Elementary Statistics ( 3rd International Edition ) Isbn:9781260092561
3rd Edition
ISBN: 9781259969454
Author: William Navidi Prof.; Barry Monk Professor
Publisher: McGraw-Hill Education
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Chapter 14.1, Problem 23E
Artificial hips: Using the data in Exercise 21, perform the Tukey-Kramer test to determine which pairs of means, if any, differ. Use the
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Application Exercise:
Dr. Mussey used a measure to classify children as showing some form of learning disorder. She also examined
school records and noted which were enrolled in a remedial Math. Below is the contingency table of the data.
What can be concluded with an a of 0.01?
Remedial
Disorder
yes
no
none
23
78
dyslexia
25
75
ADHD
20
20
T) What is the appropriate test statistic?
--Select-
Compute the statistic selected in a):
U Obtain/compute the appropriate values to make a decision about Ho.
Critical Value =
; Test Statistic =
Decision: ---Select-
v Compute the corresponding effect size(s) and indicate magnitude(s).
If not appropriate, input and/or select "na" below.
Effect Size =
; Magnitude: --Select--
wMake an interpretation based on the results.
O There is a significant relationship between learning disorder and the school.
O There is a significant learning disorder difference in remedial Math.
O There is no relationship between learning disorder and remedial Math.
Pls specify everything all conditions and all step.
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Chapter 14 Solutions
Elementary Statistics ( 3rd International Edition ) Isbn:9781260092561
Ch. 14.1 - In Exercises 7 and 8, fill in each blank with the...Ch. 14.1 - Prob. 8ECh. 14.1 - Prob. 9ECh. 14.1 - Prob. 10ECh. 14.1 - Prob. 11ECh. 14.1 - Prob. 12ECh. 14.1 - In a one-way ANOVA, the following data were...Ch. 14.1 - In a one-way ANOVA, the following data were...Ch. 14.1 - Samples were drawn from three populations. The...Ch. 14.1 - Samples were drawn from three populations. The...
Ch. 14.1 - Pesticide danger: One of the factors that...Ch. 14.1 - Life-saving drug: Penicillin is produced by the...Ch. 14.1 - Pesticide danger: Using the data in Exercise 17,...Ch. 14.1 - Life-saving drug: Using the data in Exercise 18,...Ch. 14.1 - Artificial hips: Artificial hip joints consist of...Ch. 14.1 - Floods: Rapid drainage of floodwater is crucial to...Ch. 14.1 - Artificial hips: Using the data in Exercise 21,...Ch. 14.1 - Floods: Using the data in Exercise 22, perform the...Ch. 14.1 - Polluting power plants: Power plants can emit...Ch. 14.1 - Prob. 26ECh. 14.1 - Prob. 27ECh. 14.1 - Prob. 28ECh. 14.1 - Prob. 29ECh. 14.1 - Prob. 30ECh. 14.1 - Prob. 31ECh. 14.2 - Prob. 5ECh. 14.2 - Prob. 6ECh. 14.2 - Prob. 7ECh. 14.2 - Prob. 8ECh. 14.2 - In a two-way ANOVA, the P-value for interactions...Ch. 14.2 - Prob. 10ECh. 14.2 - Prob. 11ECh. 14.2 - Prob. 12ECh. 14.2 - Prob. 13ECh. 14.2 - Prob. 14ECh. 14.2 - Prob. 15ECh. 14.2 - Prob. 16ECh. 14.2 - Prob. 17ECh. 14.2 - Prob. 18ECh. 14.2 - Prob. 19ECh. 14.2 - Prob. 20ECh. 14.2 - Prob. 21ECh. 14.2 - Prob. 22ECh. 14.2 - Prob. 23ECh. 14.2 - Strong beams: The following table presents...Ch. 14.2 - Prob. 25ECh. 14.2 - Prob. 26ECh. 14.2 - Fruit yields: An agricultural scientist performed...Ch. 14.2 - Prob. 28ECh. 14.2 - Prob. 29ECh. 14 - Exercises 1-4 refer to the following data: At a...Ch. 14 - Prob. 2CQCh. 14 - Prob. 3CQCh. 14 - Prob. 4CQCh. 14 - Prob. 5CQCh. 14 - Prob. 6CQCh. 14 - Prob. 7CQCh. 14 - Prob. 8CQCh. 14 - Prob. 9CQCh. 14 - Prob. 10CQCh. 14 - Prob. 1RECh. 14 - Prob. 2RECh. 14 - Prob. 3RECh. 14 - Prob. 4RECh. 14 - Prob. 5RECh. 14 - Prob. 6RECh. 14 - Prob. 7RECh. 14 - Prob. 8RECh. 14 - Prob. 9RECh. 14 - Prob. 10RECh. 14 - Prob. 11RECh. 14 - Prob. 12RECh. 14 - Prob. 13RECh. 14 - Prob. 14RECh. 14 - Prob. 15RECh. 14 - Prob. 1WAICh. 14 - Prob. 2WAICh. 14 - Prob. 3WAICh. 14 - Prob. 4WAICh. 14 - Prob. 5WAICh. 14 - Prob. 1CSCh. 14 - Prob. 2CSCh. 14 - Prob. 3CSCh. 14 - Prob. 4CS
