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Calculus
- Existence. Integrate the function f(x, y) = 1/(1 - x²- y²) over the disk x²+ y² ≤ 3/4. Does the integral of f(x, y) exist over the disk x²+ y² ≤ 1? Justify your answer.arrow_forwardCurrent Attempt in Progress Locate the centroid of the shaded area. Set b = 0.30 a. b Answer: x=0(1-2²) a (x, y) = (i x ) aarrow_forwardDetermine the x- and y-coordinates of the centroid of the shaded area. y = 1+ -x - 1 2.arrow_forward
- The figure shows the sales growth rates under different levels of distribution and advertising from a to b. Set up an integral to determine the extra sales growth if $3 million is used in advertising rather than $2 million. (Use f for f(x), g for g(x), and h for h(x).) $4 Million advertising $3 Million 8 advertising $2 Million h advertising b Distribution - h dx Sales Growth Ratearrow_forwardPractice with tabular integration Evaluate the following inte- grals using tabular integration (refer to Exercise 77). a. fre dx b. J7xe* de d. (x – 2x)sin 2r dx с. | 2r² – 3x - dx x² + 3x + 4 f. е. dx (x – 1)3 V2r + 1 g. Why doesn't tabular integration work well when applied to dx? Evaluate this integral using a different 1 x² method.arrow_forwardUsing Green's Theorem, find the outward flux of F across the closed curve C.F = (-5x + 2y) i + (6x - 9y) j; C is the region bounded above by y = -5x 2 + 250 and below by y=5x2 in the first quadrantarrow_forward
- Evaluating Polar Integrals In Exercises 9-22, change the Cartesian integral into an equivalent polar integral. Then evaluate the polar integral. μl pV²-3² 11 12. Jo Jo ra I √a²-x² тугилау dy dx JOJOarrow_forwardUsing the method of u-substitution, 5 [²(2x - 7)² de where U = du: = a = b = f(u) = = ·b [ f(u) du a It (enter a function of x) da (enter a function of ä) (enter a number) (enter a number) (enter a function of u). The value of the original integral is 9.arrow_forwardUsing the method of u-substitution, | (32 – 8)² dz = | f(u) du - where u = (enter a function of æ) du = da (enter a function of ¤) a = (enter a number) b = (enter a number) f(u) = (enter a function of u). The value of the original integral isarrow_forward
- Evaluate the line integral using Green's Theorem and check the answer by evaluating it directly. $ 5 y dx + 5 x²dy, where Cis the square with vertices (0, 0), (2, 0), (2, 2), and (0, 2) oriented counterclockwise. + iarrow_forwardpint Evaluate the double integral I ry dA where D is the triangular region with vertices (0,0), (5, 0), (0, 5).arrow_forward) Using Green's theorem, convert the line integral f.(6y² dx + 2xdy) to a double integral, where C is the boundary of the square with vertices ±(2, 2) and ±(2,-2). ( do not evaluate the integral)arrow_forward
- Calculus For The Life SciencesCalculusISBN:9780321964038Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.Publisher:Pearson Addison Wesley,