Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change
Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change
7th Edition
ISBN: 9780078129865
Author: Martin Silberberg Dr., Patricia Amateis Professor
Publisher: McGraw-Hill Education
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Chapter 14, Problem 14.109P

(a)

Interpretation Introduction

Interpretation:

The equation for the reaction of interhalogen IF has to be written from the given depiction.

Concept Introduction:

Interhalogen compounds:

The compounds which are only composed of two different halogens are known as Interhalogen.

Disproportionation redox reaction:

The formation of products of oxidized and reduced substances from a simultaneous redox reaction of single reactant is known as disproportionation redox reaction.

(a)

Expert Solution
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Explanation of Solution

Given depiction is,

    Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change, Chapter 14, Problem 14.109P , additional homework tip  1

Figure 1

From the given depiction, brown colour = iodine and green coloured are Fluorine atoms.

Therefore, the depiction refers the formation of IF5 and 2I2 molecules from five IF molecules by disproportionation redox reaction.

Hence, the balanced equation for the give reaction is,

    5IFIF5+2I2

(b)

Interpretation Introduction

Interpretation:

Name of the product of given redox reaction of IF has to be given.

Concept Introduction:

Disproportionation redox reaction:

The formation of products of oxidized and reduced substances from a simultaneous redox reaction of single reactant is known as disproportionation redox reaction.

Interhalogen compounds:

The compounds which are only composed of two different halogens are known as Interhalogen.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given depiction is,

    Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change, Chapter 14, Problem 14.109P , additional homework tip  2

Figure 1

From the given depiction, brown colour = iodine and green coloured are Fluorine atoms.

Therefore, the depiction refers the formation of IF5 and 2I2 molecules from five IF molecules by disproportionation redox reaction.

The balanced equation for the give reaction is,

    5IFIF5+2I2

Product of above reaction is Iodine penta-fluoride.

(c)

Interpretation Introduction

Interpretation:

Name of given redox reaction of IF has to be given.

Concept Introduction:

Disproportionation redox reaction:

The formation of products of oxidized and reduced substances from a simultaneous redox reaction of single reactant is known as disproportionation redox reaction.

Interhalogen compounds:

The compounds which are only composed of two different halogens are known as Interhalogen.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given depiction is,

    Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change, Chapter 14, Problem 14.109P , additional homework tip  3

Figure 1

From the given depiction, brown colour = iodine and green coloured are Fluorine atoms.

Therefore, the depiction refers the formation of IF5 and 2I2 molecules from five IF molecules by disproportionation redox reaction.

The balanced equation for the give reaction is,

    5IFIF5+2I2

Therefore, the above reaction shows given reaction is disproportionation reaction.

(d)

Interpretation Introduction

Interpretation:

Mass of product that formed from 2.50×103molIF has to be calculated.

Concept Introduction:

Disproportionation redox reaction:

The formation of products of oxidized and reduced substances from a simultaneous redox reaction of single reactant is known as disproportionation redox reaction.

Interhalogen compounds:

The compounds which are only composed of two different halogens are known as Interhalogen.

Mole:

Mole of substance that present in taken mole of sample is calculated by mass of substance is divided by molar mass of the substance.

    Mole=MassMolarmass

(d)

Expert Solution
Check Mark

Explanation of Solution

Given depiction is,

    Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change, Chapter 14, Problem 14.109P , additional homework tip  4

Figure 1

From the given depiction, brown = iodine and green = Fluorine atoms.

Therefore, the depiction refers the formation of IF5 and 2I2 molecules from five IF molecules by disproportionation redox reaction.

The balanced equation for the give reaction is,

    5IFIF5+2I2

Therefore, the above reaction shows given reaction is disproportionation reaction.

Mass of IF5 formed from the reaction of 2.50×103molIF is,

Molar mass of IF5 is 221.9g

    MassIF5=(7IFmolecules)(2.50×10-3molIF1molIF)(1molIF55molIF)(221.9g1molIF) =0.777gIF5

Mass of I2 formed from the reaction of 2.50×103molIF is,

Molar mass of I2 is 253.8 g

MassI2=(7IFmolecules)(2.50×10-3molIF1molIF)(2molI25molIF)(253.8gI21molIF) =1.78gI2

Hence, 0.777gIF5 and 1.78gI2 are formed from 2.50×103molIF.