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- What is an experiment? Give two examples.arrow_forwardFor the following exercises, assume two die are rolled. 47. Construct a table showing the sample space.arrow_forwardt test for Independent Means. Professor Wolinsky hypothesizes that type of TV show impacts people’s mood. To study this, she uses two groups: the experimental group who watches reality TV shows for three hours, while the control group watches the news for three hours. Each of the groups then completes an assessment of mood. In all, 32 people participate: 17 watch reality TV shows and 15 watch the news. The Mean, Sample Size, and SS for each group are below. Using these data, conduct a t test (p<.05) to determine if TV show type had an impact on an individual’s mood. Reality TV Shows: News: N = 17 N = 15 M = 34 M = 24 SS = 340 SS = 251 Step 1) Create a research hypothesis and a null hypothesis about the populations. Null hypothesis (H0): Research hypothesis (HA): Step 2) Determine the characteristics of the comparison distribution. Degrees of freedom for experimental group and control group =…arrow_forward
- Helparrow_forwardPls select the correct option and explain it...arrow_forwardDoes training in stress reduction make a difference for student success? 15 students received training (M1= 88, SS1= 400) and 15 students did not (M2= 82, SS2= 440). Test using α = .05 The correct APA format for the result would includearrow_forward
- Select all the studies where the explanatory variable is measured at the same time as the outcome variable. Clinical Trial Case-Control Cross-Sectional Cohort A survey where a large portion of those under the age of 25 in the sample did not answer the questions about drug use is an example of what type of bias? Selection Measurement Respone Non-Response When the population of interest is everyone in a high school, but only people who attend the sporting events are recruited into the sample, this is an example of what kind of bias? Selection Measurement Respone Non-Responsearrow_forwardhomework helparrow_forwardUSING A KRUSKAL-WALLIS NON-PARAMETRIC TEST , SOLVE AND INTERPRET IF THE NULL IS RETAIN OR REJECTEDJoana was insterested in the effects of five different kinds of drugs upon the mean time to complete a task.. She used 30 subjects and randomly assigned 6 of them to each drug The data represent the time in minutes to complete the task. Use a 1% level of significance to test that the population mean times to complete the task are the same with each drug. The data are given in the table.arrow_forward
- USING A KRUSKAL-WALLIS NON-PARAMETRIC TEST , SOLVE AND INTERPRET IF THE NULL IS RETAIN OR REJECTEDJoana was insterested in the effects of five different kinds of drugs upon the mean time to complete a task.. She used 30 subjects and randomly assigned 6 of them to each drug The data represent the time in minutes to complete the task. Use a 1% level of significance to test that the population mean times to complete the task are the same with each drug. The data are given in the table.arrow_forwardTask: A company's trainees are randomly assigned to groups which are taught a period they are tested for inspection performance quality. The following are their scores. Method A: 80, 83, 79, 85, 90, 68 Method B: 82, 84, 60, 72, 86, 67, 91 Method C: 93, 65, 77, 78, 88. Use the H test to determine at the 0.05 level of significance whether the three methods are equally effective.arrow_forwardOver the past few decades, public health officials have examined the link between weight concerns and teen girls' smoking. Researchers surveyed a group of 273 randomly selected teen girls living in Massachusetts (between 12 and 15 years old). After four years the girls were surveyed again. Sixty-three said they smoked to stay thin. Is there good evidence that more than thirty percent of the teen girls smoke to stay thin?After conducting the test, what are your decision and conclusion? Reject H0: There is sufficient evidence to conclude that less than 30% of teen girls smoke to stay thin. Do not reject H0: There is not sufficient evidence to conclude that less than 30% of teen girls smoke to stay thin. Reject H0: There is not sufficient evidence to conclude that more than 30% of teen girls smoke to stay thin. Reject H0: There is sufficient evidence to conclude that more than 30% of teen girls smoke to stay thin. Do not reject H0: There is not sufficient evidence to conclude that…arrow_forward
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