Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 14.12, Problem 61AAP
To determine
The electrical resistivity of a silver wire.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A wire of radius 1 mm and conductivity 5x [10] ^7 S/m if an electric field of 5
mV/m is applied. Determine the current in the wire *
0.943
0.628
0.785
O 0.393
Your answer is partially correct.
The ammonia molecule NH3 has a permanent electric dipole moment equal to 1.47 D, where 1 D-1 debye unit-3.34 x 10-30 C-m.
Calculate the electric potential in volts due to an ammonia molecule at a point 46.7 nm away along the axis of the dipole. (Set V-0 at
infinity.)
Number
2.26E-5
Units V
The accepted resistivity value at room temperature for copper wire is 1.7421 x 10-8 ohm meter. please explain why or why not the measurements recorded are within some percent error of thius value. calculate resistivity and show the percent error. Use R=p L/A
Using the formula calculate p
Chapter 14 Solutions
Foundations of Materials Science and Engineering
Ch. 14.12 - Describe the classic model for electrical...Ch. 14.12 - Prob. 2KCPCh. 14.12 - Prob. 3KCPCh. 14.12 - Prob. 4KCPCh. 14.12 - Prob. 5KCPCh. 14.12 - Define the following quantities pertaining to the...Ch. 14.12 - Prob. 7KCPCh. 14.12 - What structural defects contribute to the residual...Ch. 14.12 - Prob. 9KCPCh. 14.12 - Prob. 10KCP
Ch. 14.12 - Prob. 11KCPCh. 14.12 - Prob. 12KCPCh. 14.12 - Prob. 13KCPCh. 14.12 - Prob. 14KCPCh. 14.12 - Prob. 15KCPCh. 14.12 - Prob. 16KCPCh. 14.12 - Prob. 17KCPCh. 14.12 - Prob. 18KCPCh. 14.12 - Prob. 19KCPCh. 14.12 - Prob. 20KCPCh. 14.12 - Prob. 21KCPCh. 14.12 - Prob. 22KCPCh. 14.12 - Prob. 23KCPCh. 14.12 - Prob. 24KCPCh. 14.12 - Prob. 25KCPCh. 14.12 - Prob. 26KCPCh. 14.12 - Prob. 27KCPCh. 14.12 - Describe the movement of the majority and minority...Ch. 14.12 - Prob. 29KCPCh. 14.12 - Prob. 30KCPCh. 14.12 - What is a zener diode? How does this device...Ch. 14.12 - Prob. 32KCPCh. 14.12 - Prob. 33KCPCh. 14.12 - Prob. 34KCPCh. 14.12 - Prob. 35KCPCh. 14.12 - Describe how the planar bipolar transistor can...Ch. 14.12 - Prob. 37KCPCh. 14.12 - Prob. 38KCPCh. 14.12 - Prob. 39KCPCh. 14.12 - Prob. 40KCPCh. 14.12 - Prob. 41KCPCh. 14.12 - Prob. 42KCPCh. 14.12 - Prob. 43KCPCh. 14.12 - Prob. 44KCPCh. 14.12 - Prob. 45KCPCh. 14.12 - Prob. 46KCPCh. 14.12 - Prob. 47KCPCh. 14.12 - Prob. 48KCPCh. 14.12 - Prob. 49KCPCh. 14.12 - Prob. 50KCPCh. 14.12 - Prob. 51KCPCh. 14.12 - Prob. 52KCPCh. 14.12 - Prob. 53KCPCh. 14.12 - What are ferroelectric domains? How can they be...Ch. 14.12 - Prob. 55KCPCh. 14.12 - Prob. 56KCPCh. 14.12 - What are the PZT piezoelectric materials? In what...Ch. 14.12 - Prob. 58AAPCh. 14.12 - Prob. 59AAPCh. 14.12 - Prob. 60AAPCh. 14.12 - Prob. 61AAPCh. 14.12 - Prob. 62AAPCh. 14.12 - Prob. 63AAPCh. 14.12 - Prob. 64AAPCh. 14.12 - Prob. 65AAPCh. 14.12 - Prob. 66AAPCh. 14.12 - Prob. 67AAPCh. 14.12 - Prob. 68AAPCh. 14.12 - Prob. 69AAPCh. 14.12 - Prob. 70AAPCh. 14.12 - Phosphorus is added to make an n-type silicon...Ch. 14.12 - Prob. 72AAPCh. 14.12 - A silicon wafer is doped with 2.50 1016 boron...Ch. 14.12 - A silicon wafer is doped with 2.50 1015...Ch. 14.12 - Prob. 75AAPCh. 14.12 - Prob. 76AAPCh. 14.12 - Prob. 77AAPCh. 14.12 - What fabrication techniques are used to encourage...Ch. 14.12 - Prob. 79AAPCh. 14.12 - Prob. 80AAPCh. 14.12 - Calculate the intrinsic electrical conductivity of...Ch. 14.12 - Prob. 82AAPCh. 14.12 - Prob. 83AAPCh. 14.12 - Prob. 85AAPCh. 14.12 - Prob. 86AAPCh. 14.12 - Prob. 87AAPCh. 14.12 - Prob. 88AAPCh. 14.12 - Prob. 89AAPCh. 14.12 - Prob. 90AAPCh. 14.12 - Prob. 91AAPCh. 14.12 - Prob. 92SEPCh. 14.12 - Prob. 93SEPCh. 14.12 - Design a p-type semiconductor based on Si that...Ch. 14.12 - Prob. 95SEPCh. 14.12 - Prob. 96SEPCh. 14.12 - Prob. 97SEPCh. 14.12 - Prob. 98SEPCh. 14.12 - Prob. 99SEPCh. 14.12 - Prob. 100SEP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 1. What is the total flux passing through a 10 cm x 6 cm surface in a region where the electric flux density is 2700 µC/m? ? [1.62 x 105 C]arrow_forwardEngineering science Distinguish elastic, electrical and magnetic hysteresis in different Materials.arrow_forward4. Fermi-Dirac statistics Develop an Excel sheet to numerically calculate the numbers of electrons with energies above the Fermi energy level EF = 5.5 eV in silver at 300 K and 1000 K, assuming EF does not change with temperature. m mm marrow_forward
