B + -tree: In this case, initially it is considered that the B + -tree is empty and the values are inserted in ascending order. It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values. The first two key values (2,3) get added to the root node.

Question

Want to see the full answer?

Answer 1

Question

Chapter 14, Problem 3PE

a)

Program Plan Intro

B⁺ -tree:

In this case, initially it is considered that the B⁺-tree is empty and the values are inserted in ascending order.

It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values.

The first two key values (2,3) get added to the root node.

b)

Explanation of Solution

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

c)

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

I want a database on MySQL to analyze blood disease analyses with a selection of all its commands, with an ER drawing, and a complete chart for normalization. I want them completely.

Assignment Instructions: You are tasked with developing a program to use city data from an online database and generate a city details report. 1) Create a new Project in Eclipse called "HW7". 2) Create a class "City.java" in the project and implement the UML diagram shown below and add comments to your program. 3) The logic for the method "getCityCategory" of City Class is below: a. If the population of a city is greater than 10000000, then the method returns "MEGA" b. If the population of a city is greater than 1000000 and less than 10000000, then the method returns "LARGE" c. If the population of a city is greater than 100000 and less than 1000000, then the method returns "MEDIUM" d. If the population of a city is below 100000, then the method returns "SMALL" 4) You should create another new Java program inside the project. Name the program as "xxxx_program.java”, where xxxx is your Kean username. 3) Implement the following methods inside the xxxx_program program The main method…

CPS 2231 - Computer Programming – Spring 2025 City Report Application - Due Date: Concepts: Classes and Objects, Reading from a file and generating report Point value: 40 points. The purpose of this project is to give students exposure to object-oriented design and programming using classes in a realistic application that involves arrays of objects and generating reports. Assignment Instructions: You are tasked with developing a program to use city data from an online database and generate a city details report. 1) Create a new Project in Eclipse called "HW7”. 2) Create a class "City.java" in the project and implement the UML diagram shown below and add comments to your program. 3) The logic for the method "getCityCategory" of City Class is below: a. If the population of a city is greater than 10000000, then the method returns "MEGA" b. If the population of a city is greater than 1000000 and less than 10000000, then the method returns "LARGE" c. If the population of a city is greater…

Answer 2

Question

Chapter 14, Problem 3PE

a)

Program Plan Intro

B⁺ -tree:

In this case, initially it is considered that the B⁺-tree is empty and the values are inserted in ascending order.

It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values.

The first two key values (2,3) get added to the root node.

b)

Explanation of Solution

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

c)

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 14, Problem 3PE

a)

Program Plan Intro

B⁺ -tree:

In this case, initially it is considered that the B⁺-tree is empty and the values are inserted in ascending order.

It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values.

The first two key values (2,3) get added to the root node.

b)

Explanation of Solution

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

c)

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 14, Problem 3PE

a)

Program Plan Intro

B⁺ -tree:

In this case, initially it is considered that the B⁺-tree is empty and the values are inserted in ascending order.

It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values.

The first two key values (2,3) get added to the root node.

b)

Explanation of Solution

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

c)

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 14, Problem 3PE

a)

Program Plan Intro

B⁺ -tree:

In this case, initially it is considered that the B⁺-tree is empty and the values are inserted in ascending order.

It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values.

The first two key values (2,3) get added to the root node.

b)

Explanation of Solution

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

c)

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...

Answer 6

Chapter 14, Problem 3PE

a)

Program Plan Intro

B⁺ -tree:

In this case, initially it is considered that the B⁺-tree is empty and the values are inserted in ascending order.

It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values.

The first two key values (2,3) get added to the root node.

Answer 7

Chapter 14, Problem 3PE

a)

Program Plan Intro

B⁺ -tree:

In this case, initially it is considered that the B⁺-tree is empty and the values are inserted in ascending order.

It is not possible to have a value less that n/2 as the non-root node and in this case the non-root node can only have 2-3 key values.

The first two key values (2,3) get added to the root node.

Answer 8

b)

Explanation of Solution

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

Answer 9

b)

Explanation of Solution

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

Answer 10

c)

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...

Answer 11

c)

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 14 - Prob. 1PE Ch. 14 - Prob. 2PE Ch. 14 - Prob. 3PE Ch. 14 - Prob. 4PE Ch. 14 - Prob. 5PE Ch. 14 - Prob. 7PE Ch. 14 - Prob. 8PE Ch. 14 - Prob. 9PE Ch. 14 - Prob. 10PE Ch. 14 - Prob. 11PE

Explanation of Solution

Next, when key value 7 is inserted in the tree; Root node now holds key value 7, and its first pointer points to a leaf node. The inserted leaf node contains the key value 2,3, and 5. As more key values are inserted, more leaf nodes are added as per requirement...

Explanation of Solution

The first four key values (2,3,5, and 7) are simply added to the root node. Next, when key value 11 is inserted in the tree; Root node now holds the key value 11, and its first pointer points to a leaf node. The inserted leaf node contains the key values 2,3,5, and 7...

Want to see the full answer?

Chapter 14 Solutions

Next, when key value 7 is inserted in the tree;

Root node now holds key value 7, and its first pointer points to a leaf node.

The inserted leaf node contains the key value 2,3, and 5.

As more key values are inserted, more leaf nodes are added as per requirement...

The first four key values (2,3,5, and 7) are simply added to the root node.

Next, when key value 11 is inserted in the tree;

Root node now holds the key value 11, and its first pointer points to a leaf node.

The inserted leaf node contains the key values 2,3,5, and 7...