta =\frac{y}{r}$ ; $\tan \theta =\frac{x}{y}$ .

Calculation:

Given equation in polar-coordinate is $r=1+\sin \theta$ .

Constructing a table for $\theta$ .

$\theta$	$r=1+\sin \theta$
$0^0$	$1$
${30}^0$	$\frac{3}{2}$
${60}^0$	$\frac{2+\sqrt{3}}{2}$
${90}^0$	$2$
${120}^0$	$\frac{2+\sqrt{3}}{2}$
${150}^0$	$\frac{3}{2}$
${180}^0$	$1$
${210}^0$	$\frac{1}{2}$
${240}^0$	$\frac{2-\sqrt{3}}{2}$
${270}^0$	$0$
${300}^0$	$\frac{2-\sqrt{3}}{2}$
${330}^0$	$\frac{1}{2}$
${360}^0$	$1$

Plotting graph as below.