Chapter 14.2, Problem 17PPS

To determine

To solve the given expression

Answer to Problem 17PPS

  $5b^2+4a^2+4b+a-1$

Explanation of Solution

Given information:

  $(b^2+a+7-2b)+(4a^2+6b+4b^2-8)$

Formula used: Polynomial addition

Calculation:

  $(b^2+a+7-2b)+(4a^2+6b+4b^2-8)$

Opening the brackets,

  $=b^2+a+7-2b+4a^2+6b+4b^2-8$

Re-arranging the expression,

  $\begin{array}{l}=b^2+4b^2+4a^2+a+6b-2b+7-8\\ =5b^2+4a^2+4b+a-1\end{array}$