- A charged nonconducting rod, with a length of 2.52 m and a cross-sectional area of 4.76 cm², lies along the positive side of an x axis with one end at the origin. The volume charge density p is charge per unit volume in coulombs per cubic meter. How many excess electrons are on the rod if p is (a) uniform, with a value of -4.66 µC/m³, and (b) nonuniform, with a value given by p= bx², where b = -2.18 µC/m²? (a) Number i (b) Number i Units Unitsarrow_forwardM4.25 (Sl units) What is the resistance R of a length of copper wire whose length 10 m and whose diameter 0.30 mm? Use Table 4.3 of the book for reference. Round to the nearest thousandth of an ohm ()arrow_forwardThe free charge density in copper is 1.81x1010 C/m 3 . For a current density of 8x106A/m2, solve the electric field intensity and the drift velocity.Look at the table for more information.arrow_forward
- 1. The resistivity of aluminum is 2.8 x 10-8 Nm. How long (in meters) a piece of aluminum wire 1.0 mm diameter is needed to give a resistance of 4.0 0?arrow_forwardIf the number density of electrons in a wire is n = 1.00 × 1028 m-3, at what drift velocity must they travel through a wire of diameter d = 0.520 mm to deliver a current of 2.90 A? Give your answer in mm s-1 to 3 significant figures. Take π = 3.14, and the magnitude of the charge on an electron e = 1.60 × 10-¹⁹ C Drift velocity: mm s-1arrow_forwardA rod of semiconducting material of lenght L=3 m and cross-sectional area A=4.5 mm^2 lies along the x-axis between x=0 and x=L. The material obeys ohm's law, and resistivity varies along the rod according to p=p0 (1-(x^2/L^2)) where p0= 4.10^-4 ohm.m. The end of the rod x=0 is at a potential V0=30V greater than the x=L. A) what is the total resistance, in units of ohm, of the rod? B) what is the current, in units of miliamperes, in the rod? C) what is the electric potential, in units of Volt, in the rod at x=L/2? D) what is the electic-field magnitude E, in units of V/m, in the rod at x=L/2?arrow_forward
- An ideal capacitor with a capacitance of 90.0 nF is charged up to a voltage of 3.00 V. (i) Calculate the magnitude of charge stored in the capacitor. (ii) Determine the potential energy stored in the capacitor. (iii) The capacitor is disconnected from the battery and is then inserted with a piece of mica of which the dielectric constant is 5.00. Compare the final potential energy to the initial potential energy in the capacitor.arrow_forwardIf 5.8x1020 electrons are deposited on the positive plate of a capacitor by applied voltage of 40V, find the capacitance of the capacitor? (Analysis)arrow_forwardYou are given a number of 32 Q resistors, each capable of dissipating only 1.8 W without being destroyed. What is the minimum number of such resistors that you need to combine in series or in parallel to make a 32 Q resistance that is capable of dissipating at least 14.0 W? Number i Unitsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Understanding Motor ControlsMechanical EngineeringISBN:9781337798686Author:Stephen L. HermanPublisher:Delmar Cengage Learning
Understanding Motor Controls
Mechanical Engineering
ISBN:9781337798686
Author:Stephen L. Herman
Publisher:Delmar Cengage Learning
Dislocations and Plastic Deformation; Author: LearnChemE;https://www.youtube.com/watch?v=cpvTwYAUeA8;License: Standard Youtube License