(a) Answer The pair of congruent acute angles is ( ∠ A O B , ∠ H O G ) Explanation Given information: Formula used: Acute angles are angles which are less than 90°. Calculation: Consider the definition of Congruent Angles: Congruent angles are angles that have equal measures. Acute angles are angles which are less than 90°. Right angles are angles which are equal to 90°. Obtuse angles are angles which are greater than 90°. From the above figure it can be observe that ∠ AOB and ∠ HOG are both congruent acute angles since both measure 20° which are less than 90°, i.e. acute angles. Therefore, a pair or congruent acute angles is ( ∠ A O B , ∠ H O G ) Conclusion: A pair of congruent acute angles is ( ∠ A O B , ∠ H O G ) (b) To determine To obtain: The pair of congruent of right angles. Answer The pair of congruent right angles is ∠ AOC , ∠ COH Explanation Given information: Formula used: Right angles are angles which are equal to 90°. Calculation: From the above figure it can be observe that ∠ AOC , and ∠ COH are both congruent and right angles, i.e. both are 90°. Therefore, a pair of congruent right angles is ∠ AOC , ∠ COH Conclusion: The pair of congruent right angles is ∠ AOC , ∠ COH . (c) To determine To get: The pair of congruent of obtuse angles. Answer The pair or congruent obtuse angles is ( ∠ AOG, ∠ HOB ) Explanation Given information: Formula used: Obtuse angles are angles which are greater than 90°. Calculation: From the above figure it can be observing that ∠ AOG and ∠ H O B are both congruent and obtuse angles i.e. both measures 160° and are greater than 90°. Therefore, a pair of congruent obtuse angles is ( ∠ AOG, ∠ HOB ) Conclusion: The pair of congruent obtuse angles is ( ∠ AOG, ∠ HOB )

McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Videos

Question

Chapter 1.4, Problem 25CE

(a)

To determine

To find: The pair of congruent of acute angles.

(a)

Expert Solution

Answer to Problem 25CE

The pair of congruent acute angles is (∠AOB,∠HOG)

Explanation of Solution

Given information:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.4, Problem 25CE , additional homework tip 1

Formula used:

Acute angles are angles which are less than 90°.

Calculation:

Consider the definition of Congruent Angles:

Congruent angles are angles that have equal measures.

Acute angles are angles which are less than 90°.

Right angles are angles which are equal to 90°.

Obtuse angles are angles which are greater than 90°.

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.4, Problem 25CE , additional homework tip 2

From the above figure it can be observe that ∠AOB and ∠HOG are both congruent acute angles since both measure 20° which are less than 90°, i.e. acute angles.

Therefore, a pair or congruent acute angles is (∠AOB,∠HOG)

Conclusion:

A pair of congruent acute angles is (∠AOB,∠HOG)

(b)

To determine

To obtain: The pair of congruent of right angles.

(b)

Expert Solution

Answer to Problem 25CE

The pair of congruent right angles is ∠AOC,

∠COH

Explanation of Solution

Given information:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.4, Problem 25CE , additional homework tip 3

Formula used:

Right angles are angles which are equal to 90°.

Calculation:

From the above figure it can be observe that ∠AOC, and ∠COH are both congruent and right angles, i.e. both are 90°.

Therefore, a pair of congruent right angles is ∠AOC,

∠COH

Conclusion:

The pair of congruent right angles is ∠AOC,

∠COH .

(c)

To determine

To get: The pair of congruent of obtuse angles.

(c)

Expert Solution

Answer to Problem 25CE

The pair or congruent obtuse angles is (∠AOG,∠HOB)

Explanation of Solution

Given information:

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 1.4, Problem 25CE , additional homework tip 4

Formula used:

Obtuse angles are angles which are greater than 90°.

Calculation:

From the above figure it can be observing that ∠AOG and ∠HOB are both congruent and obtuse angles i.e. both measures 160° and are greater than 90°.

Therefore, a pair of congruent obtuse angles is (∠AOG,∠HOB)

Conclusion:

The pair of congruent obtuse angles is (∠AOG,∠HOB)

Chapter 1.4, Problem 24CE

Chapter 1.4, Problem 26CE

Chapter 1 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 1.1 - Prob. 1CE Ch. 1.1 - Prob. 2CE Ch. 1.1 - Prob. 3CE Ch. 1.1 - Prob. 4CE Ch. 1.1 - Prob. 5CE Ch. 1.1 - Prob. 6CE Ch. 1.1 - Prob. 7CE Ch. 1.1 - Prob. 8CE Ch. 1.1 - Prob. 1WE Ch. 1.1 - Prob. 2WE

