Chapter 1.4, Problem 62SPR

To determine

To calculate the distance between pair of points

Answer to Problem 62SPR

The distance between pair of points $d=4.27$ .

Round off to nearest hundred $d=0$ .

Explanation of Solution

Given information:

  $J(1,\frac{1}{4}),M(-3,\frac{7}{4})$

Formula used:

Distance formula

  $d=\sqrt{{(x2-x1)}^2+{(y2-y1)}^2}$

Calculation:

Applying the given formula,

  $d=\sqrt{{(x2-x1)}^2+{(y2-y1)}^2}$

Putting values,

  $x1=1,x2=-3,y1=\frac{1}{4},y2=\frac{7}{4}$

So,

  $d=\sqrt{{(5-(-5))}^2+{(\frac{2}{5}-\frac{8}{5})}^2}$

On solving,

  $d=\sqrt{{(-3-1)}^2+{(\frac{7}{4}-\frac{1}{4})}^2}$

So,

  $d=\sqrt{{(-4)}^2+{(\frac{6}{4})}^2}$

On squaring,

  $d=\sqrt{16+\frac{36}{16}}$

Taking least common factor,

  $d=\sqrt{\frac{256+36}{16}}$

On solving further,

  $d=\sqrt{\frac{292}{16}}$

Therefore,

  $d=\sqrt{18.25}$

So,

  $d=4.27$

Rounding off to nearest hundred.

  $d=0$