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Chapter 14 Solutions

Connect 2-Year Access Card for Chemistry: The Molecular Nature of Matter and Change

Ch. 14 - Prob. 14.11PCh. 14 - Prob. 14.12PCh. 14 - Prob. 14.13PCh. 14 - Prob. 14.14PCh. 14 - Prob. 14.15PCh. 14 - Prob. 14.16PCh. 14 - Prob. 14.17PCh. 14 - Prob. 14.18PCh. 14 - Prob. 14.19PCh. 14 - Prob. 14.20PCh. 14 - Prob. 14.21PCh. 14 - Prob. 14.22PCh. 14 - Prob. 14.23PCh. 14 - Prob. 14.24PCh. 14 - Prob. 14.25PCh. 14 - Prob. 14.26PCh. 14 - Prob. 14.27PCh. 14 - Prob. 14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Prob. 14.32PCh. 14 - Prob. 14.33PCh. 14 - Prob. 14.34PCh. 14 - Prob. 14.35PCh. 14 - Prob. 14.36PCh. 14 - Prob. 14.37PCh. 14 - Prob. 14.38PCh. 14 - Prob. 14.39PCh. 14 - Prob. 14.40PCh. 14 - Prob. 14.41PCh. 14 - Prob. 14.42PCh. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.45PCh. 14 - Prob. 14.46PCh. 14 - Give explanations for the large drops in melting...Ch. 14 - Prob. 14.48PCh. 14 - Prob. 14.49PCh. 14 - Prob. 14.50PCh. 14 - Prob. 14.51PCh. 14 - Prob. 14.52PCh. 14 - Prob. 14.53PCh. 14 - Prob. 14.54PCh. 14 - Prob. 14.55PCh. 14 - Prob. 14.56PCh. 14 - Prob. 14.57PCh. 14 - Prob. 14.58PCh. 14 - Prob. 14.59PCh. 14 - Prob. 14.60PCh. 14 - Prob. 14.61PCh. 14 - Prob. 14.62PCh. 14 - Prob. 14.63PCh. 14 - Prob. 14.64PCh. 14 - Prob. 14.65PCh. 14 - Prob. 14.66PCh. 14 - Prob. 14.67PCh. 14 - Prob. 14.68PCh. 14 - Prob. 14.69PCh. 14 - Prob. 14.70PCh. 14 - Prob. 14.71PCh. 14 - Prob. 14.72PCh. 14 - Prob. 14.73PCh. 14 - Prob. 14.74PCh. 14 - Prob. 14.75PCh. 14 - Prob. 14.76PCh. 14 - Prob. 14.77PCh. 14 - Prob. 14.78PCh. 14 - Prob. 14.79PCh. 14 - Prob. 14.80PCh. 14 - Prob. 14.81PCh. 14 - Prob. 14.82PCh. 14 - Prob. 14.83PCh. 14 - Prob. 14.84PCh. 14 - Prob. 14.85PCh. 14 - Prob. 14.86PCh. 14 - Prob. 14.87PCh. 14 - Prob. 14.88PCh. 14 - Prob. 14.89PCh. 14 - Prob. 14.90PCh. 14 - Prob. 14.91PCh. 14 - Prob. 14.92PCh. 14 - Prob. 14.93PCh. 14 - Prob. 14.94PCh. 14 - Prob. 14.95PCh. 14 - Prob. 14.96PCh. 14 - Prob. 14.97PCh. 14 - Prob. 14.98PCh. 14 - Prob. 14.99PCh. 14 - Prob. 14.100PCh. 14 - Prob. 14.101PCh. 14 - Prob. 14.102PCh. 14 - Prob. 14.103PCh. 14 - Prob. 14.104PCh. 14 - Xenon tetrafluoride reacts with antimony...Ch. 14 - Prob. 14.106PCh. 14 - Prob. 14.107PCh. 14 - Prob. 14.108PCh. 14 - Prob. 14.109PCh. 14 - Prob. 14.110PCh. 14 - Prob. 14.111PCh. 14 - Prob. 14.112PCh. 14 - Prob. 14.113PCh. 14 - Prob. 14.114PCh. 14 - Prob. 14.115PCh. 14 - Prob. 14.116PCh. 14 - Prob. 14.117PCh. 14 - Prob. 14.118PCh. 14 - Prob. 14.119PCh. 14 - Prob. 14.120PCh. 14 - Prob. 14.121PCh. 14 - Prob. 14.122PCh. 14 - Prob. 14.123PCh. 14 - Prob. 14.124PCh. 14 - Prob. 14.125PCh. 14 - Prob. 14.126PCh. 14 - Prob. 14.127PCh. 14 - Prob. 14.128PCh. 14 - Prob. 14.129PCh. 14 - Prob. 14.130PCh. 14 - Prob. 14.131PCh. 14 - Prob. 14.132PCh. 14 - Prob. 14.133PCh. 14 - Prob. 14.134PCh. 14 - Hydrogen peroxide can act as either an oxidizing...
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