Ch. 1.1 - Prob. 3WE Ch. 1.1 - Prob. 4WE Ch. 1.1 - Prob. 5WE Ch. 1.1 - Prob. 6WE Ch. 1.1 - Prob. 7WE Ch. 1.1 - Prob. 8WE Ch. 1.1 - Prob. 9WE Ch. 1.1 - Prob. 10WE Ch. 1.2 - Prob. 1CE Ch. 1.2 - Prob. 2CE Ch. 1.2 - Prob. 3CE Ch. 1.2 - Prob. 4CE Ch. 1.2 - Prob. 5CE Ch. 1.2 - Prob. 6CE Ch. 1.2 - Prob. 7CE Ch. 1.2 - Prob. 8CE Ch. 1.2 - Prob. 9CE Ch. 1.2 - Prob. 10CE Ch. 1.2 - Prob. 11CE Ch. 1.2 - Prob. 12CE Ch. 1.2 - Prob. 13CE Ch. 1.2 - Prob. 14CE Ch. 1.2 - Prob. 15CE Ch. 1.2 - Prob. 16CE Ch. 1.2 - Prob. 17CE Ch. 1.2 - Prob. 18CE Ch. 1.2 - Prob. 19CE Ch. 1.2 - Prob. 20CE Ch. 1.2 - Prob. 1WE Ch. 1.2 - Prob. 2WE Ch. 1.2 - Prob. 3WE Ch. 1.2 - Prob. 4WE Ch. 1.2 - Prob. 5WE Ch. 1.2 - Prob. 6WE Ch. 1.2 - Prob. 7WE Ch. 1.2 - Prob. 8WE Ch. 1.2 - Prob. 9WE Ch. 1.2 - Prob. 10WE Ch. 1.2 - Prob. 11WE Ch. 1.2 - Prob. 12WE Ch. 1.2 - Prob. 13WE Ch. 1.2 - Prob. 14WE Ch. 1.2 - Prob. 15WE Ch. 1.2 - Prob. 16WE Ch. 1.2 - Prob. 17WE Ch. 1.2 - Prob. 18WE Ch. 1.2 - Prob. 19WE Ch. 1.2 - Prob. 20WE Ch. 1.2 - Prob. 21WE Ch. 1.2 - Prob. 22WE Ch. 1.2 - Prob. 23WE Ch. 1.2 - Prob. 24WE Ch. 1.2 - Prob. 25WE Ch. 1.2 - Prob. 26WE Ch. 1.2 - Prob. 27WE Ch. 1.2 - Prob. 28WE Ch. 1.2 - Prob. 29WE Ch. 1.2 - Prob. 30WE Ch. 1.2 - Prob. 31WE Ch. 1.2 - Prob. 32WE Ch. 1.2 - Prob. 33WE Ch. 1.2 - Prob. 34WE Ch. 1.2 - Prob. 35WE Ch. 1.2 - Prob. 36WE Ch. 1.2 - Prob. 1ST1 Ch. 1.2 - Prob. 2ST1 Ch. 1.2 - Prob. 3ST1 Ch. 1.2 - Prob. 4ST1 Ch. 1.2 - Prob. 5ST1 Ch. 1.2 - Prob. 6ST1 Ch. 1.2 - Prob. 7ST1 Ch. 1.2 - Prob. 1AR Ch. 1.2 - Prob. 2AR Ch. 1.2 - Prob. 3AR Ch. 1.2 - Prob. 4AR Ch. 1.2 - Prob. 5AR Ch. 1.2 - Prob. 6AR Ch. 1.2 - Prob. 7AR Ch. 1.2 - Prob. 8AR Ch. 1.2 - Prob. 9AR Ch. 1.2 - Prob. 10AR Ch. 1.2 - Prob. 11AR Ch. 1.2 - Prob. 12AR Ch. 1.2 - Prob. 13AR Ch. 1.2 - Prob. 14AR Ch. 1.2 - Prob. 15AR Ch. 1.2 - Prob. 16AR Ch. 1.2 - Prob. 17AR Ch. 1.2 - Prob. 18AR Ch. 1.2 - Prob. 19AR Ch. 1.2 - Prob. 20AR Ch. 1.2 - Prob. 21AR Ch. 1.2 - Prob. 22AR Ch. 1.2 - Prob. 23AR Ch. 1.2 - Prob. 24AR Ch. 1.2 - Prob. 25AR Ch. 1.2 - Prob. 26AR Ch. 1.2 - Prob. 27AR Ch. 1.2 - 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Prob. 5WE Ch. 1.3 - Prob. 6WE Ch. 1.3 - Prob. 7WE Ch. 1.3 - Prob. 8WE Ch. 1.3 - Prob. 9WE Ch. 1.3 - Prob. 10WE Ch. 1.3 - Prob. 11WE Ch. 1.3 - Prob. 12WE Ch. 1.3 - Prob. 13WE Ch. 1.3 - Prob. 14WE Ch. 1.3 - Prob. 15WE Ch. 1.3 - Prob. 16WE Ch. 1.3 - Prob. 17WE Ch. 1.3 - Prob. 18WE Ch. 1.3 - Prob. 19WE Ch. 1.3 - Prob. 20WE Ch. 1.3 - Prob. 21WE Ch. 1.3 - Prob. 22WE Ch. 1.3 - Prob. 23WE Ch. 1.3 - Prob. 24WE Ch. 1.3 - Prob. 25WE Ch. 1.3 - Prob. 26WE Ch. 1.3 - Prob. 27WE Ch. 1.3 - Prob. 28WE Ch. 1.3 - Prob. 29WE Ch. 1.3 - Prob. 30WE Ch. 1.3 - Prob. 31WE Ch. 1.3 - Prob. 32WE Ch. 1.3 - Prob. 33WE Ch. 1.3 - Prob. 34WE Ch. 1.3 - Prob. 35WE Ch. 1.3 - Prob. 36WE Ch. 1.3 - Prob. 37WE Ch. 1.3 - Prob. 38WE Ch. 1.3 - Prob. 39WE Ch. 1.3 - Prob. 40WE Ch. 1.3 - Prob. 41WE Ch. 1.3 - Prob. 42WE Ch. 1.3 - Prob. 43WE Ch. 1.3 - Prob. 44WE Ch. 1.3 - Prob. 45WE Ch. 1.3 - Prob. 46WE Ch. 1.3 - Prob. 47WE Ch. 1.3 - Prob. 48WE Ch. 1.4 - Prob. 1CE Ch. 1.4 - Prob. 2CE Ch. 1.4 - Prob. 3CE Ch. 1.4 - Prob. 4CE Ch. 1.4 - Prob. 5CE Ch. 1.4 - Prob. 6CE Ch. 1.4 - Prob. 7CE Ch. 1.4 - Prob. 8CE Ch. 1.4 - Prob. 9CE Ch. 1.4 - Prob. 10CE Ch. 1.4 - Prob. 11CE Ch. 1.4 - Prob. 12CE Ch. 1.4 - Prob. 13CE Ch. 1.4 - Prob. 14CE Ch. 1.4 - Prob. 15CE Ch. 1.4 - Prob. 16CE Ch. 1.4 - Prob. 17CE Ch. 1.4 - Prob. 18CE Ch. 1.4 - Prob. 19CE Ch. 1.4 - Prob. 20CE Ch. 1.4 - Prob. 21CE Ch. 1.4 - Prob. 22CE Ch. 1.4 - Prob. 23CE Ch. 1.4 - Prob. 24CE Ch. 1.4 - Prob. 25CE Ch. 1.4 - Prob. 26CE Ch. 1.4 - Prob. 27CE Ch. 1.4 - Prob. 28CE Ch. 1.4 - Prob. 29CE Ch. 1.4 - Prob. 30CE Ch. 1.4 - Prob. 31CE Ch. 1.4 - Prob. 32CE Ch. 1.4 - Prob. 33CE Ch. 1.4 - Prob. 34CE Ch. 1.4 - Prob. 35CE Ch. 1.4 - Prob. 36CE Ch. 1.4 - Prob. 37CE Ch. 1.4 - Prob. 38CE Ch. 1.4 - Prob. 1WE Ch. 1.4 - Prob. 2WE Ch. 1.4 - Prob. 3WE Ch. 1.4 - Prob. 4WE Ch. 1.4 - Prob. 5WE Ch. 1.4 - Prob. 6WE Ch. 1.4 - Prob. 7WE Ch. 1.4 - Prob. 8WE Ch. 1.4 - Prob. 9WE Ch. 1.4 - Prob. 10WE Ch. 1.4 - Prob. 11WE Ch. 1.4 - Prob. 12WE Ch. 1.4 - Prob. 13WE Ch. 1.4 - Prob. 14WE Ch. 1.4 - Prob. 15WE Ch. 1.4 - Prob. 16WE Ch. 1.4 - Prob. 17WE Ch. 1.4 - Prob. 18WE Ch. 1.4 - Prob. 19WE Ch. 1.4 - Prob. 20WE Ch. 1.4 - Prob. 21WE Ch. 1.4 - Prob. 22WE Ch. 1.4 - Prob. 23WE Ch. 1.4 - Prob. 24WE Ch. 1.4 - Prob. 25WE Ch. 1.4 - Prob. 26WE Ch. 1.4 - Prob. 27WE Ch. 1.4 - Prob. 28WE Ch. 1.4 - Prob. 29WE Ch. 1.4 - Prob. 30WE Ch. 1.4 - Prob. 31WE Ch. 1.4 - Prob. 32WE Ch. 1.4 - Prob. 33WE Ch. 1.4 - Prob. 34WE Ch. 1.4 - Prob. 35WE Ch. 1.4 - Prob. 36WE Ch. 1.5 - Prob. 1CE Ch. 1.5 - Prob. 2CE Ch. 1.5 - Prob. 3CE Ch. 1.5 - Prob. 4CE Ch. 1.5 - Prob. 5CE Ch. 1.5 - Prob. 6CE Ch. 1.5 - Prob. 7CE Ch. 1.5 - Prob. 8CE Ch. 1.5 - Prob. 9CE Ch. 1.5 - Prob. 10CE Ch. 1.5 - Prob. 11CE Ch. 1.5 - Prob. 12CE Ch. 1.5 - Prob. 13CE Ch. 1.5 - Prob. 14CE Ch. 1.5 - Prob. 15CE Ch. 1.5 - Prob. 16CE Ch. 1.5 - Prob. 1WE Ch. 1.5 - Prob. 2WE Ch. 1.5 - Prob. 3WE Ch. 1.5 - Prob. 4WE Ch. 1.5 - Prob. 5WE Ch. 1.5 - Prob. 6WE Ch. 1.5 - Prob. 7WE Ch. 1.5 - Prob. 8WE Ch. 1.5 - Prob. 9WE Ch. 1.5 - Prob. 10WE Ch. 1.5 - Prob. 11WE Ch. 1.5 - Prob. 12WE Ch. 1.5 - Prob. 13WE Ch. 1.5 - Prob. 14WE Ch. 1.5 - Prob. 15WE Ch. 1.5 - Prob. 16WE Ch. 1.5 - Prob. 17WE Ch. 1.5 - Prob. 18WE Ch. 1.5 - Prob. 19WE Ch. 1.5 - Prob. 20WE Ch. 1.5 - Prob. 1E Ch. 1.5 - Prob. 2E Ch. 1.5 - Prob. 3E Ch. 1.5 - Prob. 4E Ch. 1.5 - Prob. 5E Ch. 1.5 - Prob. 6E Ch. 1.5 - Prob. 1ST2 Ch. 1.5 - Prob. 2ST2 Ch. 1.5 - Prob. 3ST2 Ch. 1.5 - Prob. 4ST2 Ch. 1.5 - Prob. 5ST2 Ch. 1.5 - Prob. 6ST2 Ch. 1.5 - Prob. 7ST2 Ch. 1.5 - Prob. 8ST2 Ch. 1.5 - Prob. 9ST2 Ch. 1.5 - Prob. 10ST2 Ch. 1.5 - Prob. 11ST2 Ch. 1.5 - Prob. 12ST2 Ch. 1 - Prob. 1CR Ch. 1 - Prob. 2CR Ch. 1 - Prob. 3CR Ch. 1 - Prob. 4CR Ch. 1 - Prob. 5CR Ch. 1 - Prob. 6CR Ch. 1 - Prob. 7CR Ch. 1 - Prob. 8CR Ch. 1 - Prob. 9CR Ch. 1 - Prob. 10CR Ch. 1 - Prob. 11CR Ch. 1 - Prob. 12CR Ch. 1 - Prob. 13CR Ch. 1 - Prob. 14CR Ch. 1 - Prob. 15CR Ch. 1 - Prob. 16CR Ch. 1 - Prob. 17CR Ch. 1 - Prob. 18CR Ch. 1 - Prob. 19CR Ch. 1 - Prob. 20CR Ch. 1 - Prob. 1CT Ch. 1 - Prob. 2CT Ch. 1 - Prob. 3CT Ch. 1 - Prob. 4CT Ch. 1 - Prob. 5CT Ch. 1 - Prob. 6CT Ch. 1 - Prob. 7CT Ch. 1 - Prob. 8CT Ch. 1 - Prob. 9CT Ch. 1 - Prob. 10CT Ch. 1 - Prob. 11CT Ch. 1 - Prob. 12CT Ch. 1 - Prob. 13CT Ch. 1 - Prob. 14CT Ch. 1 - Prob. 15CT Ch. 1 - Prob. 16CT Ch. 1 - Prob. 17CT Ch. 1 - Prob. 18CT Ch. 1 - Prob. 19CT Ch. 1 - Prob. 20CT Ch. 1 - Prob. 21CT Ch. 1 - Prob. 22CT Ch. 1 - Prob. 23CT Ch. 1 - Prob. 24CT

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The pair of congruent of acute angles .

Concept explainers

Videos

To find: The pair of congruent of acute angles.

Answer to Problem 25CE

Explanation of Solution

To obtain: The pair of congruent of right angles.

Answer to Problem 25CE

Explanation of Solution

To get: The pair of congruent of obtuse angles.

Answer to Problem 25CE

Explanation of Solution

Chapter 1 Solutions

Additional Math Textbook Solutions