Chapter 13.4, Problem 42E

Changing the order of integration Rewrite the following integrals using the indicated order of integration and then evaluate the resulting integral.

42.     ${\displaystyle {\int }_0^4{\displaystyle {\int }_0^{\sqrt{16-x^2}}{\displaystyle {\int }_0^{\sqrt{16-x^2-z^2}}dydzdx}}}$ in the order dz dy dx