Chapter 13.3, Problem 61AYU

On The Price Is Right, there is a game in which a bag is filled with 3 strike chips and 5 numbers. Let’s say that the numbers in the bag are 0, 1, 3, 6, and 9. What is the probability of selecting a strike chip or the number 1?

To determine

To find: The probability of selecting a strike chip or the number 1?

Answer to Problem 61AYU

$P\left(strike or one\right)=\frac{1}{2}$

Explanation of Solution

Given:

On The Price Is Right, there is a game in which a bag is filled with 3 strike chips and 5 numbers. Let’s say that the numbers in the bag are 0, 1, 3, 6, and 9.

Formula Used:

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

Calculation:

There is a game in which a bag is filled with 3 strike chips and 5 numbers. Let’s say that the numbers in the bag are 0, 1, 3, 6, and 9.

$P\left(strike or one\right)=P\left(strike\right)+P\left(one\right)$

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}$

$P\left(strike or one\right)=\frac{3}{8}+\frac{1}{8}=\frac{4}{8}=\frac{1}{2}$

$P\left(strike or one\right)=\frac{1}{2}$